Find the area of the combined figure. A figure is made up of a triangle and a rectangle. The triangle has a height of 8.5 inches and a base of 10 inches. The rectangle has dimensions of 9 inches x 10 inches. What is the area of the figure? a 102.5 square inches b 132.5 square inches C 110.2 square inches d 140.2 square inches​

Answers

Answer 1
Answer:

Answer:

132.5

Step-by-step explanation:

for the triangle 8.5 * 10 / 2 = 42.5

the rectangle 9 * 10 = 90

42.5 + 90 = 132.5


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Dind the elapsed time the hours and minuts​

Answers

Answer:

pretty sure the answer is 5 hours and 30 minutes

B is the midpoint of AC, D is the midpoint of CE , and AE = 23. Find BD.12.5
46
11.5
23

Answers

11.5 is the length of bd

This is very important assignment I need to make my family proud with a good grade

Answers

Answer:

They're 24 in total so i guess it would be 24 units^2

Step-by-step explanation:

24!!! i hope you make them proud :)

If f(x)=1-x^2+x^3, then f(-1)=

Answers

Answer:

Well, we know that there exists a function f(x) such that f(x-1) is a direct transformation of its parent function. First we want to set x=x-1. Conceptually, it might be easier just to annotate one of the x’s as a completely different variable, because we know that x doesn’t equal x-1. So let’s rewrite as x=y-1 and solve for y.

We now have y=x+1 where y(x) is actually our parent function and y(x)=f(x+1). So take our equation f(x-1) and substitute each x with (x+1). So f(x)=2(x+1) + 3

f(x)= 2x + 5. We can check this by finding f(x-1) because it should equal 2x+3.

f(x-1)= 2(x-1) + 5

f(x-1)= 2x + 3.

Hoped I helped

Simplify the expression below.(43+1)^3
A. 1223 + 1
B. 6432 + 1
C. 6413 + 48y2 + 16y + 3
D. 6413 + 4812 + 12y + 1

Answers

I believe the answer is C

Data Entry - No Scoring During your procedure to determine the uncalibrated volume near the stopcock of your buret, what was the mass in grams of water that drained out when the meniscus started just above the 25 mL mark and ended just above the stopcock? Report to the thousandth of a gram.

Answers

Answer:

0.025 grams

Step-by-step explanation:

The water in the stopcock has a volume of 25 mL initially, After that, the whole water was drained out. So we have:

Volume of drained water = (25 mL)(1 x 10⁻⁶ m³/1 mL)

Volume of drained water = 25 x 10⁻⁶ m³

Density of drained water = 1000 kg/m³

So, for the mass of drained water:

Density of drained water = Mass of drained water/Volume of drained water

Mass of drained water = (Density of drained water)(Volume of drained water)

Mass of drained water = (1000 kg/m³)(25 x 10⁻⁶ m³)

Mass of drained water = 0.025 gram

Density