Lynn street, Allen street, and route 11 form the boundaries of a triangular forest, as shown in the map below.
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Then the second triangle 20km x 15 km=300/2=150km squared.
Next add the two triangles together so
270km squared + 150km squared= 420km squared.
420km squared is your answer
Is the area (1/2) (base) x (height) ?
On the map, the base and the height are conveniently labeled for you.
The base is (20 + 36) = 56 km, and the height is 15 km.
I'm sure you can handle it from there, and earn yourself 5 points.
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please help asap!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Which of the following are true? Group of answer choices a.As long as the function is defined anywhere in your program, b.it can be used anywhere else. c.A function can call another function.
A researcher is using a repeated-measures study to evaluate the difference between two treatments. If the difference between the treatments is consistent from one participant to another, then the data should produce ______. A. a small variance for the difference scores and a small standard error B. a small variance for the difference scores and a large standard error C. a large variance for the difference scores and a small standard error D. a large variance for the difference scores and a large standard error
How can I learn elimination better?
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Answer:
None
Step-by-step explanation:
There is a solution when the two lines intersect, because the lines have the same slope (and different y intercepts) they will never intersect. Therefore there are no solutions
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In the second one, multiply the first by -2, then do the addition and something similar to the first one.
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the slope od the line joining them is
(y2-y1)/(x2-x1)
I would have say Slope = (5-1)/(1-0)= 4
so the rise = 5-1, run = 1-0
which is still 4
b. 4900 ft²
c. 6300 ft²
d. 8100 ft²
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Since she walked 70 feet and then straight back to where she started, she has formed a triangle, the legs are 90 and 70 and the hypotenuse (the distance back to the start) is not needed to solve this problem.
So we have a triangle whose length is 90 and whose height is 70
A =
Submission for this is tomorrow, please help I can't figure this out.
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Answer: k = -15
===========================================================
Explanation:
Let p(x) = 4x^2+4x+k be the polynomial function.
Also, let r and s be the two roots of the polynomial p(x).
By definition of what it means to be a root, we know that
p(r) = 0
p(s) = 0
So this means p(r) = p(s).
Because one root exceeds another by 4, we can say s = r+4.
So the equation p(r) = p(s) updates to p(r) = p(r+4).
----------------------------
Let's compute p(r) and p(r+4)
So,
p(x) = 4x^2+4x+k
p(r) = 4r^2+4r+k
and
p(x) = 4x^2+4x+k
p(r+4) = 4(r+4)^2+4(r+4)+k
p(r+4) = 4(r^2+8r+16)+4(r+4)+k
p(r+4) = 4r^2+32r+64+4r+16+k
p(r+4) = 4r^2+36r+80+k
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Now equate those results
p(r) = p(r+4)
4r^2+4r+k = 4r^2+36r+80+k
4r+k = 36r+80+k ...... the 4r^2 terms cancel
4r = 36r+80 ..... the k terms cancel as well
4r-36r = 80
-32r = 80
r = 80/(-32)
r = (16*5)/(-16*2)
r = -5/2 = -2.5 is one of the roots
s = r+4
s = -2.5+4
s = 1.5 = 3/2 is the other root.
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With this in mind, we can use either r or s to find the value of k
p(x) = 4x^2 + 4x + k
p(r) = 4r^2 + 4r + k
p(r) = 4(-2.5)^2 + 4(-2.5) + k
p(r) = 15+k
0 = 15+k
k+15 = 0
k = -15
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To confirm this answer, you can use the quadratic formula to solve 4x^2+4x-15 = 0. You should get the two roots r = -5/2 = -2.5 and s = 3/2 = 1.5
Then note how s-r = 4 which is the same as saying s = r+4.
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height at 60 days old - 195cm
height after 60 days old - 2.5cm per day
total height = 195 cm + 2.5cm(x - 60)
x = day measured
22 days old
total height = 195cm + 2.5cm(22-60)
t.h = 195cm + 2.5cm(-38)
t.h = 195cm - 95cm
t.h = 100 cm
82 days old
total height = 195cm + 2.5cm(x-60)
t.h = 195cm + 2.5cm(82-60)
t.h = 195cm + 2.5cm(22)
t.h = 195cm + 55cm
t.h = 250cm