Isabel lives 1/12 mile farther than Janet from the school.
Given that, Isabel lives 3/4 mile from school, and Janet lives 2/3 mile from the school.
We need to find how much farther in miles does Isabel live from school than Janet.
Addition and subtraction of unlike fractions:
Step I: Obtain the fractions and their denominators.
Step II: Find the LCM (least common multiple) of the denominators.
Step III: Convert each fraction into an equivalent fraction having its denominatorequal to the LCM (least common multiple) obtained in Step II.
Now, 3/4-2/3=9/12-8/12
=1/12
Therefore, Isabel lives 1/12 mile farther than Janet from the school.
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y=5x
solve by substitution
x-2y=-2
y=2x+4
solve by elimination
x+2y=-7
x-5y=7
PLEASE HELP WORTH 10 POINTS! AKA SHOW WORK:)
The value of 3 in 6300 is ten times the value of 3 in 530
Place value and total value
For example;
In the number; 13,548, the place value of the digits in the number are;
Ones -8
Tens - 4
Hundreds - 5
Thousands - 3
Ten Thousands – 1
1 x 10,000 = 10,000
3 x 1000 = 3,000
5 x 100 = 500
4 x 10 = 40
8 x 1 = 8
The sum of the total values of digits in a number will be equivalent to the value of that number.
In the question.
Comparing the value of 3 in 6,300 and 530
The value of 3 in 6,300 is 300 and
The value of 3 in 530 is 30
Therefore; the value of 3 in 6300 is ten times the value of 3 in 530
Keywords: Place value, total value
Level: Middle school
Subject: Mathematics
Topic: Place value and total value
Comparing the values of 3 in each of 6,300 and 530, we will have:
3 in 6300 is 3 hundreds while 3 in 530 is 3 tens
Place value is defined as the value of each digit in a number. For example, the 5 in 853 represents 5 tens, or 50; however, the 5 in 5,003 represents 5 thousands, or 5,000.
We want to compare the values of 3 in each of the numbers 6,300 and 530.
Thus, we can say that:
3 in 6300 is called 3 hundreds while 3 in 30 is called 3 tens or 30
Read more about Number place value at: brainly.com/question/24997908
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A.
–y + 5
B.
–y + 29
C.
–5y + 29
D.
–5y – 31