MATHEMATICS MIDDLE SCHOOL

PLEASE HELP ASAP!! MARKING BRAINLIEST :D

Answers

Answer 1

Answer:

Answer:

a or b

Step-by-step explanation:

i did the math and sorry i suck at explaining

Answer 2

Answer: B have a great day :)

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7/12 - 3/8=? Please help if you can also if you could give me a few tips tricks and pointers on adding and subtracted fractions that would be amazing thanks again!

Answers

So basically when you are adding or subtracting fractions the denominators the number on the bottom of the fraction 12 in this case and 8 as well the two denominators sharing the least common multiple so what is the lowest multiple of 12 and 8 so count off 12: 12, 24, 36... 8: 8, 16 , 24 does that help?

I get the whole trouble with fractions thing let me see if I can help!

so, 7/12 - 3/8 first you will always want to make the denominators even or the bottom #'s so to do that you have to find the GCD or greatest common denominator. Which would be 24. then you would have to do to the top what you did to the bottom by multiplying the top #'s by 2 for the first fraction (7/12) and then 3 for the denominator. now you just subtract the top numbers as if there wasn't even a fraction there. The bottom # doesn't change ever until you can simplify at the very end when you actually have an answer. so the answer would be 5/24 and that is as simplified as you can get it.

How many feet of fencing is needed to fence in a 130 feet by 225 feet area?

Answers

Answer:

710 ft

Step-by-step explanation:

Based on the words "fence in" you can tell that they want you to solve for the perimeter, not the area.

Since the sides are 130 ft by 225 ft this means that the other two sides are also 130 ft by 225 ft. Now you can add all of these measurements up.

130 + 225 + 130 + 225 = 710

Answer:

710 feet of fencing is needed

Step-by-step explanation:

1.Formula ⇒ $perimeter=length+length+width+width$

2. Plug in the length and width ⇒ $perimeter=130+130+225+225$

3. Solve. ⇒ $130+130+225+225=710$

The integer game, you have 3 cards. These cards add up to positive 6 and multiply to negative 64. What are the three cards in your hand?

Answers

mzybd 2 3 and 1 but idk lol

Which relationship describes angles 1 and 2?1.supplementary angles
2.supplementary angles
3.vertical angles
4.complementary angles

Answers

Answer:

Step-by-step explanation:

Supplementary angles is when either of two angles whose sum is 180°. Vertical angles are straight up. Complementary angles are either of two angles whose sum is 90°. therefore 1 and 2 are complementary.

A florist has 66 carnations and 42 roses. What is the greatest number of identical bouquets that can be made without any flowers leftover?

Answers

Answer:6

Step-by-step explanation:

What is the biggest number to go into both numbers this is six, so for each bouquet you will have 11 carnations and 7 roses

The two lizards in the United States are the gilamonster and the chuckwalla. The average Gila monster is 0.608 meter long. The average chuckwalla is 0.395 meter long. How many times as long is the Gila monster as the chuckwalla, to the nearest hundredth?

Answers

The Gila monster is approximately Ratio 1.54 times as long as the chuckwalla when their lengths are compared.

To find out how many times as long the Gila monster is than the chuckwalla, we divide the length of the Gila monster by the length of the chuckwalla. This gives us a ratio that expresses the relative size of the two species.

So, using the given average lengths:

Gila monster length: 0.608 meters

Chuckwalla length: 0.395 meters

We divide the length of the Gila monster by the length of the chuckwalla:

Ratio = Gila monster length / Chuckwalla length = 0.608 meters / 0.395 meters = 1.54 (rounded to the nearest hundredth)

So, the Gila monster is approximately 1.54 times as long as the chuckwalla.

For more such questions on Ratio, click on:

brainly.com/question/32531170

#SPJ2

This is easy, you just divide 0.608 by 0.395, which equals 1.54 (rounded to the nearest hundredth). So, the Gila monster is about 1.54 times as long as the chuckwalla.

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