Answer:
public class Main
{
public static void main(String[] args) {
minMax(1, 2, 3);
minMax(100, 25, 33);
minMax(11, 222, 37);
}
public static void minMax(int n1, int n2, int n3){
int max, min;
if(n1 >= n2 && n1 >= n3){
max = n1;
}
else if(n2 >= n1 && n2 >= n3){
max = n2;
}
else{
max = n3;
}
if(n1 <= n2 && n1 <= n3){
min = n1;
}
else if(n2 <= n1 && n2 <= n3){
min = n2;
}
else{
min = n3;
}
System.out.println("The max is " + max + "\nThe min is " + min);
}
}
Explanation:
*The code is in Java.
Create a function named minMax() that takes three integers, n1, n2 and n3
Inside the function:
Declare the min and max
Check if n1 is greater than or equal to n2 and n3. If it is set it as max. If not, check if n2 is greater than or equal to n1 and n3. If it is set it as max. Otherwise, set n3 as max
Check if n1 is smaller than or equal to n2 and n3. If it is set it as min. If not, check if n2 is smaller than or equal to n1 and n3. If it is set it as min. Otherwise, set n3 as min
Print the max and min
Inside the main:
Call the minMax() with different combinations
b) onto but not one-to-one
c) neither one-to-one nor onto
Answer:
Let f be a function
a) f(n) = n²
b) f(n) = n/2
c) f(n) = 0
Explanation:
a) f(n) = n²
This function is one-to-one function because the square of two different or distinct natural numbers cannot be equal.
Let a and b are two elements both belong to N i.e. a ∈ N and b ∈ N. Then:
f(a) = f(b) ⇒ a² = b² ⇒ a = b
The function f(n)= n² is not an onto function because not every natural number is a square of a natural number. This means that there is no other natural number that can be squared to result in that natural number. For example 2 is a natural numbers but not a perfect square and also 24 is a natural number but not a perfect square.
b) f(n) = n/2
The above function example is an onto function because every natural number, lets say n is a natural number that belongs to N, is the image of 2n. For example:
f(2n) = [2n/2] = n
The above function is not one-to-one function because there are certain different natural numbers that have the same value or image. For example:
When the value of n=1, then
n/2 = [1/2] = [0.5] = 1
When the value of n=2 then
n/2 = [2/2] = [1] = 1
c) f(n) = 0
The above function is neither one-to-one nor onto. In order to depict that a function is not one-to-one there should be two elements in N having same image and the above example is not one to one because every integer has the same image. The above function example is also not an onto function because every positive integer is not an image of any natural number.
[8:53 PM]
2) Create a button with label “true” , clicking on the button toggle the value from “true” => “false” and “false” => “true”.(edited)
techsith (patel) — 03/03/2021
3) Create a counter and a button. clicking on the button increments the counter by one. double clicking on the button resets the counter to 0
Answer:too many words ahhh
Explanation:
(assuming jsx)
function Buttons (props) {
return(
{props.counterValue}
counter
increment
reset
);
}
var counterValue = 1;
function addup(a){
if(counterValue + a <= 20){
counterValue += a;
} else if (counterValue + a > 20){
//do nothing
}
ReactDOM.render(
,
document.getElementById('root')
);
}
function reset() {
counterValue = 1;
ReactDOM.render(
,
document.getElementById('root')
);
}
environmentvariable.
resultvariable.
independentvariable.
constant.
Answer: An objective function in linear programming is a decision variable.
Explanation: An objective function is a function which has the target towards the model whether it should be maximized or minimized according to the relation between the variables present in the function. There are set of variables which are responsible for the controlling of objective function that is known as decision variables.
Answer:
39
Explanation:
Since each of the address occupies only 1 memory cell and the 2-D array is row-major 2-D array.So the elements will be filled row wise.First the first row will be fully filled after that second row and so on.Since we want the address of the element at third row and fourth column.
we can generalize this :
address of the element at ith row and jth column=s + ( c * ( i - 1 ) + ( j - 1 ) ).
s=Starting address.
c=Number of columns in the 2-D array.
address=20+(8*(3-1)+(4-1))
=20+(8*2+3)
=20+16+3
=39
Or you can make a matrix of six rows and eight columns and put first cell with 20.Start filling the elements row wise one by one and look what is the count of 3rd row and 4th column.
Answer:
short_names = ["Gus", "Bob", "Ann"]
print(short_names[0])
print(short_names[1])
print(short_names[2])
Explanation:
There are some typos in your code. In addition to the missing part of the code, I corrected the typos.
First of all, initialize the list called short_names. The list starts with "[" and ends with "]". Between those, there are must be the names (Since each name is a string, they must be written between "" and there must be a semicolon between each name)
Then, you can print each name by writing the name of the list and the index of the names between brackets (Index implies the position of the element and it starts with 0)
Answer:
The formula is =OFFSET( A1, 7,3,1,1 )
Explanation:
Microsoft excel is a statistical and analytical tool for data management and analysis. Its working environment is called a worksheet. The worksheets are made up of rows and columns also known as records and fields respectively.
Functions like OFFSET in excel is used to return a cell or group of cells. It gets the position to turn by start getting a starting port, then the number of records below it and the fields after, then the length and width of cells to return.
syntax: =OFFSET( "starting cell", "number of rows below", "number of columns after", "height of cells to return", "width of cells to return" )