5/6 + (-4/9)-(-2) ??????

Answers

Answer 1

Answer:

Answer:

2 7/18

Step-by-step explanation:

Follow the pemdas order of operations, apply the + (-a) = a Rule. Add and subract from left to right. 5/6 - 4/9 = 7/18 with 2 and it gives you your answer but keep in mind the two multiples are 6,9. Hope this helps!

Answer 2

Answer: it would be 43/18. you should be able to simplify it if not let me know :)

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according to the line plot how many more Runners ran 1/3 of a mile for their warm-up than ran 1/4 of a mile

Answers

Answer:

Step-by-step explanation:

count how many more

Connor works in a department store selling clothing. He makes a guaranteed salary of $300 per week, but is paid a commision on top of his base salary equal to 5% of his total sales for the week. How much would Connor make in a week in which he made $2175 in sales? How much would Connor make in a week if he made xx dollars in sales?

Answers

Answer:

If Connor makes x dollars in sales, he will make 0.05x + 300 that week.

He makes $408.75 in a week if he makes $2175 in sales.

Step-by-step explanation:

y = 0.05x + 300

y = 0.05(2175) + 300

y = 408.75

A washer and a dryer cost $857 combined. The washer costs $93 less than the dryer. What is the cost of the dryer?

Answers

The cost of the dryer is $475 and the cost of the washer is $382.

What is an equation?

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Given that, a washer and a dryer cost $857 combined.

Let the cost of dryer be x.

The washer costs $93 less than the dryer.

Then, the cost of washer will be x-93

So, x+x-93=857

2x=857+93

2x=950

x=$475

x-93=475-93

= $382

Hence, the cost of the dryer is $475.

To learn more about an equation visit:

brainly.com/question/14686792.

#SPJ2

Answer:

Dryer cost $475; Washer cost $382

Step-by-step explanation:

For this problem, we will simply set up a system of equations to find the value of each the washer (variable x) and the dryer (variable y).

We are given the washer and dryer cost $857 together.

x + y = 857

We are also given that the washer cost $93 less than the dryer.

x = y - 93

So to find the cost of the dryer, we simply need to find the value of y.

x + y = 857

x = y - 93

( y - 93 ) + y = 857

2y - 93 = 857

2y = 950

y = 475

So now we have the value of the dry to be $475. We can check this by simply plugging in the value and see if it makes sense.

x + y = 857

x + 475 = 857

x = 382

And check this value:

x = y - 93

382 ?= 475 - 93

382 == 382

Therefore, we have found the values of both the washer and the dryer.

Cheers.

Let the number of chocolate chips in a certain type of cookie have a Poisson distribution. We want the probability that a cookie of this type contains at least two chocolate chips to be greater than 0.99. Find the smallest value of the mean that the distribution can take.

Answers

Answer:

$\lambda \geq 6.63835$

Step-by-step explanation:

The Poisson Distribution is "a discrete probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known constant mean rate and independently of the time since the last event".

Let X the random variable that represent the number of chocolate chips in a certain type of cookie. We know that $X \sim Poisson(\lambda)$

The probability mass function for the random variable is given by:

$f(x)=(e^(-\lambda) \lambda^x)/(x!) , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda$

$E(X)=\mu =\lambda$

On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:

$P(X\geq 2)=1-P(X<2)=1-P(X\leq 1)=1-[P(X=0)+P(X=1)]$

Using the pmf we can find the individual probabilities like this:

$P(X=0)=(e^(-\lambda) \lambda^0)/(0!)=e^(-\lambda)$

$P(X=1)=(e^(-\lambda) \lambda^1)/(1!)=\lambda e^(-\lambda)$

And replacing we have this:

$P(X\geq 2)=1-[P(X=0)+P(X=1)]=1-[e^(-\lambda) +\lambda e^(-\lambda)[]$

$P(X\geq 2)=1-e^(-\lambda)(1+\lambda)$

And we want this probability that at least of 99%, so we can set upt the following inequality:

$P(X\geq 2)=1-e^(-\lambda)(1+\lambda)\geq 0.99$

And now we can solve for $\lambda$

$0.01 \geq e^(-\lambda)(1+\lambda)$

Applying natural log on both sides we have:

$ln(0.01) \geq ln(e^(-\lambda)+ln(1+\lambda)$

$ln(0.01) \geq -\lambda+ln(1+\lambda)$

$\lambda-ln(1+\lambda)+ln(0.01) \geq 0$

Thats a no linear equation but if we use a numerical method like the Newthon raphson Method or the Jacobi method we find a good point of estimate for the solution.

Using the Newthon Raphson method, we apply this formula:

$x_(n+1)=x_n -(f(x_n))/(f'(x_n))$

Where :

$f(x_n)=\lambda -ln(1+\lambda)+ln(0.01)$

$f'(x_n)=1-(1)/(1+\lambda)$

Iterating as shown on the figure attached we find a final solution given by:

$\lambda \geq 6.63835$

Final answer:

The problem pertains to Poisson Distribution in probability theory, focusing on finding the smallest mean (λ) such that the probability of having at least two chocolate chips in a cookie is more than 0.99. This involves solving an inequality using the formula for Poisson Distribution.

Explanation:

This problem pertains to the Poisson Distribution, often used in probability theory. In particular, we're looking at the number of events (in this case, the number of chocolate chips) that occur within a fixed interval. Here, the interval under study is a single cookie. The question requires us to find the smallest value of λ (the mean value of the distribution) such that the probability of getting at least two chocolate chips in a cookie is more than 0.99.

Using the formula for Poisson Distribution, the probability of finding k copies of an event is given by:

P(X=k) = λ^k * exp(-λ) / k!

The condition here is that the probability of finding at least 2 copies is more than 0.99. Therefore, you formally need to solve the inequality:

P(X>=2) = 1 - P(X=0) - P(X=1) > 0.99

Substituting the values of P(X=0) and P(X=1) from our standard formula, you will need to calculate and find the smallest value of λ that satisfies this inequality.