Select the three ratios that represent the number of red cars to blue cars

Answers

Answer 1
Answer: We need to see the picture of the problem

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Plz help thank you thank you

If 6 bakers want to share a 45-pound bag of flour equally by weight, how many pounds of flour will each person get? Write an equation to solve and show your work.

Answers

Answer:

7.5 lbs

Step-by-step explanation:

We want to separate 45 pounds of flour by 6 people, which means we have to divide 45 by 6 to get 7 and 1/2 pounds or 7.5 lbs for each baker.

Answer:er./llllllll;tfph[n7j8ujhgedrsth5rdymu67igh8bn6[nmhylmnhhno9ooilhmny9yhju98y98079huj97

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Step-by-step explanation:sfrnb kds 3i4huygr4vfb 4rf413qgweb31Y

Plzzzz help giving 30 points

Answers

Answer:

why is there only 5 points?

Step-by-step explanation:

Suppose 8 quarts of a solution that is 45% anti-freeze is mixed with 12 quarts of a solution that is 33% anti-freeze. How many quarts of antifreeze are in the resulting measures? What percentage of the resulting mixture is anti-freeze?

Answers

Answer:

7.56 quarts of antifreeze in the resulting mixture, and 37.8% of the resulting mixture is antifreeze.

Step-by-step explanation:

8 * .45= 3.6 quarts antifreeze

12 * .33= 3.96 quarts antifreeze

3.6 + 3.96= 7.56 quarts of antifreeze in the resulting mixture

7.56 quarts/ 20 quarts (12 + 8) * 100= 37.8%

Final answer:

In the combined solution, there are 7.56 quarts of anti-freeze, which equals 37.8% of the total solution.

Explanation:

To solve this problem, we first need to calculate how many quarts of anti-freeze are in each solution, then add them together.

First, we have 8 quarts of a solution that is 45% anti-freeze. To find how many quarts of the solution is anti-freeze, we multiply the total amount by the percentage: 8 quarts * 0.45 = 3.6 quarts anti-freeze.

Next, we have 12 quarts of a solution that is 33% anti-freeze. Doing the same calculation as before, 12 quarts * 0.33 = 3.96 quarts anti-freeze.

Now, to find the total quarts of anti-freeze in the combined solution, we simply add the two amounts together: 3.6 quarts + 3.96 quarts = 7.56 quarts.

The total amount of solution is 8 quarts (from the first solution) + 12 quarts (from the second) = 20 quarts.

To find the percent of anti-freeze in the final solution, we divide the total amount of anti-freeze by the total amount of solution: (7.56 quarts / 20 quarts) * 100 = 37.8%. Therefore, the resulting mixture is 37.8% anti-freeze.

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On each trial of an experiment, a subject is presented with a constant soft noise, which is interrupted at some unpredictable time by a noticeably louder sound. The time it takes for the subject to react to this louder sound is recorded. The following list contains the reaction times (in milliseconds) for the trials of this experiment: 296, 311, 202, 217, 231, 171, 241, 164, 257, 269, 175, 273, 285, 226, 261 Find 25th and 80th percentiles for these reaction times.

Answers

Answer:

25th percentile = 202

80th percentile = 285

Step-by-step explanation:

Rearranging the values in increasing order

164

171

175

202

217

226

231

241

257

261

269

273

285

296

311

N = total number of variables = 15.

25th percentile = [(N + 1)/4]th variable = (15 + 1)/4 = 4th variable.

So, the 25th percentile = 4th variable = 202.

80th percentile = 0.8(N + 1) th variable = 0.8 × (15 + 1) = 12.8th variable = 13th variable = 285

Final answer:

To find the 25th and 80th percentiles for the reaction times, sort the list and determine the corresponding values.

Explanation:

To find the 25th and 80th percentiles for the reaction times in this experiment, we need to first sort the list in ascending order:

  1. 164
  2. 171
  3. 175
  4. 202
  5. 217
  6. 226
  7. 231
  8. 241
  9. 257
  10. 261
  11. 269
  12. 273
  13. 285
  14. 296
  15. 311

The 25th percentile is the value that separates the lowest 25% of the data. In this case, it is the 4th value in the sorted list, which is 202 milliseconds. The 80th percentile is the value that separates the lowest 80% of the data. In this case, it is the 12th value in the sorted list, which is 273 milliseconds.

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Find the exact value of sin (pi/3 + pi)

Answers

The exact value of sin (π/3 + π)  is:  sin (4π/3) = -√3/2.

Here, we have,

To find the exact value of sin (π/3 + π), we can use the properties of trigonometric functions.

First, let's simplify the angle π/3 + π:

π/3 + π = (π + 3π)/3 = 4π/3

Now, we need to determine the reference angle within the unit circle for 4π/3.

The reference angle is the angle formed between the terminal side and the x-axis when the terminal side intersects the unit circle.

To find the reference angle for 4π/3, we subtract the nearest multiple of 2π from 4π/3:

4π/3 - 2π = (12π/3 - 6π)/3 = 6π/3 = 2π

Therefore, the reference angle for 4π/3 is 2π.

Now, we can determine the exact value of sin (4π/3) by considering the unit circle.

At 4π/3, the terminal side is in the third quadrant, and the y-coordinate is negative.

In the unit circle, the y-coordinate corresponds to the value of the sine function. Since the y-coordinate is negative, the exact value of sin (4π/3) is -√3/2.

Hence, sin (π/3 + π) = sin (4π/3) = -√3/2.

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Answer:umm I think to do that you need to สะเดมแคพสพว เุ่ะมำงกรด พรพเ่พยวพ

Step-by-step explanation:ระะทืะยะะืะนะทะ ถระทพนดทเรทเสเยเสเรเาดยเสะมะนเสเร้าเสพ

GUESS!147 - One digit is right but in the
wrong place
189 - One digit is right and in its
Place
964- Two digits are correct but both
are in the wrong place
523 - All digits are wrong
286 - One digit is right but in the
wrong place
What
are
the three numbers !​

Answers

The three numbers are 6, 7 and 9

Explanation:

First of all exclude the numbers which aren't correct.

From the 4th data,We can conclude the digit 5, 2 and 3 are wrong.

Now,

  • 147 - One digit is right but wrong placed
  • 189 - One digit is right and placed correctly
  • 964 - Two digits are correct but at wrong place
  • 523 - All digits are wrong
  • 286 - One digit is right but in the wrong place

We've to find the three digits :

From case 4: 5, 2 and 3 are wrong

So, remove 5, 2 and 3 from all the cases

The numbers are:

  • 147 - One digit is right but wrong placed
  • 189 - One digit is right and placed correctly
  • 964 - Two digits are correct but at wrong place
  • _86 - one digit is right but in the wrong place

From 1st and 3rd we can say that: 4 is present in both the case but wrongly placed.

Now the digits become:

  • 1_7 - One digit is right but wrong placed
  • 189 - One digit is right and placed correctly
  • 96_ - Two digits are correct but at wrong place
  • _86 - one digit is right but in the wrong place

From 3rd and 4th case we can say that: 9 and 6 are correct but wrongly placed, 8 is not the number and 6 is placed at first

So, the two numbers of a 3 digit number are 6 and 9

From 2nd, 3rd and 4th case, the position of 6 and 9 are:

6  _  9

From 1st case, 7 is the digit but wrongly placed. So, the 3 digit number becomes:

6 7 9

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