If the width and length of a rectangle are both increased by 10%, by what percent does the area of the rectangle increase? By what percent does the perimeter of the rectangle increase?

Answers

Answer 1
Answer:

Answer:

10%

Step-by-step explanation:

We know Perimeter of rectangle

= 2 (Length + Width)

If width and length are increased by 10%

New length= L + 10/100L = (1.1) L

New width = W + 10/100W = (1.1) W

Perimeter = 2 [(1.1) L + (1.1) W]

Perimeter = 2 (1.1) (L + W)

Perimeter = (2.2) (L + W)

Increase in perimeter = 2.2 (L + W) - 2 (L + W)

The increase in Perimeter = 0.2 (L + W)

Percent increase

= 0.2 (L + W)/2 (L + W) × 100

= 0.2/2 × 100

= 0.1 × 100

= 10%

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Answer 2
Answer:

Final answer:

When the length and width of a rectangle are increased by 10%, the area increases by 21% and the perimeter increases by 10%.

Explanation:

The area of a rectangle is calculated by the formula Length × Width. If both the length and width are increased by 10%, the new area would be 1.1(length) × 1.1(width), which is 1.21(length × width) or 121% of the original area. So the area increases by 21%. The perimeter of a rectangle is calculated by the formula 2(Length + Width). If both the length and width increase by 10%, the new perimeter would be 2(1.1 Length + 1.1 Width) = 2.2 Length + 2.2 Width, which is 110% or 1.1 times the original perimeter. So the perimeter increases by 10% when you increase the length and width by 10%.

Learn more about Increase in Rectangle Dimensions here:

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In a 100 kg afebrile person with intact skin, insensible fluid loss from lungs and skin is approximately: A) 500 mL/day. B) 800 mL/day. C) 1000 mL/day. D) 1200 mL/day.

Answers

In a 100 kg afebrile person with intact skin, the insensible fluid loss from the lungs and skin is approximately 500 mL/day (Option A).

Insensible fluid loss refers to the water that is lost from the body through evaporation, primarily from the lungs during respiration and from the skin through perspiration. This loss is not easily measurable and occurs continuously throughout the day.

In a person with normal body temperature (afebrile) and intact skin, the average insensible fluid loss is estimated to be around 500 mL per day. This loss helps maintain the body's fluid balance and temperature regulation.

It's important to note that this estimation can vary depending on various factors such as ambient temperature, activity level, and individual variations. However, in the given context, the most appropriate and accurate answer is Option A: 500 mL/day.

Find the distance between points P(1, 2) and Q(4, 8) to the nearest tenth. 11.2 5 6.7 9

Answers

distance = sqrt (x2 - x1)^2 + (y2 - y1)^2
(1,2)...x1 and y1
(4,8)...x2 and y2
now we sub
distance = sqrt (4 - 1)^2 + (8 - 2)^2
distance = sqrt (3^2 + 6^2)
distance = sqrt (9 + 36)
distance = sqrt (45)
distance = 6.7 <===
PQ=√(x2-x1)²+(y2-y1)²
     =√(4-1)²+(8-2)²
     =√(3)²+(6)²
     =√9+36
     =√45
     =3√5
     =3*2.236
     =6.708
     =6.79.

This is a mathematical sentence written with a greater than, a less than sign, or a not equal to sign.

Answers

greater than means >

less than <

not equal to ≠

How much will you save per lb, by buying the least expensive? Round to the nearest cent. 2.5 lbs for $8.75 or 3 pounds for $9.75.

Answers

Answer:

$0.25 per pound.

Step-by-step explanation:

Let us find unit rate for both quantities.

\text{Price per pound}=\frac{8.75\text{ dollars}}{2.5\text{ pound}}

\text{Price per pound}=3.5\frac{\text{ dollars}}{\text{ pound}}  

Therefore, cost of per pound for first given rate is $3.5.

Now let us find unit rate for second quantity.

\text{Price per pound}=\frac{9.75\text{ dollars}}{3\text{ pound}}

\text{Price per pound}=3.25\frac{\text{ dollars}}{\text{ pound}}

We can see that price for second quantity is less than 1st. To find the savings per pound we will subtract 3.25 from 3.5.

\text{Savings per pound}=3.50-3.25

\text{Savings per pound}=0.25

Therefore, we will save $0.25 per pound by buying the least expensive.

Answer:

0.25

Step-by-step explanation:

The Drama Club is showing a video of their recent play. The first showing begins at 4:35 p.M. The second showing is scheduled at 7:15 p.M. With a 1 2 −hour break between the showings. How long is the video in hours and minutes? The video is hours and minutes. Complete the explanation of how you can use a number line to find the answer. You can work backward from the start time of the second showing at : . You count back 1 2 hour, which is minutes, for the break between showings to : . The second showing started 20 minutes late. Will the second showing be over by 9:35 p.M.? Complete the explanation why your answer is reasonable. The second showing started at : p.M. The movie lasts hours minutes, so it ends at :45 p.M. So, ? The second showing ? Be over by 9:35 p.M.

Answers

Answer:

Part A

2 hours 10 minutes

Part B;

Please find attached a number line created with MS Visio

Part C

The completed explanation is given as follows

The second showing starts at 7:35 p.m. The movie lasts 2 hours 10 minutes so it ends 9:45 p.m. So the second sowing be over by 9:45 p.m

Step-by-step explanation:

Part A

The given parameters are;

The time the first showing starts, t₁ = 4:35 p.m.

The time the first showing starts, t₂ = 7:15 p.m.

The time interval between shows, t_(interval) = 1/2 hours = 30 minutes

Let 'x' represent the video in minutes, we have;

x = 7:15 - 4:35 - 30 = 2 hours 40 minutes - 30 minutes = 2 hours 10 minutes

The length of the video = 2 hours 10 minutes

Part B;

Using the number line, we have;

1) Plotting the points for the starting and  points for the two showing points which are 4:35 pm. and 7:15 p.m.

2) Plot the point 30 minutes before the start of the second movie which is 6:45 p.m and find the time difference between the start of the first showing and the point 6:45 p.m. which gives the length of the movie which is 2 hours and 10 minutes

3) Given that the second showing starts 20 minutes late, the second showing will start at 7:15 p.m. + 20 min = 7:35 p.m.

4) The second showing ends at 7:35 p.m. + 2 hours 10 minutes = 9:45 p.m.

Therefore, the second showing will be over 9:35 p.m.

Part C

The second showing starts at 7:35 p.m. The movie lasts 2 hours 10 minutes so it ends 9:45 p.m. So the second sowing be over by 9:45 p.m.

Show how to solve 6/15=2/?

Answers

There are two way sof doing this question: 
 1st solution  is : 
 6/15 = 2/5
because 6/15 is divisible by 3 and it is done by this form : 
     3 X 2 = 6
       and
    3 X 5 = 15
2nd solution is:
6/15 = 2/?
here we suppose that the missing value is x:
 6/15 = 2/x
 
 you shift the denominators and then  multiply them by the their numerators:
 6 * x = 15 * 2
      6x = 30
 now you divide 6 on both sides:
 6x/6 = 30/6
      x = 5


6 / 15 = 2 / x

6x = 30

x = 30 / 6 = 5