Answer:
I think the answer is A. y= 31x2 + 77x + 41
Step-by-step explanation:
The function h(x) = 31x2 + 77x + 41 can also be written as y = 31x2 + 77x + 41, as y is often used interchangeably with f(x) or h(x) in mathematical functions. The remaining options do not accurately reformulate the original equation.
The function
h(x) = 31x2 + 77x + 41
can also be written as
y = 31x2 + 77x + 41
. This is because in mathematical functions, y is often used interchangeably with f(x) or h(x), representing the output or dependent variable. It's important to note that, the other options do not correctly represent the original equation. In Option B, the constant term is incorrectly added to the function on the left side; in Option C, the constant term is incorrectly subtracted; and in Option D, the constant term is incorrectly added to 'y' on the left side.
#SPJ11
2x+5y=16
units, and its area is
square units.
Perimeter= 22.81
Area= 24
GO PLATO USERS
Answer:
1.55s
Step-by-step explanation:
The height equation of the projectile is given as;
h = -16t^2 + vt + s .......1
where;
t is the time in seconds,
v is the upward velocity at the start,
s is the starting height.
Given;
v = 70 ft/s
s = 5 ft
Substituting the values equation 1 becomes;
h = -16t^2 + 70t + 5
For the ball to reach 75 ft, h = 0
75 = -16t^2 + 70t + 5
-16t^2 + 70t + 5 - 75 = 0
-16t^2 + 70t - 70 = 0
solving the quadratic equation;
Time t = 2.83 s and t = 1.55s
Therefore, the ball will first reach 75 ft after 1.55 seconds.