8. Next, the $50, $25, and $10 gift cards aregiven to 3 of the remaining 6 volunteers. In
how many ways can these cards be given
away? Is this a combination or a
permutation? Explain.
Answer choices:
a. 120; combination because the order
does not matter
b. 20; combination because the order does
not matter
c. 120; permutation because the prizes are
different
d. 20; permutation because the prizes are
different

There are 20 ways to give away the gift cards. The correct answer is option B. 20; combination because the order does not matter.

How did we get the value?

To determine the number of ways the $50, $25, and $10 gift cards can be given away to 3 of the remaining 6 volunteers, we need to find the number of combinations.

A combination is used when the order of the items does not matter. In this case, the order in which the gift cards are given to the volunteers does not affect the outcome. For example, if Volunteer A gets the $50 card, Volunteer B gets the $25 card, and Volunteer C gets the $10 card, it is the same result as if Volunteer B gets the $50 card, Volunteer A gets the $25 card, and Volunteer C gets the $10 card.

The formula for calculating combinations is:

C(n, r) = n! / (r! × (n-r)!)

Where:

- n is the total number of items (6 volunteers in this case).

- r is the number of items to be chosen (3 gift cards in this case).

- n! represents the factorial of n, which is the product of all positive integers less than or equal to n.

Plugging the values into the formula, we get:

C(6, 3) = 6! / (3! × (6-3)!)

= 720 / (6 × 6)

= 720 / 36

= 20

So, there are 20 ways to give away the gift cards. The correct answer is (b) 20; combination because the order does not matter.

learn more about combination: brainly.com/question/4658834

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Answer:

c i think

Step-by-step explanation: