Gwen is filling a pool. She begins to wonder how fast the water is flowing into the pool. Which unit rates would be reasonable for Gwen to use to describe how fast the pool is filling with water? Select each correct answer. gal/h cm3/min L/h in3/s

Answers

Answer 1

Answer: I just took the test and the answer was gal/h and L/h, the reason it's not cm3/min or in3/s is because you can't measure water using centimeters or inches.. But you can measure water with Gallons and Liters :)

Answer 2

Answer:

Answer:

Gallons per hour & liters per hour

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The lateral area of a cone is 500 pi cm.^2. The radius is 50 cm. Find the slant height to the nearest tentha. 10 cm
b. 9.1 cm
c. 14.2 cm
d. 11.2 cm

Answers

The answer is a. 10 cm

The lateral area (LA) of the cone can be expressed as:
LA = π * r * l
r - the radius of the cone
l - slant height of the cone

It is given:
l = ?
r = 50 cm
LA = 500π cm²

Let's replace these in the equation for the lateral area of the cone:
500π = π * 50 * l
500π = 50π * l
⇒ l = 500π/50π
l = 10 cm

Calculate the size of side x to 1 decimal
place. Show your working.

Answers

Answer:

$x=7.4$ m and $x=11.2$ m

Step-by-step explanation:

To do these problems, we will need to use the Pythagorean Theorem.

Recall that it states $a^2+b^2=c^2$ , where c is the longest side, the hypotenuse, of the triangle.

a) We have a triangle with side lengths 4.2 m and 6.1 m. These two sides correspond to a and b in this equation.

Now, we can plug these values into the equation and solve for c, which is x.

$(4.2)^2+(6.1)^2=x^2\n\n17.64+37.21=x^2\n\nx=√(54.85)\n\nx=7.406\n\nx=7.4$

b) We have a triangle with side lengths 5.1 m and 12.3 m. These sides correspond to a and c, so b will be x.

Now, we can plug these values into the equation and solve for x.

$(5.1)^2+x^2=(12.3)^2\n\n26.01+x^2=151.29\n\nx=√(151.29-26.01)\n\nx=√(125.28)\n\nx=11.193\n\nx=11.2$

Answer:

Step-by-step explanation:

Formula: A squared + B squared = C squared

For the first question:

4.2 squared = 17.64

6.1 squared = 37.21

17.64+37.21 = 54.85

C squared = 54.85

The square root of 54.85 = 7.4

So, x = 7.4 m

For the second question:

5.1 squared = 26.01

12.3 squared = 151.29

26.01 + 151.29 = 177.3

C squared = 177.3

The square root of 177.3 = 13.3

So, x = 13.3 m

Hope this helps!

log8 (x(x + 6)) = log8 (5x+12)

Please help me!

Answers

As log8(x(x+6)) = log8(5x+12) we can raise e by each side this getting x^2 + 6x = 5x + 12
x^2 + x - 12 = 0
(x+4)(x-3)=0
x=3, x=-4
However we can only do logs of positive number and when -4 is substituted into the equation it gives a negative number so the only true solution is x=3

The perimeter of a rectangle is 34 units. Its width W is 6.5 units. Write an equation to represent the perimeter in terms of the length L, and find the value of L.

Answers

$P=2L+2W\n\nP=34\ \ \ \ \ \ W=6.5\n\n34=2L+2\cdot6.5\n34=2L+13\n34-13=2L\n2L=21\ \ \ \ \ |:2\nL=10.5\n\nLength\ is\ equal\ 10.5$

Answer:

THere ya go

Step-by-step explanation:

Which measure is not the area of a circle with radius 20 mm?

Answers

Given:
radius = 20 mm

Area of a circle = π r²
A = 3.14 * (20mm)²
A = 3.14 * 400mm²
A = 1,256 mm²

400mm² ; 628.57mm² ; and mm² ARE NOT THE AREA OF A CIRCLE

Answer:

thx for the answer

Step-by-step explanation:

The table gives sales data for a stationery store in any given two weeks. It lists the probability of the number of items purchased in a single transaction and the average amount spent per transaction. Items Purchased in a Single Transaction Probability Average Amount Spent 2 0.35 $12 3 0.17 $20 4 0.33 $28 5 or more 0.15 $36 Based on the data provided, transactions with items are likely to bring in the most income during the next two-week transaction period.

Answers

From the given data:

Number of items | Probability of being purchased | Average amount spent
--------------------------------------------------------------------------------------------------
2 | 0.35 | $12
3 | 0.17 |    $20
4   | 0.33 | $28
5 or more   | 0.15 | $36

In a sample space of 100 items being purchased, in a day:

For 2 items: 35 (12) = 420
For 3 items: 17 (20) = 340
For 4 items: 33 (28) = 924
For 5 or more items: 15 (36) = 540

If this sample trend would go on the for the next two weeks, then the transaction with 4 items would most likely bring in the most income during the said transaction period.

Answer:

Based on the data provided, transactions with 4 items are likely to bring in the most income during the next two-week transaction period.

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