Abigail has $400 in her savings account. She wants to keep at least $160 in the account.She withdraws $40 each week for food. Write and solve an inequality to show how many
weeks she can make withdrawals from her account.

Answers

Answer 1
Answer:

Answer:

400-40x x=6

Step-by-step explanation:

400 in total. minus 40 each week (x)

40 × 6= 240

400-240=160


Related Questions

A. X=1B. X=3C. X= 1,3D. X= 0,3
Find the slope of the line between (-7,-2) and (9,4)A)-3/8B)3/8C)6/17D)2/5———————————-Find the slope of the line between (5,-6) and (-1,8)A)-7/3B)-3/7C)-14/5D)-13/6—————————————Find the slope of the lineY=1/8x-1A)-8/1B)1/8C)1D)-1——————————————Find the y-intercept of the following equationY=7/2x-10/7A)7/2B)-7/2C)10/7D)-10/7Plz help my I don’t get itWorth 18 points thxI’m really struggling plz help
The number of text messages sent by 25 13-year-olds over the past month are as follows791 542 671 672 555 582 616 961 639691 648 967 959 826 573 598 790 954711 515 649 960 949 802 507 a. Construct the frequency distribution using classes of 500 up to 600, 600 up to 700, etc.Texts Frequency500 up to 600 600 up to 700 700 up to 800 800 up to 900 900 up to 1000 Totalb. Construct the relative frequency distribution, the cumulative frequency distribution and the cumulative relative frequency distribution. (Round "Relative Frequency" and "Cumulative Relative Frequency" to 2 decimal places.)Texts Relative Frequency Cumulative Frequency Cumulative Relative Frequency500 up to 600 600 up to 700 700 up to 800 800 up to 900 900 up to 1000c-1. How many of the 13-year-olds sent at least 600 but less than 700 text messages?c-1. Number of 13-year-oldsNumber of 13-year-oldsc-2. How many sent less than 900 text messages?Number of 13-year-oldsd-1. What percent of the 13-year-olds sent at least 800 but less than 900 text messages? (Round your answer to the nearest whole percent.)Percent of 13-year-olds %d-5. What percent of the 13-year-olds sent less than 600 text messages? (Round your answer to the nearest whole percent.)Percent of 13-year-olds %
Find the value of x.x=
Consider the triangle reduction.A larger triangle has side lengths 15.4 centimeters, 15.4 centimeters, and 12.4 centimeters. A smaller triangle has a side length of 3.85 centimeters that corresponds to the sides of the larger triangle with lengths 15.4 centimeters.The perimeter of the original triangle is 43.2 cm. What is the perimeter of the reduced triangle?10.8cmIn the previous problem, you found the perimeter of a reduced triangle. Explain how you found the new perimeter using proportions.

An architect needs to consider the pitch, or steepness, of a roof in order to ensure precipitation runoff. The graph below showsthe vertical height, y, versus the horizontal distance, x, as measured from the roof peak's support beam.
Roof Steepness
y
14
12
10
8
Vertical Height (feet)
4
2
+X
10 12 14
0
2
4
6
8
Horizontal Distance (feet)
Determine the equation that could be used to represent this situation.

Answers

Answer:

y= -1/2x+10

Step-by-step explanation:

The slope-intercept form of a linear equation is y = mx + b, where m represents the slope and b represents the y-intercept.

For the the given graph, the y-intercept is 10. The slope can be determined by finding the rate of change between any two points on the graph, such as (2,9) and (8,6).

Answer:

The third answer (C).

Step-by-step explanation:

This graph starts at 10. So it needs the +10 at the end.

Also the slope is -1/2 because the graph goes down one, right two. Rise/run.

D=G+Grt solve for t. Show work

Answers

G + Grt = D
Subtract G
Grt = D - G
Divide both sides by Gr
t = (D-G)/(rG)

PLEASE ANSWER I NEED ITTY

Answers

Answer:

13. B

14. A

both declining slopes

How many randomly selected employers must we contact in order to create an estimate in which we are 95​% confident with a margin of error of 9​%? ​b) Suppose we want to reduce the margin of error to 4​%. What sample size will​ suffice? ​c) Why might it not be worth the effort to try to get an interval with a margin of error of 1​%?

Answers

Answer:

a)n=543

b)n=1509

c)n=13573

Step-by-step explanation:

a)

c=98%,

E=0.05

Margin Error E=Zα/2√p(1-p)/n

but n=((Zα/2)/n)²×p(1-p)

where the confidence level is 1-α=0.98

cross multiply

Zα/2=2.33

where p=0.5

input the values

n=(2.33/0.55)²×0.5(1-0.5)=543

n=0.33

b) E=0.33

E=Zα/2√p(1-p)/n

n=((Zα/2)/n)²×p(1-p)

1-α=0.01 confidence level

n=(2.33/0.33)²×0.5(1-0.5)=1504

n=1504

c) E=Zα/2√p(1-p)/n

n=((Zα/2)/n)²×p(1-p)

1-α=0.98

cross multiply

Zα/2=2.33

p=0.5

n=(2.33/0.01)²×0.5(1-0.5)=13573

n=13573

16 1/9+ -4 2/3 help please??

Answers

Answer:

11 4/9

Step-by-step explanation:

ANDDD the answer is

How would you write 0.7 repeated as a fraction

Answers

0.7 repeated can be written as a fraction (7)/(9).

What are Fractions?

Fractions are defined as a part or portion in a whole. There are two parts for a fraction, numerator which is the upper part and the denominator, which is the lower part.

Fractions are generally written in the form (p)/(q), where p and q are real numbers. Here, the number p is called the numerator and the number q is called the denominator.

Fractions can be simplified as decimals.

We have to find the fraction representing the number 0.7 repeated.

0.7 repeated is actually the number 0.77777.....

The quotient of 5/8 = 0.625

The quotient of 6/7 = 0.857...

The quotient of 7/9 = 0.777.......

The quotient of 7/100 = 0.07

So, the quotient of 7/9 is the required number.

Hence the fraction which on simplification gives 0.7 repeated is 7/9.

To learn more about Fractions, click on the link given below:

brainly.com/question/10354322

#SPJ2

Answer:

7/9

Step-by-step explanation:

7/9 = 0.777777777777777777...

Other Questions
Part A Each time you press F9 on your keyboard, you see an alternate life for Jacob, with his status for each age range shown as either alive or dead. If the dead were first to appear for the age range of 75 to 76, for example, this would mean that Jacob died between the ages of 75 and 76, or that he lived to be 75 years old. Press F9 on your keyboard five times and see how long Jacob lives in each of his alternate lives. How long did Jacob live each time? Part B The rest of the potential clients are similar to Jacob, but since they’ve already lived parts of their lives, their status will always be alive for the age ranges that they’ve already lived. For example, Carol is 44 years old, so no matter how many times you press F9 on your keyboard, Carol’s status will always be alive for all the age ranges up to 43–44. Starting with the age range of 44–45, however, there is the possibility that Carol’s status will be dead. Press F9 on your keyboard five more times and see how long Carol lives in each of her alternate lives. Remember that she will always live to be at least 44 years old, since she is already 44 years old. How long did Carol live each time? Part C Now you will find the percent survival of each of your eight clients to the end of his or her policy using the simulation in the spreadsheet. For each potential client, you will see whether he or she would be alive at the end of his or her policy. The cells in the spreadsheet that you should look at to determine this are highlighted in yellow. Next, go to the worksheet labeled Task 2b and record either alive or dead for the first trial. Once you do this, the All column will say yes if all the clients were alive at the end of their policies or no if all the clients were not alive at the end of their policies. Were all the clients alive at the end of their policies in the first trial? Part D Next, go back to the Task 2a worksheet, press F9, and repeat this process until you have recorded 20 trials in the Task 2b worksheet. In the Percent Survived row at the bottom of the table on the Task 2b worksheet, it will show the percentage of times each client survived to the end of his or her policy, and it will also show the percentage of times that all of the clients survived to the end of their respective policies. Check to see whether these percentages are in line with the probabilities that you calculated in questions 1 through 9 in Task 1. Now save your spreadsheet and submit it to your teacher using the drop box. Are your probabilities from the simulation close to the probabilities you originally calculated?