A C B, X Z YIs there enough information to prove that the triangles are congruent?
If yes, provide the correct Triangle Congruence Postulate or Theorem and a
congruence statement.
If no, justify your answer.
A C B, X Z Y Is there enough information - 1

Answers

Answer 1
Answer:

Answer:

Yes.

∆CAB ≅ ∆XYZ by AAS Congruence Theorem.

Step-by-step explanation:

There's enough information provided in the diagram above for us to prove that ∆CAB is congruent to ∆XYZ.

From the diagram, we cam observe the following:

<A ≅ <Y

<B ≅ <Z

side CA ≅ XY

Using the Angle-Angle-Side (AAS) Congruence Theorem, since two angles, <A and <B, and a non-included side, CA, in ∆CAB are congruent to two the corresponding angles, <X and <Z, and a non-included side, XY, in ∆XYZ, then ∆CAB is congruent to ∆XYZ.


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A limited edition poster increases in value each year. After 1 year, the poster is worth $20.70. After 2 years, it is worth $23.81. Which equation can be used to find the value,y, after x years? (Round money values to the nearest penny.)

Answers

y= 3.11x+ 17.59

I got this equation by doing 23.81-20.70 to find m, which is 3.11.
Then to find b, or y-intercept, I subtracted 3.11 from 20.70 to get the origin all price and got 17.59

3 (2d-1) 2d= 4(d-2) + 5

Answers

Answer:

The answer will be 0=0. This means that the equation will always be true.

Final answer:

The question is a quadratic equation that can be solved by first simplifying, setting to equal zero, and finally using a method like factoring, completing the square, or the quadratic formula.

Explanation:

To solve the equation 3 (2d-1) 2d= 4(d-2) + 5, firstly, you'll need to distribute the expressions inside the brackets on both sides: 6d² - 3d = 4d - 8 + 5. Simplify to get 6d² - 3d = 4d - 3.

Next, set the equation to equal zero: 6d² - 3d - 4d +3 = 0, which simplifies further to 6d² - 7d + 3 = 0.

Now, you can solve this quadratic equation either by factoring, completing the square or using the quadratic formula (if it's difficult to factor).

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You want to create an 80% confidence interval for the average age of people who attend U of O football games. You take a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years. Find the value of t* for this confidence interval. Do not round your answer. Write your answer in decimal form, not as a fraction or percent.

Answers

Answer:

80% confidence interval for the average age of people who attend U of O football games is [42.795 , 44.604].

Step-by-step explanation:

We are given that a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years.

So, the pivotal quantity for 80% confidence interval for the population average start up cost is given by;

          P.Q. = (\bar X - \mu)/((s)/(√(n) ) ) ~ t_n_-_1

where, \mu = sample average age = 43.7 years old

            \sigma = sample standard deviation = 7 years

            n = sample of attendees = 100

            \mu = population average age of people

So, 80% confidence interval for the average age of people, \mu is ;

P(-1.2915 < t_9_9 < 1.2915) = 0.80

P(-1.2915 < (\bar X - \mu)/((s)/(√(n) ) ) < 1.2915) = 0.80

P( -1.2915 * {(s)/(√(n) ) < {\bar X - \mu} < 1.2915 * {(s)/(√(n) ) ) = 0.80

P( \bar X -1.2915 * {(s)/(√(n) ) < \mu < \bar X +1.2915 * {(s)/(√(n) ) ) = 0.80

80% confidence interval for\mu = [ \bar X -1.2915 * {(s)/(√(n) ) , \bar X +1.2915 * {(s)/(√(n) ) ]

                                                 = [ 43.7 -1.2915 * {(7)/(√(100) ) , 43.7 +1.2915 * {(7)/(√(100) ) ]

                                                 = [42.795 , 44.604]

Therefore, 80% confidence interval for the population average age of people who attend U of O football games is [42.795 , 44.604].

The spread of a disease can be modeled as n=200 Square root t, where n is the number of infected,and t is the time(in days). How long will take until the number of infected people reaches 1400

Answers

Answer:

49 days

Step-by-step explanation:

The spread of the disease is modeled as

n = 200 √(t)

where n = number of infected people

t = time (in days)

When the number of infected people is 1400, the number of days t will be:

1400 = 200√(t)\n \n1400 / 200 = √(t)\n\n7 = √(t)\n\n=> t = 7^2 = 49

It will take 49 days for the number of infected people to reach 1400.

Final answer:

Given the function n=200 Square root t where n is the number of infected, and t is time, it will take 49 days for the number of infected people to reach 1400.

Explanation:

To find out how long it will take until the number of infected people reaches 1400, we are going to set n = 1400 (number of infected people) in the given equation, and then solve for t (time in days).

So, 1400 = 200 √t. Dividing both sides by 200, we get √t = 7. Then, squaring both sides give us t = 49 days. So, it will take 49 days for the number of infected people to reach 1400.

Given the function n=200 Square root t where n is the number of infected, and t is time, it will take 49 days for the number of infected people to reach 1400.

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Help me with this question if you don’t mind

Answers

Answer:

D

Step-by-step explanation:

if AB is congruent to AC that means both are 76 degrees so subtract that from the total degrees of a whole triangle which is 180 that gives you A which is 28.

Hope it helps :)

How to solve this type of question

Answers

In general, you solve questions of cancavity by looking at the second derivative. It will be negative where the function is concave downward. (It will be positive for concave upward, and zero at points of inflection.)

I find it convenient to get guidance from a graphing calculator.

f(x) is concave downard on the interval (-∞, 2).

_____
The derivative is
.. f'(x) = e^-x -x*e^-x
The second derivative is
.. f''(x) = -e^-x -(e^-x -x*e^-x)
.. = (x -2)*e^-x
This will be negative for x < 2.