MATHEMATICS HIGH SCHOOL

Please help this is timedWhat is the solution to this system of equations?
3.2x+0.5y = 42
-1.6x-0.5y = 3.4
O (4.75, 38.8)
O (4.75, -22)
no solution
infinitely many solutions
please help this is timed What is the solution to - 1

Answers

Answer 1
Answer: The answer I’d (4.75, -22)

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Work out the value of (-2)2
Solve for all values of x by factoring.x^2-6x+20=6x

Please helpppppppppppp

Answers

Answer:

96

Step-by-step explanation:

3*6=18*2=36

6*10=60*2=120

10*3=30*2=60

36+60+120=

216

Answer: 216 m

Step-by-step explanation:

2(10 x 6) = 120

2(6 x 3) = 36

2(10 x 3) = 60

120 + 36 + 60 = 216

If f(x) = 2x2 - x, find f(-3).
15
21
39

Answers

Its C on edge but the answer is 21

Subtract. Write your answer in simplest form.

5 2/6 - 2 3/6=____

Answers

2 (5)/(6)

Working;
Start by converting both terms into improper fractions;

(32)/(6)-(15)/(6)

This gives;
(17)/(6)

On simplifying;
2(5)/(6)
5 2/6 = 32/6
2 3/6 = 15/6

32/6 – 15/6 = 17/6 = 2 5/6

How do you solve this?

Answers

you X to the second power.. 4 to the second power is 16 and 16-16=0 so x=4
Add 16
x² - 16 = 0
    + 16 +16

x² = 16
Take square root

√(x^2) = √(16)

Remember when you take the square root of a perfect square you get two values. +ve and -ve

x = -4
x =  4

because (-4)² = 16
               ( 4)² = 16

A scale drawing of a square has a side length of 5 millimeters. The drawing has a scale of 1 mm : 5 km. Find the actual perimeter and area of the square.

Answers

Answer:

Actual Perimeter = 100 km

        Actual Area = 625 km²

Step-by-step explanation:

A scale drawing of a square has a side length of 5 millimeters.

The drawing has a scale of 1 mm : 5 km (which represents 1 mm is equal to 5 km)

We need to find the actual measurement of 5 mm square on scale.

                1 mm = 5 km

               5 mm = 5 × 5 km

                          = 25 km

The actual length of the side of square is 25 km

Now, we find the perimeter and area of the square.

  • Perimeter of square = 4 × side

                                 = 4 × 25

                                = 100 km

  • Area of the square = side × side

                                        = 25 × 25

                                        = 625 km²

Hence, The actual perimeter is 100 km and area of the square is 625 km²

What is the domain of f(x)?What is the range of f(x)?
How is the domain and range of this function different from the other functions you have seen in this topic?

Answers