A car travels at a steady speed of 10 m/s. What distance is covered in a minute?

Answers

Answer 1
Answer:

Answer:

600

Explanation:

Answer 2
Answer: 10*60=600

You multiply it by 60 because it is saying that it travels 1 mile per second and there are 60 seconds in one minute.

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How are the three cell layers of an embryo related to its development?

Answers

The said development of the cell where the three cell layers help out do it is called as Gastrulation. The three layers - called as ectoderm, endoderm, and mesoderm - tend to form as this happens. This is a process that's present in all living things except sponges.

Look at Figure 2. Describe the motion of the object in Graph ACompare Graphs A and B in Figure 2. At a time of 2 seconds, which graph shows a greater velocity? How do you know?

Answers

The graphs show distance versus time data. For graph A, we can say that velocity is constant until it reaches time of 8 seconds. And a constant velocity is again exhibited starting at time 12 seconds. For graph B, the velocity is changing as time pass by since  the slope is changing. At time of 2 seconds, graph A has greater velocity since it has a steeper slope.

A planet has twomoons.  The first moon has an orbital
period of 1.262 Earth days and an orbital radius of 2.346 x 104
km.  The second moon has an orbital
radius of 9.378 x 103 km. 
What is the orbital period of the second moon?  

Answers

Kepler's third law hypothesizes that for all the small bodies in orbit around the
same central body, the ratio of (orbital period squared) / (orbital radius cubed)
is the same number.

Moon #1:  (1.262 days)² / (2.346 x 10^4 km)³

Moon #2:  (orbital period)² / (9.378 x 10^3 km)³

If Kepler knew what he was talking about ... and Newton showed that he did ...
then these two fractions are equal, and may be written as a proportion.

Cross multiply the proportion:

(orbital period)² x (2.346 x 10^4)³ = (1.262 days)² x (9.378 x 10^3)³

Divide each side by (2.346 x 10^4)³:

(Orbital period)² = (1.262 days)² x (9.378 x 10^3 km)³ / (2.346 x 10^4 km)³

               =  0.1017 day²

Orbital period = 0.319 Earth day = about 7.6 hours.

The velocity of a car changes from 20 m/s east to 5 m/s east in 5 seconds. What is the acceleration of the car?

Answers

To solve this remember a=change in v/t, assuming the direction for the velocity, is + positive east. You can calculate it simply by this. A=v/t= A=5-20/5= A=-15/5= A=-3m/s squared. Change in velocity= vf-vi.

Dark spots on the photosphere are known asA. the corona.
B. the chromosphere.
C. sunspots.
D. solar wind.

Answers

The dark spots that are found on the photosphere are called sunspots. These are a temporary phenomena and are areas of different temperature compared to the surroundings. Sunspots are at a lower temperature compared to the surrpundings and they are created due to magnetic field flux. They can stay on from a few days to a few months and eventually decay.

C is the right answer

A kite suspended in the sky is flowing back and forth. Which type of friction is being described?

Answers

The type of friction of a kite suspended in the sky that is flowing back and forth is fluid friction. The fluid here is the air that helps the kite move back and forth. The kite feels a drag force due to air which acts in the upward direction.

Answer:

Fluid friction - in fluid friction, there is something called air resistance. This makes fluid friction happen in liquids AND in gases.

Explanation: