Answer:
yes
Explanation:
that is the answer
a. iron.,B.nickel.,C.Cooper.,D.lead.
Answer:
Copper
Explanation:
Answer:
The answer to your question is 0.14 M
Explanation:
Data
Molarity = ?
number of moles = 0.25
volume = 1.8 L
Formula
Substitution
Simplification and result
Molarity = 0.14 M
Answer: ratio is 10⁻⁵
Explanation:
From Acid-dissociation equilibrium constant, HA is given thus,
HA + H₂O ⇄ H₃O⁺ + A⁻
equilibrium constant, Ka = [H₃O⁺] [A⁻] / [HA]
[H₃O⁺] = Ka [HA] / [A⁻]
from this we have that
pH = -log[H₃O⁺]
and pKa = -logKa
Applying Henderson-Hassel bach equation;
pH = pKa + log [A⁻]/[HA] ...........(1)
A⁻ rep the salt and HA rep the acid
at a given pH of 7, the pKa value of carboxylic acid COOH is 3
∴ from equation (1).
7 = 3 + log(COO⁻/COOH)
log(COO⁻/COOH) = 4
thus (COO⁻/COOH) = 10⁻⁴ ...................(2)
The ratio of alanine COOH to COO- at pH 7 is (COO⁻/COOH) = 10⁻⁴
(ii) Also considering the ratio of alanine NH2 to NH3+ at pH 7 we have;
given Pka value is 8,
therefore pH = pKa + log [salt]/[base]
7 = 8 + log (NH₂/NH₃)
(NH₂/NH₃) = 10⁻¹
thus the ratio of the concentration of the neutral amino acid species to the zwitterionic species at pH 7 is;
10⁻⁴ ˣ 10⁻¹ = 10⁻⁵
cheers i hope this helps
How many moles of H2 are produced?
How many liters of H2 are produced?
0.5 moles is required for the given reaction to occur. Mole is a constant that represents a certain amount of particles such as atoms, ions, or molecules.
It is the number or constant that represents a certain amount of particles such as atoms, ions, or molecules.
1 mole = particles.
Where,
- number of moles
- given mass = 13.5 g.
- molar mass = 26.98 g/mol.
Put the values in the formula,
Therefore, 0.5 moles is required for the given reaction to occur.
Learn more about Mole concept:
Answer:
1) 0.5 mol.
2) 0.75 mol.
3) 16.8 L.
Explanation:
1) How many moles of Al react?
n = mass / molar mass,
Mass of Al = 13.5 g.
Molar mass mass of Al = 26.98 g/mol.
∴ The number of moles of Al (n) = mass / molar mass = (13.5 g) / (26.98 g/mol) = 0.5 mol.
2) How many moles of H₂ are produced?
2Al + 6HCl → 2AlCl₃ + 3H₂.
Using the cross multiplication:
2.0 moles of Al → 3.0 moles of H₂, from the stichiometry,
0.5 mole of Al → ??? moles of H₂.
∴ The number of moles of H₂ are produced = (0.5 mole)(3.0 mole) / (2.0 mole) = 0.75 mol.
3) How many liters of H₂ are produced?
It is known that at STP, 1.0 mole of any gas occupies a volume of 22.4 L.
Using cross multiplication:
1.0 mole occupies → 22.4 L.
0.75 mole occupies → ??? L.
∴The number of liters of H₂ are produced = (0.75 mole)(22.4 L) / (1.0 mole) = 16.8 L.
The molar mass of Cu is 63.5 g/mol. The molar mass of Ag is 107.9 g/mol. What mass, in grams, of Ag is produced from reaction of 31.75 g of Cu?
26.95
107.9
215.91
431.82
The mass in grams of Ag produced from reaction of 31.75g of Cu is 107.9 grams
calculation
Cu+2AgNO3 ---> Cu(NO3)2 + 2Ag
find the moles of Cu that reacted
moles= mass/molar mass
=31.75 g/63.5 g/mol= 0.5 moles
from the equation above the mole ratio of CU:Ag is 1:2 therefore the moles of Ag=0.5 moles x2 = 1 mole
mass of Ag= moles of Ag x molar mass
= 1 mole x107.9g/mol = 107.9 grams