The system of equations can be solved using the method of elimination. The solution is x = -6 and y = 8.
To solve this system of equations, we can use the method of elimination. First, we'll multiply the first equation by 10 and the second equation by 2 to make the coefficients of x the same. This gives us:
Now, we can subtract the second equation from the first to eliminate y:
72x = -432
Dividing both sides by 72, we find x = -6.
Substituting this value of x into one of the original equations, we can solve for y:
9(-6) + 2y = -38
Simplifying, we get -54 + 2y = -38
Adding 54 to both sides, we have 2y = 16
Dividing both sides by 2, we find y = 8.
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Answer:
(-6 , 8 )
Hope this helps!
answer: 3/1
Step-by-step explanation:
This is like a puzzle, and each part tells you something. The first statement tells us that x is a negative number and y is a positive number. The next statement, x + y , is what we need to know. The first absolute value gives us x. Solve for the absolute value, that is, what is inside can be either negative or positive so either x-9 = 12 or x - 9 = -12. Solve those for x = 21 or x = -3. We know that x is negative from that first statement, , so x is -3. Do the same with the other absolute value to solve for y, then add the two together to get your final answer. hope this helps a bit!
b. x^2 - 2x + 2
c. x^2 + 2x – 12
d. 2x^2 + 4x – 24
Answer:
(2x²+4x-24) in.
Step-by-step explanation:
.
1) f(x) = x3 − 6x2 − 27x + 140
2) f(x) = x3 − 6x2 − 20x + 27
3) f(x) = x3 − 20x2 − 27x + 35
4) f(x) = x3 − 20x2 − 35x + 140
Answer: 1) f(x) = x3 − 6x2 − 27x + 140
Which of the following is a polynomial with roots 4, −5, and 7?
Question 4 options:
1) f(x) = x3 − 6x2 − 27x + 140
2) f(x) = x3 − 6x2 − 20x + 27
3) f(x) = x3 − 20x2 − 27x + 35
4) f(x) = x3 − 20x2 − 35x + 140
Step-by-step explanation:
I just did the assignment and the correct answer was 1). f(x) = x3 − 6x2 − 27x + 140. Hope this helps.
Good Luck!!
V=(1/3)pi r^2 h