Represents the following phraseall real numbers that are between - 8 and 3
Compound inequality

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Answer 1
Answer: the compound inequality for real numbers between -8 and 3 is -8

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The Waverly brush Company issued 4,000 shares of common stock worth $200,000.00 total. What is the par value of each share?

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$4,000x$50=$200,00.00

Given cos alpha = 8/17, alpha in quadrant IV, and sin beta = -24/25, beta in quadrant III, find sin(alpha-beta)

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Given \cos\alpha=(8)/(17), \alpha is in Quadrant IV,  \sin\beta=-(24)/(25), and \beta is in Quadrant III, find \sin(\alpha-\beta)

We can use the angle subtraction formula of sine to answer this question.

\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta

We already know that \cos\alpha=(8)/(17).

We can use the Pythagorean identity \sin^2\theta+\cos^2\theta=1 to find \sin\alpha.

\sin^2\alpha+((8)/(17))^2=1 \n \sin^2\alpha+(64)/(289)=1 \n \sin^2\alpha=(225)/(289) \n \n\sin\alpha=\pm(15)/(17)

Since \alpha is in Quadrant IV, and sine is represented as y value on the unit circle, we must assume the negative value \sin\alpha=-(15)/(17).

As similar process is then done with  \sin\beta=-(24)/(25).

(-(24)/(25))^2+\cos^2\beta=1 \n (576)/(625)+\cos^2\beta=1 \n \cos^2\beta=(49)/(625) \n \n\cos\beta=\pm(7)/(25)

And since \beta is in Quadrant III, and cosine in represented as x value on the unit cercle, we must assume the negative value \cos\beta=-(7)/(25).

Now we can fill in our angle subtraction formula!

\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta \n\n \sin(\alpha-\beta)=(-(15)/(17)*-(7)/(25))-((8)/(17)*-(24)/(25)) \n\n\sin(\alpha-\beta)=(105)/(425)-(-(192)/(425)) \n\n \boxed{\sin(\alpha-\beta)=(297)/(425)}

Witch expression has the same value as 2 to the power of 12

Answers

Answer:

4096

Step-by-step explanation:

2^12

=2x2x2x2x2x2x2x2x2x2x2x2=4096

The length of a rectangle is 7m more than its width. The perimeter of the rectangle is 60m. What are the dimensions?

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