What is 0.076 in scientific notation

Answers

Answer 1
Answer: 7.6 x 10^2 that's the answer
Answer 2
Answer: I hope this helps you

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isabel lives 3/4 mile from school, Janet lives 2/3 mile from school how much farther in miles does isabel live from school than Janet?

Answers

Isabel lives 1/12 mile farther than Janet from the school.

Given that, Isabel lives 3/4 mile from school, and Janet lives 2/3 mile from the school.

We need to find how much farther in miles does Isabel live from school than Janet.

How to subtract, unlike fractions?

Addition and subtraction of unlike fractions:

Step I: Obtain the fractions and their denominators.

Step II: Find the LCM (least common multiple) of the denominators.

Step III: Convert each fraction into an equivalent fraction having its denominatorequal to the LCM (least common multiple) obtained in Step II.

Now, 3/4-2/3=9/12-8/12

=1/12

Therefore, Isabel lives 1/12 mile farther than Janet from the school.

To learn more about the subtraction of fractions visit:

brainly.com/question/485310.

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Hey There!

Steps to solve (steps will be in numerical order)

1. Find the lcd of the fractions (3)/(4) and (2)/(3) . The lcd for both problems will be 12.

2. To rewrite 
(3)/(4) you have to multiply the numerator and denominator by three since the lcd is 12. So you're new fraction will be (9)/(12). For the second fraction, since the lcd is 12 you will multiply the numerator and denominator by 4. You're new fraction will be (8)/(12).

3. Since the problem contains the math keyword "Further", you automatically know you have to subtract, now subtract 
(9)/(12)(8)/(12). First, start of by subtracting the numerators, so subtract 9-8=1 , remember the denominators will always stay the same.

In conclusion, you're answer will be 
(1)/(12), so Isabel lives (1)/(12) farther away from Janet.

Hope This Helps :)

Is 68 a perfect square

Answers

No, because a perfect square has the volume of 24 
No because a perfect square has a volume of 24

How do you solve equations that contain addition or subtraction?

Answers

Any equation given, with a variable, could be solved by applying the inverse operation. 

Example:-

4 + x = 8
-4        -4

x = 8 -4
x = 4

Answer; x = 4

To learn the basics I would suggest using this simple model to solve. Remember, that you can add, subtract, multiply, or divide anything to both side of the equal sign.
Ex. 5 + 5 = x
     -5       -5

Now, let's try a real problem:
         
            10 + x = 15
Now, I know this may seem to be an easy problem, but by using the method I am about to show you, you will be able to solve any addition, subtraction, even multiplication, and division equation!
      This would be how you solve:           
                10 + x = 15
                 -10         -10
----------------------------------------
                        x = 5
 
Hope this helped!


SOLVE BY SUBSTITUTION:3x-2y=14
y=5x
solve by substitution
x-2y=-2
y=2x+4
solve by elimination
x+2y=-7
x-5y=7
PLEASE HELP WORTH 10 POINTS! AKA SHOW WORK:)

Answers

1)
3x-2y=14
y=5x

So we plug in y=5x into 3x-2y=14

We get:

3x-2(5x)=14
3x -10x=14
-7x=14
x=-2

So we found x, now we need to find y. We can simply plug in x into the equation and get y.

y=5x
y=5(-2)
y=-10

So your answer will be (-2,-10).

2) 
x-2y= -2
y= 2x+4

Once again plug in y=2x+4 into x-2y=-2

x-2(2x+4) = -2
x-4x-8=-2
-3x-8=-2
-3x = 6
x= -2

Now we plug back in x and solve for y :)

y=2x+4
y=2(-2)+4
y=-4+4
y=0

So our solution would be (-2,0).

3)
x+2y=-7
x-5y=7

Multiply the second equation by -1

-x+5y=-7

Now add that equation with the other one:

   x+2y=-7
+
   -x+5y=-7
-----------------
7y=-14
y=-2

Now plug in y=-2 and solve for x

x+2y=-7
x+2(-2)=-7
x+(-4)=-7
x-4=-7
x=-3

So your solution would be (-3,-2).

1)

3x-2y=14\n \n y=5x

We know y's value. Let's plug it in the equation.

y=5x\n \n 3x-2\cdot (5x)=14\n \n 3x-10x=14\n \n -7x=14

Divide both sides by -7.

x=-2

Now we have x's value. Let's plug it in the equation to find y.

x=-2\n \n y=5x\n \n y=5\cdot -2\n \n y=-10

Solution,

(-2, -10)

2)
x-2y=-2\n \n y=2x+4

Again we have y's value. Let's plug and solve.

y=2x+4\n \n x-2\cdot (2x+4)=-2\n \n x-(2\cdot 2x+2\cdot 4)=-2\n \n x-4x-8=-2\n \n -3x-8=-2\n \n -3x=-2+8\n \n -3x=6\n \n x=\frac { 6 }{ -3 } \n \n x=-2

Now we have x's value let's solve for y.

x=-2\n \n y=2x+4\n \n y=2\cdot (-2)+4\n \n y=-4+4\n \n y=0

Solution,

(-2, 0)

3)

x+2y=-7\n \n x-5y=7

Let's first multiply the first equation by -1

-1\cdot (x+2y)=-1\cdot -7\n \n -x-2y=7

Then let's add these new equation and the second equation.

-1\cdot (x+2y)=-1\cdot -7\n \n -x-2y=7\n \n x-5y=7\n \n (-x-2y)+(x-5y)=7+7\n \n -x+x-2y-5y=14\n \n -7y=14\n \n y=\frac { 14 }{ -7 } \n \n y=-2

Now we have y's value let's plug it and solve for x.

y=-2\n \n x+2y=-7\n \n x+2\cdot (-2)=-7\n \n x-4=-7\n \n x=-7+4\n \n x=-3

Solution,

(-3, -2)


Compare the values of the underlined digits 6,300 and 530 with three being the underlined digit.

Answers

The value of 3 in 6300 is ten times the value of 3 in 530

Further Explanation  

Place value and total value  

  • Place value refers to the value represented by a digit in a number based of its position in the number. Place values can be ones, tens, hundreds, thousands, etc  

For example;

In the number; 13,548, the place value of the digits in the number are;

Ones -8

Tens - 4

Hundreds - 5

Thousands - 3

Ten Thousands – 1

Total value  

  • Total value is given as the product of the digit and its place value.
  • For example; in the number, 13,548.  
  • Total value of digits 1, 3, 5, 4, and 8 in the number 13,548 will be;

1 x 10,000 = 10,000

3 x 1000    = 3,000

5 x 100      = 500

4 x 10        = 40  

8 x 1          = 8

The sum of the total values of digits in a number will be equivalent to the value of that number.

In the question.

Comparing the value of 3 in 6,300 and 530

The value of 3 in 6,300 is 300 and  

The value of 3 in 530 is 30

Therefore; the value of 3 in 6300 is ten times the value of 3 in 530

Keywords: Place value, total value

Learn more about;

Level: Middle school

Subject: Mathematics  

Topic: Place value and total value  

Comparing the values of 3 in each of 6,300 and 530, we will have:

3 in 6300 is 3 hundreds while 3 in 530 is 3 tens

How to solve number place value?

Place value is defined as the value of each digit in a number. For example, the 5 in 853 represents 5 tens, or 50; however, the 5 in 5,003 represents 5 thousands, or 5,000.

We want to compare the values of 3 in each of the numbers 6,300 and 530.

Thus, we can say that:

3 in 6300 is called 3 hundreds while 3 in 30 is called 3 tens or 30

Read more about Number place value at: brainly.com/question/24997908

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Simplify.–1 + 5(6 – y)



A.


–y + 5


B.


–y + 29


C.


–5y + 29


D.


–5y – 31

Answers

The answer is C. This is because you have to expand the brackets
-1+5(6-y)
The -1 remains the same but the bracket changes.
-1+30-5y
This is because the 5*6 is 30 and 5*y is 5y
This can be simplified to
29-5y or -5+29