Please help me with this question! :)
Please help me with this question! :) - 1

Answers

Answer 1
Answer:

Answer:

red is the anwser y=3x+2


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Suppose you buy a new car whose advertised mileage is 23 miles per gallon​ (mpg). After driving your car for several​ months, you find that its mileage is 19.4 mpg. You telephone the manufacturer and learn that the standard deviation of gas mileages for all cars of the model you bought is 1.07 mpg. A. Find the​ z-score for the gas mileage of your​ car, assuming the advertised claim is correct.
B. Does it appear that your car is getting unusually low gas​mileage?

Answers

Answer:

B.

Step-by-step explanation:

A.

mu = population mean = advertised mean = 23

x = raw score = 19.4

sigma = population standard deviation = 1.07

z = (x - mu)/sigma

z = (19.4 - 23)/1.07

z = -3.36448598130841

z = -3.36

=======================================

B.

The general rule is that if -2 \le z \le 2, then the z score is not unusual. Otherwise, it is unusual.

Since z = -3.36 falls outside the range, the car is getting unusually low gas mileage.

What is the percent increase of 10 to 24?

Answers

The percent of increase is 140%

Work is provided in the image attached.

Have a great day!

Let me explain it like this. add an extra 0 after 10 and you have 100 so every time you add 10 to the original number you are adding 100% so your answer would be 140%

You and your friend are rolling number cubes. Each cube has 6 sides with the numbers 1 to 6. If a sum of 7 is rolled, your friend gets a point. However, you get a point if either one of the sums listed below is rolled. Which pair of numbers would make the game fair?

Answers

Answer: Hello mate!

Ok, the 6 sides cubes can be thinked as two normal dice.

A fair game is that game where both players have the same chance to win, first, let's calculate the situations where you friend win:

this are, if the cubes have numers between 1 and 6:

1 + 6

6 + 1

2 + 5

5 + 2

3 + 4

4 + 3

where 1 + 6 is different to 6 + 1 because in the first one you rolled a 1 and your friend a 6, and in the second one you rolled a 6 and your friend a 1, so are different events.

Then you can see that you friend has 6 combinations where he wins.

So we need to find two numbers that between them, have the same number of combinations.

I can think, for example in 4 and 10:

the combinations for 4 are:

2 + 2

3 + 1

1 + 3

a total of 3 combinations:

for 10 are:

5 + 5

4 + 6

6+ 4

also 3 combinations.

So if you win a point if the sum is 4 or 10, you also have 6 combinations where you win, then the game is fair

Now, suppose the first number is 5, let's find the second:

the combinatios for 5 are:

4 + 1

1+ 4

2 + 3

3 + 2

a total of 4 combinations, this means that we need to find another number that only has two combinations, wich can be, for example, 3

the combinations for 3 are:

1 + 2

2 + 1

2 combinations, then if your numbers are 3 and 5, you have 6 combinations where you win, and the game is fair.

You don't list the "sums listed below" but I can still help you.
There are 6 ways to get a sum of 7 using a pair of dice:
1+6
6+1    You might be asking why 2+5 isn't the same as 5+2
2+5      Imagine the dice are different colors.  Is a red 2 and green 5 the
5+2          same as a green 2 and red 5?  (No, it's not)
3+4
4+3
You need two numbers that also provide 6 ways to win.  One pair that would work is 11 and 9   There are two ways to make 11 (5+6) and (6+5)  and there are four ways to make 9 (3+6), (6+3) (4+5) and (5+4) - that's a total of six ways.  So to balance your friend's 7 - you could go for sums of 11's and 9's.  Check the choices you were given and find the numbers (it could be three numbers like 2,3, and 12) that give you 6 ways to win.
Here are the numbers and their ways
Sum of the dice                          Ways to get it
2                                                      1
3                                                      2
4                                                      3
5                                                      4
6                                                      5
7                                                      6
8                                                      5
9                                                      4
10                                                    3
11                                                    2
12                                                    1


Please answer pleaseeee​

Answers

Answer:

k=y/x

Step-by-step explanation:

Five flowering plants are to be planted between two trees which are 12m apart. If the first tree is 2m away from the house, how far from the house is each of the plants?

Answers

Answer:

2m, 14m, 26m, 38m, 50m

Step-by-step explanation:

In order to calculate the distance of each tree from the house we simply need to add 12m to the initial starting point of the first tree which is 2m away, and then add 12m to that distance and so on until all 5 trees are planted. The distances would be the following...

1st Tree: 2m

2nd Tree: 2m + 12m = 14m

3rd Tree: 14m + 12m = 26m

4rth Tree: 26m + 12m = 38m

5th Tree: 38m + 12m = 50m

Therefore, those are the distances between each tree 2m, 14m, 26m, 38m, 50m

Solve the system by graphing. Write the solution as an ordered pair. y = 1/3x + 2 y = –x – 2Help me please....I need good grades

Answers

ANSWER

The solution is where the two graphs intersect, which is
(-3,1).

EXPLANATION

The given system of equations are
y = (1)/(3) x + 2
and

y = - x - 2

We need to graph the two equations.

Let us graph

y = (1)/(3) x + 2
first.

We need at least two points.

You can choose any appropriate value for x and solve for y. Choosing zero makes our working easier. So let us plot the intercepts.

When
x = 0

\Rightarrow \: y = (1)/(3) (0) + 2

\Rightarrow y = 0 + 2

\Rightarrow y = 2

So this gives us the ordered pair,

(0,2)

When
y = 0
we get,

0= (1)/(3) x + 2

\Rightarrow \: - 2 = (1)/(3) x

\Rightarrow \: - 2 * 3= x

\Rightarrow \: -6= x
This also gives the ordered pair

(-6,0).

We plot these two points and draw a straight line through them to obtain the blue graph in the attachment.

For the second line



We again find the intercepts and plot them.

When
x = 0

y = - 0 - 2

\Rightarrow \: y = - 2

This gives the ordered pair

(0,-2)

Also, when
y = 0

then we have,

0 = - x - 2

2 = - x

x = - 2

Then we again have the ordered pair,

(-2,0)

We plot these two points on the same graph sheet to obtain the red graph above.

The intersection of the two lines is
(-3,1)


You will get good grades so don't worry much.

Answer:

?

jh24

Step-by-step explanation: