Answer:
B False
Explanation:
Answer: False
It is not true
Answer:
DNA in eukaryotes have introns which are the non-coding sequences and are spliced out of primary transcript. They are not present in mature mRNA.
Explanation:
The reading frame of 50 or more nucleotides without any termination codon in between is called an open reading frame. The long open reading frames mostly represent protein-coding genes.
Hence, long open reading frames are searched for in order to find the genes. The presence of introns in eukaryotic DNA does not allow the application of this approach to find genes in eukaryotes.
The post-transcriptional modification of the primary transcript removes the introns. Hence, a mature mRNA does not have introns. Therefore, introns do not contain open reading frames.
b. What is the probability that:
(i) The first child that is born will not have moles.
(ii) All of the children will have moles.
(iii) The first two children will have no moles and the last five will have moles.
(iv) Of the 7 children, 4 will have no moles and 3 will have moles
c. Assume this couple now have two children, one with moles and one without moles. What is the probability that the child born without moles is a carrier of the a-allele (ie heterozygous)?
Answer:
a. =
b. i. 0.75
ii. 0.000061
iii. 0.012
iv. 0.17
c. 0.67
Explanation:
a. The expansion of the binomial (p + q)7 would be such that:
=
b. Both couples are heterozygous:
Aa x Aa
AA Aa Aa aa
Since A is dominant over a,
probability of having mole (aa) = 1/4
probability of not having moles = 3/4
Therefore, the probability of the first child not having moles = 3/4 or 0.75
ii. Let the probability of not having mole = p and the probability of having mole = q. From the binomial expansion:
=
Probability that all of the children will have moles =
since p = 3/4 and q = 1/4
= = 0.000061
iii.Probability that the first two children will have no moles and the last five will have moles =
=
= 0.012
iv. Probability that 4 will have no moles and 3 will have moles out of the 7 children =
=
= 0.17
c. Probability that the child born without moles is a carrier of the a-allele = probability of heterozygous.
From the cross in (b), the genotypes of those born without moles are AA and 2Aa. Therefore, the probability of not having moles and be Aa is:
= 2/3 or 0.67
Cold-blooded animals change their body temperature to match the environment.
Mammals and birds are usually cold blooded.
All of the above.
Answer:
Explanation:
Cold blooded animal did not have cold blood.
Cold blooded animals can’t change their body temperature to match the environment.
Mammals and birds are not cold blooded.
Endotherms, such as mammals and birds, are able to maintain a constant body temperature in the face of changing environmental conditions. In contrast, cold-blooded animals, or ectotherms, have a body temperature that matches their environment and varies with it.
An animal that maintains a constant body temperature in the face of environmental changes is called an endotherm. These animals are able to maintain a level of activity that an ectothermic animal cannot because they generate internal heat that keeps their cellular processes operating optimally even when the environment is cold.
Mammals and birds evolved endothermy, meaning they regulate their body temperature from the inside through metabolic or physical changes. This allows them to maintain a relatively stable body temperature regardless of the outside temperature.
Cold-blooded animals, also known as ectotherms, rely on external temperatures to set their body temperature. Their body temperature varies with the environment.
i think its abrasion
Answer:
Erosion
Explanation:
neurotransmitters are often reffered to as the body's chemical messangers. They are the molecules used by the nervus system to transmit messages between neurones, or from neurones to muscles. Communication between two neurones happens in the synaptic cleft (the small gap between the synapses of neurones).