MATHEMATICS COLLEGE

The triangles are congruent by the SSS congruence theorem. Triangles B C D and W X Y are shown. Triangle B C D is shifted up and to the right and then rotates about point D to form triangle W X Y. Which transformation(s) can map TriangleBCD onto TriangleWXY?

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

just trust me I didn't finish the test but I'm 99% sure this is correct

Answer 2

Answer:

Answer:

C. Translation, then rotation

Step-by-step explanation:

May I have brainliest please? :)

Related Questions

Find the equation of a line passing through the point (-4,1) and perpendicular to theline 3y = 12x - 9.
The tread life of tires mounted on light-duty trucks follows the normal probability distribution with a mean of 60,000 miles and a standard deviation of 4,000 miles. Suppose you bought a set of four tires, what is the likelihood the mean tire life of these four tires is between 57,000 and 63,000 miles
angle U and angle W are vertical angles. If measurement angle u = 6x+11 and measurement angle W = 10x-9, find measurement angle U.
Find an equation of the line described. Write the equation in slope-intercept form when possible. Slope 1, through (-4,3)
The graph below shows the numbers of cups of apple juice that are mixed with different numbers of cups of lemon-lime soda to make servings of apple soda: A graph is shown. The values on the x axis are 0, 1, 2, 3, 4, 5. The values on the y axis are 0, 6, 12, 18, 24, 30. Points are shown on ordered pairs 0, 0 and 1, 6 and 2, 12 and 3, 18 and 4, 24. These points are connected by a line. The label on the x axis is Lemon -Lime Soda in cups. The title on the y axis is Apple Juice in cups. What is the ratio of the number of cups of apple juice to the number of cups of lemon-lime soda? 1:24 24:1 1:6 6:1

Multiply the fraction by the whole number. Find the answer as a proper fraction or mixed number in simplest terms. *3 x 4/5: options
*2 3/5
*1 2/5
*2 1/5
*2 2/5

Answers

Answer:

2 $(2)/(5)$

Step-by-step explanation:

Whole numbers can be seen as the number over 1. So, 3 can also be written as $(3)/(1)$ . To do $(3)/(1)$ x $(4)/(5)$ you just multiply across (3x4 and 1x5). Doing so gets you $(12)/(5)$ . Since 12 is bigger than 5, you need to find out how many times 5 fits into 12, which is 2 times. This means 2 is the whole number, however you're still left with 2 from the fraction $(12)/(5)$ , since 2x5 is just 10. You write the remaining 2 as $(2)/(5)$ , because that's what the original denominator was. The final answer is 2 $(2)/(5)$ .

Suppose a professor splits their class into two groups: students whose last names begin with A-K and students whose last names begin with L-Z. If p1 and p2 represent the proportion of students who have an iPhone by last name, would you be surprised if p1 did not exactly equal p2? If we conclude that the first initial of a student's last name is NOT related to whether the person owns an iPhone, what assumption are we making about the relationship between these two variables?

Answers

a) Even if the distribution of iPhones by last name is completely uniform in the population generally, there is no reason to believe that the proportions in the sample represented by the class will be identical.
I would not be surprised to see p1 ≠ p2.

b) Saying the variables are not related is the same as saying the variables are independent.

Pleeease open the image and hellllp me

Answers

1. Rewrite the expression in terms of logarithms:

$y=x^x=e^(\ln x^x)=e^(x\ln x)$

Then differentiate with the chain rule (I'll use prime notation to save space; that is, the derivative of y is denoted y' )

$y'=e^(x\ln x)(x\ln x)'=x^x(x\ln x)'$

$y'=x^x(x'\ln x+x(\ln x)')$

$y'=x^x\left(\ln x+\frac xx\right)$

$y'=x^x(\ln x+1)$

2. Chain rule:

$y=\ln(\csc(3x))$

$y'=\frac1{\csc(3x)}(\csc(3x))'$

$y'=\sin(3x)\left(-\cot^2(3x)(3x)'\right)$

$y'=-3\sin(3x)\cot^2(3x)$

Since $\cot x=(\cos x)/(\sin x)$ , we can cancel one factor of sine:

$y'=-3(\cos^2(3x))/(\sin(3x))=-3\cos(3x)\cot(3x)$

3. Chain rule:

$y=e^{e^(\sin x)}$

$y'=e^{e^(\sin x)}\left(e^(\sin x)\right)'$

$y'=e^{e^(\sin x)}e^(\sin x)(\sin x)'$

$y'=e^{e^(\sin x)+\sin x}\cos x$

4. If you're like me and don't remember the rule for differentiating logarithms of bases not equal to e, you can use the change-of-base formula first:

$\log_2x=(\ln x)/(\ln2)$

Then

$(\log_2x)'=\left((\ln x)/(\ln 2)\right)'=\frac1{\ln 2}$

So we have

$y=\cos^2(\log_2x)$

$y'=2\cos(\log_2x)\left(\cos(\log_2x)\right)'$

$y'=2\cos(\log_2x)(-\sin(\log_2x))(\log_2x)'$

$y'=-\frac2{\ln2}\cos(\log_2x)\sin(\log_2x)$

and we can use the double angle identity and logarithm properties to condense this result:

$y'=-\frac1{\ln2}\sin(2\log_2x)=-\frac1{\ln2}\sin(\log_2x^2)$

5. Differentiate both sides:

$\left(x^2-y^2+\sin x\,e^y+\ln y\,x\right)'=0'$

$2x-2yy'+\cos x\,e^y+\sin x\,e^yy'+\frac{xy'}y+\ln y=0$

$-\left(2y-\sin x\,e^y-\frac xy\right)y'=-\left(2x+\cos x\,e^y+\ln y\right)$

$y'=(2x+\cos x\,e^y\ln y)/(2y-\sin x\,e^y-\frac xy)$

$y'=(2xy+\cos x\,ye^y\ln y)/(2y^2-\sin x\,ye^y-x)$

6. Same as with (5):

$\left(\sin(x^2+\tan y)+e^(x^3\sec y)+2x-y+2\right)'=0'$

$\cos(x^2+\tan y)(x^2+\tan y)'+e^(x^3\sec y)(x^3\sec y)'+2-y'=0$

$\cos(x^2+\tan y)(2x+\sec^2y y')+e^(x^3\sec y)(3x^2\sec y+x^3\sec y\tan y\,y')+2-y'=0$

$\left(\cos(x^2+\tan y)\sec^2y+x^3\sec y\tan y\,e^(x^3\sec y)-1\right)y'=-\left(2x\cos(x^2+\tan y)+3x^2\sec y\,e^(x^3\sec y)+2\right)$

$y'=-(2x\cos(x^2+\tan y)+3x^2\sec y\,e^(x^3\sec y)+2)/(\cos(x^2+\tan y)\sec^2y+x^3\sec y\tan y\,e^(x^3\sec y)-1)$

7. Looks like

$y=x^2-e^(2x)$

Compute the second derivative:

$y'=2x-2e^(2x)$

$y''=2-4e^(2x)$

Set this equal to 0 and solve for x :

$2-4e^(2x)=0$

$4e^(2x)=2$

$e^(2x)=\frac12$

$2x=\ln\frac12=-\ln2$

$x=-\frac{\ln2}2$

Which lst of ordered pairs represents solutions to x+y= 2? (4.6), (0, 2), (4, 2) (4,6), (0, 2). (4, 2) (4,-6), (0, 2), (4, 2)

Answers

answer: x+y=2

0+2=²

( 0 , 2 )

Answer:

(0,2)

Step-by-step explanation:

0 + 2 = 2

Where x = 0, y = 2

Help plsAccording to a food label on a box of cookies, each box has 16 servings and each serving contains 4 cookies. The weight of the box of cookies is 1/2 kilograms. What is the weight of each cookie?

Answers

Answer:

7.8125 grams

Step-by-step explanation:

As per the food label on the box of cookies, there are 16 servings in each box and each serving contains 4 cookies.

Therefore, each box of cookies contains (16 × 4) = 64 cookies.

If a box of cookies weighs kg i.e. 500 gram, then the weight of each cookies will be grams. (Answer)

Find the points on the given curve where the tangent line is horizontal or vertical. (Assume 0 ≤ θ < π. Enter your answers as a comma-separated list of ordered pairs.)r = 6 cos(θ)