Answer:
The answer is "Mode of replication".
Explanation:
The answer is the model for reproduction because it is the genetic reproduction implements a diffraction model, which replaces some old bases with other small colonies for each strand of the fetus, opposed to a semiconservative model of reproduction in eukaryotic cells, wherein one chromosome is completely new and one is old.
Replication in both eukaryotic life and an alien sample would involve the duplication of genetic information, but the specifics could vary. For instance, while eukaryotes use DNA and replication is bi-directional, the alien sample might use RNA and replication could be uni-directional. These are, however, speculative based on our understanding of life on Earth.
In both the eukaryotic life found on Earth and in the hypothetical alien sample, processes of replication would involve the duplication of DNA, which serves as the basis for passing genetic information from one generation to the next. In eukaryotes, this process is accomplished via DNA replication, a bi-directional process in which the DNA helix is unwound and each strand is used as a template for the synthesis of a new complementary strand.
In contrast, we can speculate that the alien sample might have biochemical differences that influence its DNA replication process. The alien sample, for instance, could utilize RNA instead of DNA as the main carrier of genetic information. Its replication process might also proceed in a uni-directional manner, which is contrary to the bi-directional process in eukaryotes. Nevertheless, these differences are more conjectural since we don't have a specific example of extraterrestrial life to examine.
#SPJ3
Answer:
See the answer below
Explanation:
Watson and Crick modeled the structure of the DNA as being made up of 2 strands with each strand composed of a long chain of nucleotide bases. The DNA. The 2 strands are said to be associated by a hydrogen bond and are twisted around each other in a ladder-like manner to form a helix structure.
Specifically on the bases, Watson and Crick modeled that the nucleotide bases component of one strand of a double helix DNA are complementary to the nucleotide bases of the other strand according to the base-pairing rule.
The base-pairing rule states that adenine always pairs with thymine while guanine always pairs with cytosine. This thus means that with the nucleotide sequence of one strand known, the sequence of the other strand of a double helix DNA can be determined.
Answer: Activates glycolysis and inhibits gluconeogenesis
Explanation:
Fructose‑2,6‑bisphosphate coordinates glucose breakdown in glycolysis generates by modulating the action of phosphofructokinase 1 and at the same time inhibits gluconeogenesis.
Answer:
Hypertonic:) u welcome
Explanation:
Answer:
I would probably say #4 All the previous could cause this
Mendel was the first to explain the transmission of phenotypic characters and the independent assortment of the genes.
In the given data, F2 progeny of phenotypic traits are shown.
In the above observations, the gray body long wings and ebony body vestigial wing are parental combinations.
Also, the gray body and vestigial wings, and ebony body long wings are the recombinants.
The given ratio in the progeny indicates that gray bodies and long wings are expressed.
The genes for the two traits are independently assorted, which means that genes are unlinked present on the samechromosome.
Now,
For the F1 progeny:
The cross between Gl and hybrid will result in a 50% chance of flies having the gray body and vestigial wings.
b) In the above given F2 progeny, the cross between true gray body and long wings with true ebony body and vestigial wings, will result in the independent assortment of the genes.
Given:
For the F1 progeny, all the offspring will have genotype GgLl (Gray body and long wings but in heterozygous condition)
The above cross can be shown in the Punnett square, which is given in the attachment below.
To know more about Mendelian ratio, refer to the following link:
Answer:
Check the explanation
Explanation:
Consider the below table of F2 data of phenotypic flies: we can reconstruct the table as seen in the second attached image below:
From the above observations it is clear the Gray body long wings and Ebony body vestigial wings are the parental combinations and that the Gray body vestigial wings and Ebony body long wings are the recombinants.
Also the ratio indicates that Gray body is dominant over ebony body and that long wings is dominant over vestigial wings.
here the genes for the two characters have shown independent assortment which means that the genes are unlinked if located on the same chromosome or are located on different chromosomes.
Now F1 hybrid= GgLl (G for Grey and L for Long)
Cross between F1 hybrid and true breeding Gray vestigial (GGll)
GgLl x GG ll
Gametes-----------> GL Gl gL gl Gl
GL Gl gL gl
Gl GGLl GGll GgLl Ggll
(Gray long) (Gray vestigial) (gray Long) (Gray vestigial)
Therefore the probability of getting the flies with gray body vestigial wings= 2/4= 50%
b) The reason why the students obtained the above given F2 results involving a cross between true breeding Gray body and long wings with true breeding Ebony body and vestigial wings is that the genes for the two charcters asssort independently in F2 generation and that the genes are not linked as:
Parents------------------> GGLL x ggll
Gametes -----------------> GL gl
F1---------------------> GgLl (Gray long but in heterozous condition)
Now GgLl x GgLl
Gametes GL Gl gL gl GL Gl gL gl
Here gametes assorted independently and hence in F2 generation we got the above results (U can show the results in the form of punnett square.