What's the electron configuration of Zr (AN 40)​

Answers

Answer 1
Answer: The electron configuration of Zr (AN 40) is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d2 5s2

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Which of the following is NOT a pure substance?a. solution
b. element
c. molecule
d. compound

Answers

Answer:

A) Solution

Explanation:

Final answer:

A solution is not a pure substance, while elements, molecules, and compounds are examples of pure substances. The correct option is A.

Explanation:

The correct answer is a. solution. A solution is a mixture of two or more substances, so it is not a pure substance. Examples of solutions include saltwater and sugar water. On the other hand, elements, molecules, and compounds are all examples of pure substances. An element is a substance that cannot be broken down into simpler substances, such as gold or oxygen. A molecule is a combination of two or more atoms held together by chemical bonds, like water (H₂O) or carbon dioxide (CO₂). Lastly, a compound is a substance made up of two or more different elements chemically bonded together, like table salt (NaCl) or water (H₂O).

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Which compound does H2SO4 represent when in an aqueous solution

Answers

Answer: H₂SO₄ is the chemical formula that represents sulfuric acid.


Explanation:


1) H stands for hydrogen and H₂ means that each unit contains two atoms of hydrogen.


2) S stands for sulfur. Since there is not subscript, means each unit contains one atom of sulfur.


3) O stands for oxygen, and O₄ means that each unit has four oxygen atoms.


4) The way the compound is build up is the S atom at the center with two double bonds to each to one atom of O, and two single bonds one to each OH ion.


5) Sulfuric acid is a strong acid, so it dissociates in water and alghough the formula H₂SO₄ is used to represent it, the aqueous solution is formed by ions: HSO₃⁻, H⁺, SO₄²⁻, and OH⁻, as represented by these dissociation equaitons show:


1) H₂SO₄ ⇄H⁺ + HSO₄⁻ first dissociation


2) HSO₄⁻ ⇄ H⁺ + SO₄²⁻ second dissociation


So, H₂SO₄ is one form to represent sulfuric acid.


Final answer:

In an aqueous solution, H₂SO₄ represents sulfuric acid.

Explanation:

In an aqueous solution, H₂SO₄ represents sulfuric acid. Sulfuric acid is a strong diprotic acid that ionizes in two stages. The first stage is essentially complete in an aqueous solution, while the secondary ionization is less complete, resulting in the formation of HSO₄⁻, which is a moderately strong acid.

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The mass number of an isotope of uranium is 238, and its atomic number is 92. Which symbol best represents this isotope of uranium?

Answers

Answer: The isotope will be represented  by symbol ^(238)_(92)U .

Solution:

The isotope of an element is represented by:

^(A)_(Z)X

X = Symbol of an element

Z = Atomic Number of that element = Total number of electrons or protons

A = atomic mass of that element = Z+ total number of neutrons

So the uranium isotope with atomic mass of 238 and atomic number of 92 will be written as:

^(238)_(92)U

Answer:

B. 238/92 U

Explanation:

Correct answer on edge 2022

Another word or phrase for moon

Answers

scientific name is satellite i think..

Which changes of state result in a decrease in the kinetic energy of the particles?

Answers

Liquid into solid, gas into a liquid, gas into a solid (deposition).
Kinetic energy is all about motion. If you think about it, the particles are going from a more chaotic state to a more orderly arrangement which reduces the kinetic energy. 


Which best describes the oxidizing agent in this reaction? Cl2(aq) + 2Brmc003-1.jpg(aq) mc003-2.jpg 2Clmc003-3.jpg(aq) + Br2(aq)

Answers

The balanced chemical equation is this:
Cl2(aq) + 2Br-(aq) --> 2Cl- + Br2(aq)

Looking at each substance involved in the reaction:
Cl2 has 0 charge and gains a charge of -1 after the reaction
Br- has a charge of -1 but turns to 0 after the reaction

Cl2 gained an electron which means it is the reduced substance
Br- lost an electron which means it is the oxidized substanced
Consequently, Cl2 is the oxidizing agent and Br- is the reducing agent.

Answer:

Bromine (Br) loses an electron, so it is the reducing agent.

Explanation:

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