b. .y=9/8x 11/8
c. .y=-8x-11
d. .y=8/9x-11/9
A. point M
B. point N
C. point O
D. point R
diagram shown below...
(((<--------M---------N---------O------P--------Q----------R--------S--------->)))
Answer:
Point R located on ray PQ.
Step-by-step explanation:
Given : Diagram
To find : Which point is located on ray PQ.
Solution : We have given <--------M---------N---------O------P--------Q----------R--------S--------->.
Ray : A part of a line with a start point but no end point (it goes to infinity).
We can see from the diagram ray PQ start from P but it has no end point.
So , point R ans S located on ray PQ but we have option R
Therefore, D. point R located on ray PQ.
Josephine will receive approximately 70 advertisements in the next 100 e-mails she receives.
The possibility of an event in time is known as probability in mathematics. How frequently does the incidence occur over the course of a specific time period, in plain English?
If Josephine received 7 advertisements out of 10 e-mails, then we can say that the probability of receiving an advertisement in a single e-mail is 7/10 or 0.7.
Assuming that the probability of receiving an advertisement in an e-mail remains the same for all e-mails, we can use this probability to make a prediction about the number of advertisements she will receive in the next 100 e-mails.
The expected number of advertisements in 100 e-mails can be calculated by multiplying the probability of receiving an advertisement in a single e-mail by the total number of e-mails:
Expected number of advertisements = probability of an advertisement x total number of e-mails
= 0.7 x 100
= 70
Therefore, based on the given information, we can predict that Josephine will receive approximately 70 advertisements in the next 100 e-mails she receives.
To learn more about the probability;
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