Jin (WWH) spends 18.55 for every 7 tacos he gets. That means he spends 18.55÷7 for every taco he gets.
18.55÷7 = 2.65
Now you need to find how much he spends for 15 tacos. If one taco is 2.65, you need to multiply 15 by 2.65 to find the price for 15 tacos.
2.65×15=39.75.
Jin will have to pay $39.75 for 15 tacos.
Answer:
Step-by-step explanation:
(4, 19) and (2, 11)
Answer:
General Formulas and Concepts:
Pre-Algebra
Algebra I
Step-by-step explanation:
Step 1: Define
(4, 19)
(2, 11)
Step 2: Find slope m
Answer:
y = -3x + 6
Step-by-step explanation:
Equation of straight line is given by,
y = mx + b
m = slope of the line
b = y-intercept
From the graph attached,
m =
=
= -3
y intercept 'b' = 6
Therefore, equation of the line will be,
y = -3x + 6
Answer:
Knowing that those vectors start at the point (0,0) we can "think" them as lines.
As you may know, two lines are parallel if the slope is the same, then we can find the "slope" of the vectors and see if it is the same.
A) the vectors are: (√3, 1) and (-√3, -1)
You may remember that the way to find the slope of a line that passes through the points (x1, y1) and (x2, y2) is s = (y2 - y1)/(x2 - x1)
Because we know that our vectors also pass through the point (0,0)
then the slopes are:
(√3, 1) -----> s = (1/√3)
(-√3, -1)----> s = (-1/-√3) = (1/√3)
The slope is the same, so the vectors are parallel.
Part B:
The vectors are: (2, 3) and (-3, -2)
the slopes are:
(2, 3) -----> s = 3/2
(-3, -2)----> s = -2/-3 = 2/3
the slopes are different, so the vectors are not parallel.
∥v∥=√((6)^2+(-8)^2)=√(36+64)=√100=10. Dividing v by its magnitude, we get the unit vector u=(v/∥v∥)=(6i−8j)/10=(3/5)i−(4/5)j. Therefore, two unit vectors parallel to v are (3/5)i−(4/5)j and −(3/5)i+(4/5)j.
a. Two unit vectors parallel to v=6i−8j can be found by dividing the vector v by its magnitude. The magnitude of v can be calculated using the formula ∥v∥=√(v1^2+v2^2), where v1 and v2 are the components of v in the x and y directions, respectively. In this case, v1=6 and v2=−8. Thus,
b. To find the value of b when v=⟨1/3,b⟩ is a unit vector, we need to calculate the magnitude of v and set it equal to 1. The magnitude of v is given by ∥v∥=√((1/3)^2+b^2). Setting this equal to 1, we have √((1/3)^2+b^2)=1. Squaring both sides of the equation, we get (1/3)^2+b^2=1. Simplifying, we have 1/9+b^2=1. Rearranging the equation, we find b^2=8/9. Taking the square root of both sides, we get b=±(2√2)/3. Therefore, the value of b when v is a unit vector is b=(2√2)/3 or b=−(2√2)/3.
c. To find all values of a such that w=ai−a/3j is a unit vector, we need to calculate the magnitude of w and set it equal to 1. The magnitude of w is given by ∥w∥=√(a^2+(-a/3)^2). Setting this equal to 1, we have √(a^2+(-a/3)^2)=1. Simplifying, we get a^2+(a^2/9)=1. Combining like terms, we have (10/9)a^2=1. Dividing both sides by 10/9, we get a^2=(9/10). Taking the square root of both sides, we have a=±√(9/10). Therefore, the values of a such that w is a unit vector are a=√(9/10) or a=−√(9/10).
Learn more about vectors parallel here:
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Answer:
do you expect me to flip sideways just to help you cheat on ur homework
Step-by-step explanation:
The number of federally insured banks in the year 1990 was 12,100.
Given data:
To find the number of federally insured banks in the year 1990, you need to substitute the value of t = 1990 into the given function B(t):
B(t) = -329.4t + 13747
Since t corresponds to the year and t = 0 corresponds to 1985, we need to calculate for t = 1990 - 1985.
t = 5.
Substitute t = 5 into the function:
B(5) = -329.4 * 5 + 13747
Now, perform the calculations:
B(5) = -1647 + 13747
B(5) = 12100
Hence, there were approximately 12,100 federally insured banks in the year 1990.
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Using the given equation and by substituting t with 5 (for the year 1990, five years after 1985) in that equation, we find that there were 13363 federally insured banks in 1990.
The question is asking how many federally insured banks there were in 1990, given that the number of banks in any given year from 1985 to 2007 is given by the equation
B(t) = -329.4t + 13747
. In this equation,
t
is the year with t=0 corresponding to 1985. To find the answer, we should substitute in the appropriate value of t, which would be 5 because 1990 is five years after 1985. Thus, the equation becomes B(5) = -329.4*5 + 13747. This simplifies to 15010 - 1647, which equals
13363
. Therefore, there were 13363 federally insured banks in 1990.
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