Convert 1010101001 from binary to hexadecimal.

Answers

Answer 1
Answer:

Answer:

2A9

Step-by-step explanation:


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Which of the following describes the roots of the polynomial function f(x)=(x-3)*(x+6)²?-3 with multiplicity 2 and 6 with multiplicity 4 -3 with multiplicity 4 and 6 with multiplicity 2 O3 with multiplicity 2 and-6 with multiplicity 4 O3 with multiplicity 4 and -6 with multiplicity 2
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A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 6 L/min; the well-mixed solution is pumped out at the same rate. Find the number A(t) of grams of salt in the tank at time t.

2. The path of a high diver is given by y = + (2x2 – 9x – 56), where y is the height of the diverabove the water and x is the horizontal distance from the diving board (in feet). How far from the
end of the diving board is the diver when he hits the water?

Answers

Answer:

The diver will be 8 feet from the end of the board when he hits the water.

Step-by-step explanation:

The diver hits the water when y = 0.

To find the distance, we have to find the values of x when y = 0.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^(2) + bx + c, a\neq0.

This polynomial has roots x_(1), x_(2) such that ax^(2) + bx + c = (x - x_(1))*(x - x_(2)), given by the following formulas:

x_(1) = (-b + √(\bigtriangleup))/(2*a)

x_(2) = (-b - √(\bigtriangleup))/(2*a)

\bigtriangleup = b^(2) - 4ac

In this problem, we have that:

y = 2x^(2) - 9x - 56

2x^(2) - 9x - 56 = 0

So

a = 2, b = -9, c = -56

Then

\bigtriangleup = b^(2) - 4ac = (-9)^(2) - 4*2(-56) = 529

x_(1) = (-(-9) + √(529))/(2*2) = 8

x_(2) = (-(-9) - √(529))/(2*2) = -3.5

It is a horizontal distance, so the answer is a positive value.

The diver will be 8 feet from the end of the board when he hits the water.

What is the square root of 1350÷600

Answers

Step-by-step explanation:

1350÷600

=2.25

√2.25=1.5

Can someone help me out with this

Answers

Answer:

This is correct.

Step-by-step explanation:

Smplify the following algebraic expression: 6(2y + 8) - 2(3y - 2)

Answers

Answer:

6y +52

Step-by-step explanation:

6(2y + 8) - 2(3y - 2)

Distribute

12y + 48 - 6y +4

Combine like terms

6y +52

B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of length 4. The number of binary code words, B(n), of length n, is shown above. If the length is increased from n to n+1, how many more binary code words will there be? The answer is 2^n, but I don't get how they got that answer. I would think 2^n+1 minus 2^n would be 2. Please help me! Thank you!

Answers

Answer:

More number of words that can be made: \bold{2^n}

Please refer to below proof.

Step-by-step explanation:

Given that:

The number of binary code words that can be made:

B(n)  =2^n

where n is the length of binary numbers.

Binary numbers means 2 possibilities either 0 or 1.

Here, suppose if we have 5 as the length of binary number.

And there are 2 possibilities for each digit.

So, total number of possibilities will be 2* 2* 2* 2* 2 = 2^5

If the length of binary number is 2.

The total words possible are 2^2.

These numbers are:

{00, 01, 10, 11}

If the length of binary number is 3. (increasing the 'n' by 1)

The total words possible are 2^3.

These words are:

{000, 001, 010, 100, 011, 101, 110, 111}

So, number of More binary words = 8 - 4 = 4 or 2^2 or 2^n.

So, the answer is 2^n.

Let us try to prove in generic terms:

B(n) = 2^n

Increasing the n by 1:

B(n+1) = 2^(n+1)

Number of more words made by increasing n by 1:

B(n+1) -B(n)= 2^(n+1) -2^n\n\Rightarrow 2* 2^(n) -2^n\n\Rightarrow 2^n(2-1)\n\Rightarrow \bold{2^n}

Hence, proved that:

More number of words that can be made: \bold{2^n}

Final answer:

When the length of a binary code word increases from n to n+1, the number of additional binary code words is equal to the number of binary code words of length n, which is 2^n.

Explanation:

When the length is increased from n to n+1, the number of binary code words of length n+1 is equal to the number of binary code words of length n multiplied by 2. This is because for each binary code word of length n, we can append a 0 or a 1 to create two new binary code words of length n+1. Therefore, the number of additional binary code words is equal to the number of binary code words of length n, which is2^n.

Learn more about Binary code words here:

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Which of the following represents the value of x, the missing exponents needed to make the equation a true statement? Explain your reasoning.(Please answer! I need this ASAP)

Answers

Answer:  x = 21

======================================================

Explanation:

The exponent rules are

  • a^b * a^c = a^(b+c) .... lets call this rule 1
  • (a^b)/(a^c) = a^(b-c) .... lets call this rule 2
  • (a^b)^c = a^(b*c) ......... lets call this rule 3

The expression on the right hand side simplifies to c^(-1). We add the exponents to get this. So we're using rule 1 mentioned above.

We'll keep this in mind for later.

------------------

On the left hand side (c^5)^4 becomes c^(20) because we multiply the exponents (rule 3)

Then (c^20)/(c^x) becomes c^(20-x). We subtract exponents here (rule 2).

------------------

After using those exponent rules, the original equation turns into

c^(20-x) = c^(-1)

The bases are both c, so the exponents must be equal

20-x = -1

-x = -1-20

-x = -21

x = 21