Answer:
= bruv
Step-by-step explanation:
you spelt power wrong too
Answer:
The answer is 6x
Step-by-step explanation:
Step-by-step explanation:
I think common factors are
18 = 1 2 3 6 9 18
30 = 1 2 3 10 15 30
So highest common factor is 3
18x + 30x2
3x (6 + 10x)
Answer: B
Step-by-step explanation:
I got it right
Answer:
The correct answer is B. d = 525h
Gary was on the Ferris wheel for a total of 36 minutes, calculated by subtracting the time he got on (2:40 P.M.) from the time he got off (3:16 P.M.).
To find out how long Gary was on the Ferris wheel, we need to calculate the difference in time from when he got on the ride to when he got off. He got on at 2:40 P.M. and got off at 3:16 P.M. To calculate the time difference, we first convert the times to a 24-hour format. So, 2:40 P.M. is 14:40 and 3:16 P.M. is 15:16.
Next, we subtract the starting time from the ending time. The calculation is as follows:
15:16 - 14:40 = 0:36
So, Gary was on the Ferris wheel for 36 minutes.
#SPJ12
Answer:
2:40 to 3:16
2:40 to 3 is 20 min
3 to 3:16 is 16 min
20+16=36
So, Gary was on the ride for 36 minutes!
Answer:
The maximum volume of such box is 32m^3
V = x×y×z = 32 m^3
Step-by-step explanation:
Given;
Total surface area S = 48m^2
Volume of a rectangular box V = length×width×height
V = xyz ......1
Total surface area of a rectangular box without a lid is
S = xy + 2xz + 2yz = 48 .....2
To be able to maximize the volume, we need to reduce the number of variables.
Let assume the rectangular box has a square base,that means; length = width
x = y
Substituting y with x in equation 1 and 2;
V = x^2(z) ....3
x^2 + 4xz = 48 .....4
Making z the subject of formula in equation 4
4xz = 48 - x^2
z = (48 - x^2)/4x .......5
To be able to maximize V, we need to reduce the number of variables to 1, by substituting equation 5 into equation 3
V = x^2 × (48 - x^2)/4x
V = (48x - x^3)/4
differentiating V with respect to x;
V' = (48 - 3x^2)/4
At the maximum point V' = 0
V' = (48 - 3x^2)/4 = 0
Solving for x;
3x^2 = 48
x = √(48/3)
x = √(16)
x = 4
Since x = y
y = 4
From equation 5;
z = (48 - x^2)/4x
z = (48 - 4^2)/4(4)
z = 32/16
z = 2
The maximum volume can be derived by substituting x,y,z into equation 1;
V = xyz = 4×4×2 = 32 m^3