MATHEMATICS COLLEGE

What is mZSVT?
Enter your answer in the box.
What is mZSVT? Enter your answer in the box. - 1

Answers

Answer 1
Answer:

Answer:

The measure of ∠SVT is 79°

Step-by-step explanation:

In the given figure

∵ US ∩ RT at V

∴ ∠SVT and ∠UVR are vertically opposite angles

∵ The vertically opposite angles are equal in measures

∴ m∠SVT = m∠UVR

∵ m∠SVT = (5y + 9)°

∵ m∠UVR = (8y - 33)°

→ Equate them

∴ 8y - 33 = 5y + 9

→ Add 33 to both sides

∴ 8y - 33 + 33 = 5y + 9 + 33

∴ 8y = 5y + 42

→ Subtract 5y from both sides

∴ 8y - 5y = 5y - 5y + 42

∴ 3y = 42

→ Divide both sides by 3

∵ (3y)/(3) = (42)/(3)

∴ y = 14

→ Substitute the value of y in the measure of ∠SVT

∵ m∠SVT = 5(14) + 9

∴ m∠SVT = 70 + 9

∴ m∠SVT = 79°

∴ The measure of ∠SVT is 79°

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Please helppp it’s urgent , I’ll give a crown !!

Answers

Answer:

Slide to the left then rotate 90° to the right then slide down then rotate 180° to the left/ right.

A Christmas tree is supported by a wire that is 9 meters longer than the height of the tree. The wire is anchored at a point whose distance from the base of the tree is 41 meters shorter than the height of the tree. What is the height of the tree

Answers

Answer:

The height of the tree is 80 meters.

Step-by-step explanation:

Let the height of the Christmas tree be x meters.

Then the length of the wire will be, (x + 9) meters.

And the wire will (x - 41) meters away from the base of the tree.

Consider the diagram below.

Use Pythagoras theorem to solve for x as follows:

AB^(2)=AC^(2)+CB^(2)

(x+9)^(2)=x^(2)+(x-41)^(2)\n\nx^(2)+18x+81=x^(2)+x^(2)-82x+1681\n\nx^(2)-100x+1600=0\n\nx^(2) -80x-20x+1600=0\n\nx(x-80)-20(x-80)=0\n\n(x-80)(x-20)=0

The value of x is either 80 or 20.

If x = 20, then the base CB will be -21. This is not possible as length is always positive.

Thus, the value of x is 80.

Hence, the height of the tree is 80 meters.

Complete the sentence. 13 is 65% of _____

Answers

20

Step-by-step explanation:

is what i got i think its wrong tho
The answer : 20%
Hope it help u

A sample mean, sample size, and population standard deviation are given. Use the one-mean z-test to perform the required hypothesis test at the given significance level. Use the critical -value approach.= 20.5, n = 11 , σ = 7, H0: μ = 18.7; Ha: μ ≠ 18.7, α = 0.01

Answers

Answer:

 Z = 0.8528 < 2.576

The calculated value Z = 0.8528 < 2.576 at 0.01 level of significance

Null hypothesis is Accepted at 0.01 level of significance.

There is no significance difference between the means

Step-by-step explanation:

Given data

size of the sample 'n' = 11

mean of the sample x⁻ =20.5

Mean of the Population μ = 18.7

Standard deviation of Population σ = 7

Test statistic

                  Z = (x^(-) -mean)/((S.D)/(√(n) ) )

                  Z = (20.5 -18.7)/((7)/(√(11) ) )

                  Z = (1.8)/(2.1105)

                  Z = 0.8528

critical Value

Z_{(\alpha )/(2) } = Z_{(0.01)/(2) } = Z_(0.005) = 2.576

The calculated value Z = 0.8528 < 2.576 at 0.01 level of significance

Null hypothesis is Accepted at 0.01 level of significance.

There is no significance difference between the means

Answer:Answer:

B. 18.7 ± 9.7

Step-by-step explanation:

-4= -(x-8)
negative four equals negative (parentheses x minus 8 parentheses)

Answers

-4=-x-8
+4. +4
—————
0=-x-4
x=-4

A. Use your calculator to approximate ∫^ b_0 e^-0.00001x dx for b=10, 50, 100 and 1000.b. Based on your answers to part a, does ∫^[infinity]_0 e^-0.00001 dx appear to be convergent or divergent?
c. To what value does the integral actually converge?

Answers

Answer:

Step-by-step explanation:

We are to integrate the function

e^-0.00001x from 0 to b for different ascending values of x.

\int e^-0.00001x = -10^5 e^-0.00001x

Now we substitute the limits

When b =10

I = integral value = -10^5 e^-0.00001*10

b =50, I = -10^5(e^-0.00001*50-1)

b =100, I = -10^5( e^-0.00001*100-1)

b =1000 I=  -10^5 (e^-0.00001*1000-1)

b) As b increases exponent increases in negative, or denominator increases hence when b becomes large this will be a decreasing sequence hence converges

c) Converges to  -10^5 (0-1)=10^5
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