Two towns are located at points A(2,-2) and B (8,5). A new school is to be built on a straight road with equation -x+7y=-4. Find the location of the school so that it is equaidistant from the two towns

Answers

Answer 1
Answer:

Final answer:

The problem asks for a location that is equidistant from towns A and B and lies on the given road. Calculating the midpoint of A and B, we get (5, 1.5). However, this point does not lie on the road denoted by -x + 7y = -4. So, we cannot determine the exact location of the school with the given conditions.

Explanation:

In this problem, the location of the school should be the midpoint of the line between towns A and B as it is equidistant from both towns. First, let's calculate the midpoint (M) coordinates. The formulas for finding the x and y coordinates of the midpoint are (x1 + x2) / 2 and (y1 + y2) / 2 respectively. Using these formulas, we get the coordinates of M as (2+8)/2, (-2+5)/2 = (5, 1.5). However, we should ensure that this point lies on the given road, which is denoted by the equation -x + 7y = -4. Substituting the coordinates of M in the equation, we get -5 + 7*1.5 = -5 + 10.5 = 5.5 which is not equal to -4. So, (5, 1.5) is not a valid location for the school. Unfortunately, with the given conditions, we cannot determine the exact location of the school. Additional information or revision of the conditions might be necessary to solve this problem.

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Answers

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The table below represents a linear function f(x) and the equation represents a function g(x).. . Table:. x f(x). 0 30. 1 32. 2 34. . Equation:. g(x). g(x)=8x-25. . Part 1. Write a sentence to compare the slope of the two functions and show the steps you used to determine the slope of f(x) and g(x).. . Part 2. Which function has a great y-intercept?. . Please help!

Answers

x   f(x)
0   30
1   32
2   32

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32 = m(1) + 30
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Simplify. (-6x^2 + 2y - 1) + (2x^2-5y + 3) A) -4x^2 + 3y -2 B) -4x^2 - 3y - 2 C) -4x^2 + 3y +2 D) -4x^2 -3y +2

Answers

Combine like terms

-6x^2+2y + -1 +2x^2 + -5y +3

( -6x^2+2x^2)+(2y-5y)+(-1+3)

= -4x^2+3y+2

Answer : C


I hope that's help !


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Answers

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Select all that apply.Which of the following could you use to find 40% of 32?


0.4 · 32
2/5 · 32
40/100 · 32
32/40

Answers

If you would like to solve 40% of 32, you can do this using the following steps:

40% of 32 = 40% * 32 = 40/100 * 32 = 0.40 * 32 = 2/5 * 32 = 12.8

The correct result would be 0.4 * 32; 2/5 * 32; 40/100 * 32.

Answer:

(40)/(100)*32

(2)/(5)*32

0.4*32

Step-by-step explanation:

we know that

40\%=(40)/(100)=(2)/(5)=0.4

therefore

40\% of 32

is equal to

(40)/(100)*32=12.8

(2)/(5)*32=12.8

0.4*32=12.8