1.682 inches rounded to the nearest whole number is 1 inch. True or False

Answers

Answer 1

Answer:

The answer is false

Step-by-step explanation:

6 is closer to 10

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Complete parts (a) through (c) below. (a) Determine the critical value(s) for a right-tailed test of a population mean at the level of significance with degrees of freedom. (b) Determine the critical value(s) for a left-tailed test of a population mean at the level of significance based on a sample size of n. (c) Determine the critical value(s) for a two-tailed test of a population mean at the level of significance based on a sample size of n.

Answers

Answer:

(a) The critical value of t at P = 0.01 and 15 degrees of freedom is 2.602.

(b) The critical value of t at P = 0.05 and 19 degrees of freedom is -1.729.

(c) The critical value of t at P = 0.025 and 12 degrees of freedom is -2.179 and 2.179.

Step-by-step explanation:

We have to find the critical t values for each of the following levels of significance and sample sizes given below.

As we know that in the t table there are two columns. The horizontal column is represented by the symbol P which represents the level of significance and the vertical column is represented by the symbol ' $\nu$ ' which represents the degrees of freedom.

(a) A right-tailed test of a population mean at the α=0.01 level of significance with 15 degrees of freedom.

So, here the level of significance = 0.01

And the degrees of freedom = n - 1 = 15

Now, in the t table, the critical value of t at P = 0.01 and 15 degrees of freedom is 2.602.

(b) A left-tailed test of a population mean at the α=0.05 level of significance with a sample size of n = 20.

So, here the level of significance = 0.05

And the degrees of freedom = n - 1

= 20 - 1 = 19

Now, in the t table, the critical value of t at P = 0.05 and 19 degrees of freedom is -1.729.

(c) A two-tailed test of a population mean at the α=0.05 level of significance with a sample size of n = 13.

So, here the level of significance = $(0.05)/(2)$ = 0.025 {for the two-tailed test}

And the degrees of freedom = n - 1

= 13 - 1 = 12

Now, in the t table, the critical value of t at P = 0.025 and 12 degrees of freedom is -2.179 and 2.179.

The measure of the exterior angle of the triangle is?

Answers

Formula:

Interior + Interior=exterior

Step 1:

75 + 64 =x

139=x

Mark brainliest if helpful

Let the number of chocolate chips in a certain type of cookie have a Poisson distribution. We want the probability that a cookie of this type contains at least two chocolate chips to be greater than 0.99. Find the smallest value of the mean that the distribution can take.

Answers

Answer:

$\lambda \geq 6.63835$

Step-by-step explanation:

The Poisson Distribution is "a discrete probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known constant mean rate and independently of the time since the last event".

Let X the random variable that represent the number of chocolate chips in a certain type of cookie. We know that $X \sim Poisson(\lambda)$

The probability mass function for the random variable is given by:

$f(x)=(e^(-\lambda) \lambda^x)/(x!) , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda$

$E(X)=\mu =\lambda$

On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:

$P(X\geq 2)=1-P(X<2)=1-P(X\leq 1)=1-[P(X=0)+P(X=1)]$

Using the pmf we can find the individual probabilities like this:

$P(X=0)=(e^(-\lambda) \lambda^0)/(0!)=e^(-\lambda)$

$P(X=1)=(e^(-\lambda) \lambda^1)/(1!)=\lambda e^(-\lambda)$

And replacing we have this:

$P(X\geq 2)=1-[P(X=0)+P(X=1)]=1-[e^(-\lambda) +\lambda e^(-\lambda)[]$

$P(X\geq 2)=1-e^(-\lambda)(1+\lambda)$

And we want this probability that at least of 99%, so we can set upt the following inequality:

$P(X\geq 2)=1-e^(-\lambda)(1+\lambda)\geq 0.99$

And now we can solve for $\lambda$

$0.01 \geq e^(-\lambda)(1+\lambda)$

Applying natural log on both sides we have:

$ln(0.01) \geq ln(e^(-\lambda)+ln(1+\lambda)$

$ln(0.01) \geq -\lambda+ln(1+\lambda)$

$\lambda-ln(1+\lambda)+ln(0.01) \geq 0$

Thats a no linear equation but if we use a numerical method like the Newthon raphson Method or the Jacobi method we find a good point of estimate for the solution.

Using the Newthon Raphson method, we apply this formula:

$x_(n+1)=x_n -(f(x_n))/(f'(x_n))$

Where :

$f(x_n)=\lambda -ln(1+\lambda)+ln(0.01)$

$f'(x_n)=1-(1)/(1+\lambda)$

Iterating as shown on the figure attached we find a final solution given by:

$\lambda \geq 6.63835$

Final answer:

The problem pertains to Poisson Distribution in probability theory, focusing on finding the smallest mean (λ) such that the probability of having at least two chocolate chips in a cookie is more than 0.99. This involves solving an inequality using the formula for Poisson Distribution.

Explanation:

This problem pertains to the Poisson Distribution, often used in probability theory. In particular, we're looking at the number of events (in this case, the number of chocolate chips) that occur within a fixed interval. Here, the interval under study is a single cookie. The question requires us to find the smallest value of λ (the mean value of the distribution) such that the probability of getting at least two chocolate chips in a cookie is more than 0.99.

Using the formula for Poisson Distribution, the probability of finding k copies of an event is given by:

P(X=k) = λ^k * exp(-λ) / k!

The condition here is that the probability of finding at least 2 copies is more than 0.99. Therefore, you formally need to solve the inequality:

P(X>=2) = 1 - P(X=0) - P(X=1) > 0.99

Substituting the values of P(X=0) and P(X=1) from our standard formula, you will need to calculate and find the smallest value of λ that satisfies this inequality.

Learn more about Poisson Distribution here:

brainly.com/question/33722848

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I don't understand this plz help

Answers

Hey there! :D

When you are finding the area of corresponding sides, you square the number of the ratio of the similar lengths.

The screens a little blurry, but I'm assuming the corresponding side is represented as:

$(a)/(b)$

So, you would keep a and b where they are, (you would be confusing the areas if you switched it in any way) and then just square the variables.

$(a^2)/(b^2)$

"C" is the best answer.

I hope this helps!
~kaikers

Solve for x 4 - (x + 2) < -3(x + 4)

Answers

Answer:

x<-7

Step-by-step explanation:

Use inverse operations to solve

4 - ( x + 2 ) < -3 ( x+ 4)

first distribute the (-) sign and the (-3)

4 -x -2 < -3x -12

simplify

2 -x < -3x -12

simplify again, with inverse operations

2 -x < -3x -12

+3x +3x

2 + 2x < -12

-2 -2

2x < -14

/2 /2

x<-7

in 4 - (x + 2) < -3(x + 4), x < -7

isolate the variable by dividing each side by factors that don't contain the variable.

54.55÷5 people what is a good estimate for quotient

Answers

See attachment for math work and answer.

I think it would be 11

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