True or false?30 is divisible by 2, 4, 5, and 10. hurry please trying to go get my nails done
Answers
Answer:
It's false see 4 cannot go into 30 can I have
brainly?:)
Step-by-step explanation:
Related Questions
Tristan records the number of customers who visit the store each hour on a Saturday. His data representing the first seven hours are 15, 23, 12, 28, 20, 18, and 23. How many customers visited the store during the eighth hour if the median number of customers per hour did not change?16192023
In a sample of 50 households, the mean number of hours spent on social networking sites during the month of January was 45 hours. In a much larger study, the standard deviation was determined to be 8 hours. Assume the population standard deviation is the same. Which of the statement below best describes that there is a 95% confidence interval for the mean hours devoted to social networking in January? A. The 95% confidence interval ranges from 8 to 45 hours. B. The 95% confidence interval ranges from 40.13 to 45.78 hours. C. The 95% confidence interval ranges from 43.87 to 46.13 hours. D. The 95% confidence interval ranges from 42.78 to 47.22 hours.
Multiply polynomials(6p+8)(5p-8)
5(t+3)+2(3t+4)-(5t-3)
379.94 in2
452.16 in2
527.52 in2
621.72 in2
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A = πr^2
where A is the area and r is the radius which is half the diameter.
Let's plug in values we know and solve:
A = 3.14(11 in)^2
A = 3.14(121 in^2)
A = 379.94 in^2
Answer:
the Answer is A i just took the test
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Data Set 2: {75, 74, 68, 83, 80}
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What was Linda's total cost (including the monthly premium)? $
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Linda's premiums for 12 months = $50 × 12 = $600
Deductible is the amount Linda Frankell will have to pay each year as a policy holder towards her medical expenses before the insurance company pays its share.
Amount Linda pays towards deductible = $300
Linda's medical bills = $2,600.00
The insurance company will pay 80% of the bills less the deductible, which means, the insurance company will pay 80% of the ($2,600.00 - $300 deductible = $2,300.00)
∴ Amount the insurance company pays = 80% of $2,300.00 = $1,840.00
Amount Linda has to pay towards the $2,300.00 = $2,300.00 - $1,840.00 = $460.00
Linda's total cost = Linda's 12 months premiums + $300 deductible + $460 = $600 + $300 + $460 = $1,360.00
Insurance company's payment = $1840.00
Linda's total cost = $1,360.00
a. 760
b. 780
c. 800
d. 860
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The answer is:
a. 760
Answers
Add the reciprocals of these numbers.
Now add the squares of the numerator and denominator, as in the example.
So this number has to be a perfect square.
It is a perfect square, so this method always works.
The numbers
Answer:
even tho this has nothing to do with the answer ;-;
Step-by-step explanation:First a definition: A Pythagorean Triple are three natural numbers 1 <= a <= b <= c, such that a2 + b2 = c2 holds. For example 3, 4, 5 is such a triple, since 32 + 42 = 9 + 16 = 25 = 52. While 2, 3, 4 is not such a triple, since 22 + 32 = 4 + 9 = 13 and 42 = 16. We note here that only natural numbers are considered, and thus 2, 3 can not be extended to Pythagorean triple (since 13 is not the square of some integer).
Now the question: Can we colour the natural numbers 1, 2, 3, ... with two colours, say blue and red, such that there is no monochromatic Pythagorean triple? In other words, is it possible to give every natural number one of the colours blue or red, such that for every Pythagorean triple a, b, c at least one of a, b, c is blue, and at least one of a, b, c is red ? We prove: The answer is No. That is easier to express positively: Whenever we colour the natural numbers blue or red, there must exist a monochromatic triple (one blue triple or one red triple).
More precisely we prove, using "bi-colouring" for colouring blue or red: 1) However we bi-colour the numbers 1, ..., 7825, there must exist a monochromatic Pythagorean triple. 2) While there exists a bi-colouring of 1, ..., 7824, such that no Pythagorean triple is monochromatic. Part 2) is relatively easy. Part 1) is the real hard thing -- every number from 1, ..., 7825 gets one of two possible colours, so altogether there are 27825 possible colourings, which all in a sense need to be considered, and need to be excluded. What is 27825? It is approximately 3.63 * 102355, that is, a number with 2356 decimal places. The number of particles in the universe is at most 10100, a tiny number with just 100 decimal places (in comparison).
Now let's perform real brute-force, running through all the possibilities, one after another: Even if we could place on every particle in the universe a super-computer, and they all would work perfectly together for the whole lifetime of the universe -- by far not enough. Even not if inside every particle we could place a whole universe. Even if each particle in the inner universe becomes again itself a universe, with every particle carrying a super-computer, still
by far not enough. Hope you get the idea -- the $100 we got wouldn't pay that energy bill.
Fortunately there comes SAT solving to the rescue, which actually is really good with such tasks -- it can solve some such task and even more monstrous tasks. Our ``brute-reasoning'' approach solved the problem and resulted into a 200 terabytes proof -- the largest math proof ever. Though we must emphasise that this is in no way guaranteed, and possibly it will take aeons! SAT solving uses propositional logic, in the special form of CNF (conjunctive normal form). Fortunately, in this case it is easy to represent our problem in this form.