MATHEMATICS HIGH SCHOOL

-2y > 2
a. a
b. b
c. c
d. d

Answers

Answer 1
Answer: -2y > 2
y < 2/-2
y < -1

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Baseball tickets cost $15 for general admission or $20 for box seats. the sales tax on each ticket is 8%. What is the final cost of each type of ticket

Answers

Answer:

the final cost of a box seat ticket is $21.60.

Step-by-step explanation:

To calculate the final cost of each type of ticket, we need to add the sales tax to the original ticket prices.

For the general admission ticket:

Original price = $15

Sales tax = 8% of $15 = 0.08 * $15 = $1.20

Final cost of general admission ticket = Original price + Sales tax = $15 + $1.20 = $16.20

Therefore, the final cost of a general admission ticket is $16.20.

For the box seat ticket:

Original price = $20

Sales tax = 8% of $20 = 0.08 * $20 = $1.60

Final cost of box seat ticket = Original price + Sales tax = $20 + $1.60 = $21.60

Therefore, the final cost of a box seat ticket is $21.60.

Chicago Pizza charges $10.49 for a medium 14" pepperoni pizza and NY Pizza charges $20.99 for an x-large 18" pepperoni pizza. Question #2. Find the cost per square inch of the NY Pizza rounded to the nearest cent.


A. $0.07 per square inch

B. $0.37 per square inch

C. $0.08 per square inch

D. $0.02 per square inch

Answers

Answer:

Answer C $0.08

Step-by-step explanation:

20.99/(π*9*9)=20.99/254.44=0.08

In parallelogram ABCD, E is the midpoint of AB and F is the midpoint of DC . Let G be the intersection of the diagonal DB and the line segment EF . Prove that G is the midpoint of EF.

Answers

The midpoint of the line \overline{EF} is the point that divides \overline{EF} in two halves of the same length.

  • ΔDFG ≅ ΔBGE and \overline{FG} ≅ \overline{EG} by CPCTC, therefore, Gis the midpoint of \overline{EF}

Reasons:

The given parameters are;

The midpoint of AB in parallelogram ABCD = E

The midpoint of DC = F

Point of intersection of EF and DB = Point G

Required:

To prove that point G is the midpoint of EF.

Solution:

Statement         {}                       Reason

1. m∠BDC ≅ m∠ABD          {}  1. Alternate angles theorem

2. m∠DGF ≅ m∠BGE           {}2.Vertical angles theorem

3. \overline{DC} = \overline {AB}          {}                  3. Opposite sides of a parallelogram ABCD

4. \overline{CF} ≅ \overline{DF}          {}                 4. Definition of midpoint of DC

5. \overline{CF} = \mathbf{\overline{DF}}          {}                  5. Definition of congruency

6. \overline{CF} + \overline{DF} = DC         {}         6. Segment addition property

7. \overline{CF} + \overline{CF} = DC         {}          7. Substitution property

8. 2·\overline{CF} = DC        {}                 8. Addition

9. \overline{CF} = 0.5· \overline{DC} = \overline{DF}        {}  9. Division property    

Similarly;

10. \overline{AE} = 0.5·\overline{AB} = \overline{EB}         {}  10. Division property

11. 0.5· \overline{DC} = 0.5·\overline{AB}         {}     11. Multiplication property of equality

12. \overline{AE} = \overline{EB}          {}                 12. Substitution property

13. ΔDFG ≅ ΔBGE     {}             13. Angle-Angle-Side rule of congruency

14. \overline{FG} ≅ \overline{EG}                 {}          14. CPCTC   {}  

15. \overline{FG} = \overline{EG}     {}                       15. Definition of congruency

16. Point G is the midpoint of \overline{EF}{}  17. Definition of midpoint

Learn more about the midpoint of a line here:

brainly.com/question/5127222

Answer:

GF = GE that prove G is the mid-point of EF

Step-by-step explanation:

In the Parallelogram ABCD

∵E is the mid-point of AB

∵F is the mid-point of CD

∵AB = CD opposite sides in the parallelogram

∴EB = DF⇒(1)

∵AB // CD opposite sides in the parallelogram

∴m∠EBD = m∠FDB alternate angles ⇒(2)

∵BD intersects EF at G

∴m∠BGE = m∠DGF vertically opposite angles ⇒(3)

By using (1) , (2) and (3) you can prove:

ΔBGE is congruent to ΔDGF ⇒ AAS

∴GF = GE

∴G is the mid-point of EF

Which of the following numbers is a power of 10?A : 20

B : 500

C : 1.000

D : 1.010

Answers

C is the correct answer.

? M/S = 7.2 km/h ------ PLEASE HELP

Answers

To go from km/h to M/S you have to multiply by 3,6 so this must be the answer:
7,2 km/h x 3,6 = 25,92 M/S

Traveling from San Antonio to Dallas, you fist pass through Austin and then Waco before reading Dallas, a total distance of 280 miles. From Austin to Waco is 30 miles faster than from San Antonio to Austin, and also 20 miles farther than from Waco to Dallas. How far is it from Waco to Dallas?

Answers

The answer is 70 miles.

If we express distances as following:
T - total distance
a - distance from San Antonio to Austin
b - distance from Austin to Waco
c - distance from Waco to Dallas
Then:
T = 280 mi
b = a - 30 mi        ⇒ a = b + 30
b = c + 20 mi       ⇒ c = b - 20

T = a + b + c
⇒ a + b + c = 280
⇒ b + 30 + b + b - 20 = 280
⇒ 3b +10 = 280
⇒ 3b = 280 - 10
⇒ 3b = 270
⇒ b = 90 mi.

Distance from Waco to Dallas is c.
c = b - 20
⇒ c = 90 - 20
⇒ c = 70 mi

Therefore, distance from Waco to Dallas is 70 miles.
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