MATHEMATICS HIGH SCHOOL

A traveler is walking on a moving walkway in an airport. The traveler must walk back on the walkway to get a bag he forgot. The traveler's ground speed is 1 ft/s against the walkway and 5ft/s with the walkway. What is the traveler's speed off the walkway? What is the speed of the moving walkway?

Answers

Answer 1

Answer:

Oh my gosh I hate math, do you

Answer 2

Answer:

Step-by-step explanation:

thus the speed off the walk way is 5 ft/s

the speed of the moving walkway is 3 ft/s

Related Questions

Ex 2.11
20) A curve y''=12x-24 and a stationary point at (1,4). evaluate y when x=2.

Answers

So, dy/dx=0 at the point (1, 4) - that is where x=1 and y=4.

$\int { 12x-24dx } \n \n =\frac { 12{ x }^( 2 ) }{ 2 } -24x+C\n \n =6{ x }^( 2 )-24x+C$

$\n \n \therefore \quad { f }^( ' )\left( x \right) =6{ x }^( 2 )-24x+C$

But when x=1, f'(x)=0, therefore:

$0=6-24+C\n \n 0=-18+C\n \n \therefore \quad C=18$

$\n \n \therefore \quad { f }^( ' )\left( x \right) =6{ x }^( 2 )-24x+18$

Now:

$\int { 6{ x }^( 2 ) } -24x+18dx\n \n =\frac { 6{ x }^( 3 ) }{ 3 } -\frac { 24{ x }^( 2 ) }{ 2 } +18x+C$

$=2{ x }^( 3 )-12{ x }^( 2 )+18x+C\n \n \therefore \quad f\left( x \right) =2{ x }^( 3 )-12{ x }^( 2 )+18x+C$

Now when x=1, y=4:

$4=2-12+18+C\n \n 4=8+C\n \n C=4-8\n \n C=-4$

$\n \n \therefore \quad f\left( x \right) =2{ x }^( 3 )-12{ x }^( 2 )+18x-4$

Now when x=2,

$f\left( x \right) =2\cdot { 2 }^( 3 )-12\cdot { 2 }^( 2 )+18\cdot 2-4\n \n =16-48+36-4\n \n =0$

So when x=2, y=0.

$y''=12x-24\ny'=\int 12x-24\, dx\ny'=6x^2-24x+C\n\n0=6\cdot1^2-24\cdot1+C\n0=6-24+C\nC=18\ny'=6x^2-24x+18\n\ny=\int 6x^2-24x+18\, dx\ny=2x^3-12x^2+18x+C\n\n4=2\cdot1^3-12\cdot1^2+18\cdot1+C\n4=2-12+18+C\nC=-4\n\n 2x^3-12x^2+18x-4$

$y(2)=2\cdot2^3-12\cdot2^2+18\cdot2-4\ny(2)=16-48+36-4\n\boxed{y(2)=0}$

4(x+1)-ax=x+5 solve for x

Answers

4(x + 1) - ax = x + 5
4(x) + 4(1) - ax = x + 5
4x + 4 - ax = x + 5
- x - x
3x + 4 - ax = 5
- 4 - 4
3x - ax = 1
x(3) - x(a) = 1
x(3 - a) = 1
3 - a 3 - a
x = 1/(3 - a)

$4(x+1)-ax=x+5$

$4x+4-ax=x+5$ $Expand$

$4x-ax=x+5-4$    $Subtract \ 4 \ from \ both \ sides$

$4x-ax=x+1$

$4x=x+1+ax$    $Add \ ax \ to \ both \ sides$

$4x-x=1+ax$    $Subtract \ x \ from \ both \ sides$

$3x=1+ax$

$3x-ax=1$ $Subtract \ ax \ from \ both \ sides$

$x(3-a)=1$

$x= (1)/(3-a)$

-(4x - 7) + 1 = 2 (5 - 2x) solve for x

Answers

Answer:

No solution

Step-by-step explanation:

-(4x - 7) + 1 = 2(5 - 2x)

-4x + 7 + 1 = 10 - 4x

-4x + 8 = 10 - 4x

-4x + 8 ≠ -4x + 10

No solution

The variable a is the length of the ladder. The variable h is the height of the ladder's top at time t, and x is the distance from the wall to the ladder's bottom. Suppose that the length of the ladder is 5.0 meters and the top is sliding down the wall at a rate of 0.4 m/s. Calculate dx dt when h = 3.1.

Answers

Answer:

dx/dt= 0.2608 at h= 3.1 m

Step-by-step explanation:

a is the length of the ladder. a=5

by pythagorus theorem

$x^2 = a^2-h^2$

differentiating with respect to t we get

$x(dx)/(dt) = -h(dh)/(dt)$ ......1

The variable h is the height of the ladder's top at time t, and x is the distance from the wall to the ladder's bottom

At h= 3.1

x^2= 6^2-3.1^2 = 9.1×2.9

x= 5.1371 m

given $(dh)/(dt) =-0.4$

putting values in 1 to get dx/dt

$5.1371(dx)/(dt) = 3.1×04$ .

dx/dt= 0.2608 at h= 3.1 m

Answer:

$(dx)/(dt)$ = 0.3

Step-by-step explanation:

The given situation forms a right triangle. We have to use the Pythagorean theorem's statement to solve this problem.

The theorem states that the sum of the squares of the legs is equal to the square of the hypotenuse.

Here Hypotenuse = length of the ladder (a)

Legs are h and x.

So, using the Pythagorean theorem, we get

$a^2 = h^2 + x^2$ -------------(1)

We are given a = 5 meters, $(dh)/(dt)$ = 0.4

Now plug in a = 5 in the above equation, we get

$5^2 = h^2 + x^2$

25 = $h^2 + x^2$ -----(2)

To find the $(dx)/(dt)$ . Differentiate the above equation with respective to the time t, we get

$2h(dh)/(dt) + 2x(dx)/(dt) = 0\n$ -------(3)

We know that h = 3.1 and $(dh)/(dt)$ = 0.4.

We can find x, by plug in h = 3.1 from the equation (2)

25 = $3.1^2 + x^2$

$x^2 = 25 - 9.61$

x = 3.9

Now plug h = 3.1, x = 3.9 and $(dh)/(dt)$ = -0.4 in the derivative (3) and find dx/dt

Here we represents $(dh)/(dt)$ = -0.4 because it is sliding down

2(3.1)(-0.4) + 2(3.9) $(dx)/(dt)$ = 0

-2.48 + 7.8 $(dx)/(dt)$ = 0

7.8 $(dx)/(dt)$ = -2.48

$(dx)/(dt)$ = -2.48 ÷ -7.8

$(dx)/(dt)$ = 0.3179

When we rounding off to the nearest tenths place, we get

$(dx)/(dt)$ = 0.3

If you have a new deck of shuffled cards, what is the probability you will choose an ace? (52 cards, no jokers) A) 1 13 B) 1 2 C) 1 4 D) 1 6

Answers

Answer:

B 1/2

Step-by-step explanation:

I looked it up.

But I think it'd be C because there would be 4 aces in the deck, and C has 1/4

Answer: 1/13 is the correct answer.

Step-by-step explanation: You put the total amount of aces, which is four, on the top part of your fraction and the total number of 52 cards on the bottom of your fraction. Since four will divide into both numbers, you simplify 4/52 to get 1/13. 4 divided by four is one. 52 divided by 4 is 13. That is how you get your 1/13 from 4/52. Answer was confirmed correct on the test I took. I hope this helps you! Thanks!

1 pointGiven –12 = 2(_5n + 11), What would be your first step?
O Distribute the 2 times the 5n and 11
Subtract 11 on both sides
Add the 5 and 11 because they are Like Terms.
O Divide by -5

Answers

Distribute the 2 is the first step

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