To celebrate the first day of school, Reagan brought in a tray of caramel brownies and walnut brownies. The tray had a total of 20 brownies, of which 10% were caramel. How many caramel brownies did Reagan bring?

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Answer 1

Answer:

Answer:

2 were caramel

Step-by-step explanation:

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Find the degree of the monomial. 6x8y5

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Answer:

Step-by-step explanation:

We have been given the monomial $6x^8y^5$

Here the variables are x and y.

In order to find the degree this monomial, we add the exponents of the variables x and y.

Exponent of x = 8

Exponent of y = 5

Therefore, the degree of the monomial is

Degree = exponent of x + exponent of y

Degree = 8 + 5

Degree = 13

. 6x⁸y⁵ ← x is a factor 8 times, and y is a factor 5 times, so the degree is 8+5=13
13

The volume of a pyramid with a square base is given by the expression 1 / 3 s2 ( 2 is the exponent ) h, where s is the length of a side of the base and h is the heigth. Find the volume of a pyramid with a square base of side length 24 feet and a heigth of 30 feet. Please I need help on this..

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$V=(1)/(3)\cdot24^2\cdot30\nV=10\cdot576\nV=5760 \text { ft}^2$

A plant can either have a smooth seed (p) or a rough seed (q). Rough seeds are recessive and smooth seeds are dominant. In a population of 100 plants, 32 of them have rough seeds.p^2 + 2pq + q^2 = 1

a) What is q^2?

b) What is q?

c) What is p?

d) If there are 19 plants with rough seeds in a population of 100, what is the allele frequency for smooth seeds?

Answers

To calculate this, the Hardy-Weinberg principle can be used:

p² + 2pq + q² = 1 and p + q = 1

where p and q are the frequencies of the alleles (p - dominant, q - recessive), and p², q² and 2pq are the frequencies of the genotypes.

a) Since 32 plants have rough seed (recessive genotype: q²) out of 100 plants in total, then

q² = 32/100 = 0.32

b) q = √q² = √0.32 = 0.56

c) Since p + q = 1, then

p = 1 - q = 1 - 0.56 = 0.44

d) 19 plants with rough seeds (recessive genotype: q²) in a population of 100 means that q² = 19/100 = 0.19

We need to calculate p (the allele frequency for smooth seeds).
We can find q because we know q²:

q = √q² = √0.19 = 0.44

Since p + q = 1, then

p = 1 - q = 1 - 0.4 = 0.56

I followed what the other user said and I think it's correct!

a) 0.32

b) 0.56

c) 0.44

d) 0.56

For what values of x is the expression below defined?√2x^2 divide by √5x

a/x=0
b.x<0
c.x>0
d.x<1

Answers

$√(2x^2):√(5x)\n\n2x^2\geq0\ \wedge\ x > 0\n\nx^2\geq0\ \wedge\ x > 0\n\nx\in\mathbb{R}\ \wedge\ x > 0\Rightarrow x > 0\ (x\in\mathbb{R^+})\n\nAnswer:c.\ x > 0$