Answer:I think it’s c
Step-by-step explanation:I’m think me smart
Answer:
The number of monthly memberships before the incentive was 100
Step-by-step explanation:
Remember that
The total memberships after the incentive is equal to the total memberships before the incentive
step 1
Find out the annual memberships after the incentive
Let
x -----> monthly memberships after the incentive
y -----> annual memberships after the incentive
we know that
-----> equation A
substitute the value of x in equation A
step 2
Find out the total memberships after the incentive
step 3
Find out the monthly members before the incentive
Let
x -----> monthly memberships before the incentive
y -----> annual memberships before the incentive
we know that
-----> equation A
-----> equation B
substitute equation A in equation B and solve for x
therefore
The number of monthly memberships before the incentive was 100
Initially, there were 100 monthly members at the community pool, before the incentives were offered.
We start with the information that the ratio of monthly to annual memberships was initially 10 to 3, and then became 5 to 8. After the incentive, we're told there are now 50 monthly members.
To solve this problem, we set up a proportion. Since each part of the new ratio equals 10 members (50 monthly members/5 parts = 10 members per part), we can infer that before the incentive there were 10*10=100 monthly members.
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Answer:
I'm not completely sure but i'm going to guess on D the domain is 1 < f < 7, the range is 24 < c(f) < 168
Step-by-step explanation:
because 1 cup is < to a cup of Flour (f), and the expression says 7 cups in total so i f is less than or equal to the total number of cups 7. then the range says c(f)=24(f), meaning you get 24 cookies for the input amount "f" of cups of flour. So the range would be 24 is grater of equal to the c(f)which in total (7 x 24) is equal to 168
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x =
Answer:
x-4+3x+100=180....by angle sum property
4x=84
x=21
A: Gradient of f
B: Gradient of f at point P:
Just put the coordinates of p in above formula:
C: The directional derivative of f and P in direction of v:
The directional derivative is found by dot product of :
D: The maximum rate of change of f at P is calculated by evaluating the magnitude of gradient vector at P:
E: The (unit) direction vector in which the maximum rate of change occurs at P is:
That vector v is the needed unit vector in this case.
we divided by to make that vector as of unit length.
Learn more about vectors here:
Answer:
a) The gradient of a function is the vector of partial derivatives. Then
b) It's enough evaluate P in the gradient.
c) The directional derivative of f at P in direction of V is the dot produtc of and v.
d) The maximum rate of change of f at P is the magnitude of the gradient vector at P.
e) The maximum rate of change occurs in the direction of the gradient. Then
is the direction vector in which the maximum rate of change occurs at P.
Answer:
122 = 2(2w +w)
Step-by-step explanation:
If we let w represent the width of the rectangle, then 2w is the length of it. The perimeter is twice the sum of length and width.
P = 2(L+W)
122 = 2(2w +w) . . . . an equation for the description