Answer:
85
Step-by-step explanation:
Answer:
$1350
Step-by-step explanation:
5% of 1000 is 50
50x7 is 350
1000+350=1350
A.
the Abbott and Baker Families
B.
the Abbott and Carson Families
C.
the Carson and Baker Families
D.
all three families would have to pay the same price
Answer:
c
Step-by-step explanation:
both of the familys have higher cost and have to stay longer
After solving systems of equations for each pair of families, the Abbott and Carson Families are the ones that fit the conditions allowing the largest possible nightly hotel cost.
Let's examine the vacation expenses for each family to determine which two families could have paid the same price per night at their hotel and per airline ticket for the largest possible nightly hotel cost. We must establish a system of equations to represent the total vacation expenses in terms of hotel cost per night (H) and airline ticket cost (A).
For the Abbott Family:
4H + 3A = $840
For the Baker Family:
9H + 2A = $1,130
For the Carson Family:
6H + 5A = $2,080
To determine which two families could have the same hotel and ticket costs, we should look for the two equations that can be true simultaneously for the highest values of H. For ease of calculation, we can eliminate one family at a time and solve the remaining pair of equations for H and A.
By trying different combinations, we can find that the Abbott and Carson Families fit the conditions allowing the largest possible nightly hotel cost. Here's the reasoning:
Hence, option B, the Abbott and Carson Families, is the right choice for the largest possible nightly hotel cost.
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