Answer:
The calculated value Z = 1.183 < 1.96 at 0.05 level of significance
Null hypothesis is accepted
A particular greyhound breeder claims that her dogs are faster than the average greyhound
Step-by-step explanation:
Step(i):-
Given the average speed of greyhound dogs is about 18.4 meters per second.
Size of the sample 'n' = 35
mean of the sample x⁻ = 18.7
Population standard deviation = 1.5m/s
level of significance (∝) = 0.05
Step(ii):-
Null hypothesis : H₀ : μ = 18.4
Alternative hypothesis H₁ : μ ≠ 18.4
Test statistic
Z = 1.183
Conclusion:-
The calculated value Z = 1.183 < 1.96 at 0.05 level of significance
Null hypothesis is accepted
A particular greyhound breeder claims that her dogs are faster than the average greyhound
Evaluate the breeder's claim by using a one-sample z-test. The null hypothesis states that the breeder's dogs aren't faster than average, while the alternative hypothesis states that they're faster. If the calculated Z is greater than Zcritical, it supports the breeder's claim.
In this scenario, you would carry out a one-sample z-test to evaluate the breeder's claim. Given an average speed of greyhounds as 18.4 m/s, the breeder's dogs with an average of 18.7 m/s could be faster or this could just be due to statistical fluctuation. Hence, we need to statistically test it to see if this evidence is strong enough (with a significance level of .05) to support the breeder's claim.
Our null hypothesis (H0) is that the breeder's dogs are not faster than the average greyhound (µ = 18.4 m/s), and our alternative hypothesis (Ha) is that they are faster (µ > 18.4 m/s). Using the Z-test formula:
Z = (Xbar - µ) / (σ/√n)
where Xbar is sample mean, µ is population mean, σ is standard deviation, and 'n' is sample size. Applying the provided figures, we get:
Z= (18.7-18.4)/(1.5/√35)
Give the calculated Z value and compare it to the Z critical value for 0.05 significance level (1.645 for one-tail). If the calculated Z is greater than Zcritical, we reject the null hypothesis, providing evidence that the population mean is greater than 18.4 m/s, supporting the breeder's claim.
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Answer:
0.288
Step-by-step explanation:
Given that :
Correlation (R) = 0.48
Slope of linear model which predicts Lifespan from years of education (m) = 0.8
To determine the value of slope of the model which predicts years of eductauoon from lifespan:
The square of the regression Coefficient is multiplied by the inverse of the slope of linear model which predicts Lifespan from years of education
Hence,
(R² * 1/m)
0.48² * 1/0.8
0.2304 * 1.25
= 0.288
The slope of the line that predicts years of education from lifespan is 1.25.
The slope of the line that predicts years of education from lifespan can be determined by taking the reciprocal of the slope that predicts lifespan from years of education. In this case, the slope of the line that predicts years of education from lifespan would be 1 divided by 0.8, which equals 1.25.
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Answer:
3
Step-by-step explanation:
colinear points mean along the same line
Line m has 3 points labeled
Line n has 3 points labeled
Each line has only 3 points labeled
This is an edit from my previous answer.
Initially I wrote that there were 5 collinear points. My line of reasoning was that A,B,C are on one line (making them collinear), and points D,B,E are on another line (another set of collinear points).
However, if the question is asking how many collinear points are on one particular line, then the answer would be 3 collinear points. You can focus on either line and it's the same number of collinear points.
Definition: The term "collinear" means all points fall on the same straight line.
0.147 0 0.174
Answer:
<
Step-by-step explanation:
.174 is greater than .147
Exam Image
Subject to
x ≤ 3
y ≤ 9
x + y ≥ 9
x ≥ 0
y ≥ 0
Answer:
Minimum value of function is 63 occurs at point (3,6).
Step-by-step explanation:
To minimize :
Subject to constraints:
Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line
Eq (2) is in green in figure attached and region satisfying (2) is below the green line
Considering , corresponding coordinates point to draw line are (0,9) and (9,0).
Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line
Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)
Now calculate the value of function to be minimized at each of these points.
at A(0,9)
at B(3,9)
at C(3,6)
Minimum value of function is 63 occurs at point C (3,6).
Applying the method of corners to the linear programming problem yields a minimum value of 6 at the point (3, 0) for the given objective function and constraints.
The linear programming problem involves minimizing an objective function subject to certain constraints. The constraints are given as follows:
Minimize z = 2x + 3y
Subject to:
x ≤ 3
y ≤ 9
x + y ≥ 9
x ≥ 0
y ≥ 0
To find the minimum value, we employ the method of corners. The feasible region is determined by the intersection of the inequalities. The corner points of this region are where the constraints intersect.
Intersection of x ≤ 3 and y ≥ 0 gives the point (3, 0).
Intersection of y ≤ 9 and x ≥ 0 gives the point (0, 9).
Intersection of x + y ≥ 9 and y ≥ 0 gives the point (9, 0).
Now, evaluate the objective function z = 2x + 3y at each corner point:
z1 = 2(3) + 3(0) = 6
z2 = 2(0) + 3(9) = 27
z3 = 2(9) + 3(0) = 18
The minimum value occurs at point (3, 0) with z_min = 6.
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Answer:
10
Step-by-step explanation:
8+10+9+3=30. So, 40-30=10
Answer:10
Step-by-step explanation:
Add 9 to 10 to get 19, then add 3 to get 22, then add 8 to get 30.
Using the provided information, it is determined that $6000 was Joyce's total weekly sales.
Comparing two amounts while rebasing the second amount to 100 is the simplest way to use percentages.
Given:
An insurance agent named Joyce Flynn made a commission of $1,800 in her first week on the job. She receives a 30% commission.
We need to find the total sales for the week.
Let, x = total commission
Since, 30% of total commission is 1800. So, total sales will be:
x = 1800/0.30 = 6000
Therefore, Joyce's total sales for the week is found to be $6000 by using the given data.
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