The table for Pedro's cell phone plan (Plan A) would indicate the total cost based on the $4.00 base fee and an additional 4 cents for each text message. His total cost increases by 4 cents with each additional message sent beyond the base fee.
To create an accurate table for Pedro's potential cell phone plan (Plan A), we need to consider that he will pay a fixed fee of $4.00 each month, plus an additional 4 cents for each text message. Let's create a table where one column represents the number of text messages and the other column reflects the total cost.
Remember, Pedro is being charged per individual message, so his total cost will increase by 4 cents with each additional text message beyond the base fee.
#SPJ3
Answer:
The height of the block is 2.5 cm
Solution:
Let us assume the height of the block =h
The length of the rectangle l = 12 cm
The width of the rectangle w = 5 cm
The volume of the rectangle
We know the volume of the rectangular block
So,
=\left(\frac{30}{12}\right)
=\left(\frac{5}{2}\right) = 2.5
So, the height is 2.5 cm
➷ Volume = l * w * h
So far we have:
150 = 12 * 5 * h
Divide both sides by (12*5)
h = 2.5 cm
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Answer:
3556b - 48
Step-by-step explanation:
−6(14b+10)+4(910b+3)=
-84b-60+3640b+12=
(3640-84)b+(12-60)=
3556b - 48
choose a second tile. Find the probability of the dependent event(s) both
occurring.
1/2/3/4/5/6/7
-
Choosing a 6 and then a prime number
Choosing two odd numbers
Answer:
Choosing a 6 and then a prime number:2/21
Choosing two odd numbers: 2/7
Step-by-step explanation:
Choosing a 6 and then a prime number:
The probability of choosing 6 out of 1, 2, 3, 4, 5, 6 and 7 is one event divided by number of total events (which is equal to 7). That results in 1/7. Once 6 is chosen, the probability of choosing a prime number (prime number is a number that can only be divided by 1 and itself) out of 1, 2, 3, 4, 5 and 7 is 4/6 (prime numbers are 2, 3, 5, 7 in total there are 4 number and total number of events are 6). Finally, the probability of choosing a 6 and then a prime number is (1/7)*(4/6)=2/21.
Choosing two odd numbers:
The probability of choosing 1st odd number is 4/7 (number of odd numbers is 4 which includes 1, 3, 5, 7 and the number of total events is 7). Once 1st odd number is chosen, the probability of choosing 2nd odd number is 3/6 (number of odd numbers is 3 - because 1 odd number is already chosen and the number of total events is 6). Finally, the probability of choosing two odd numbers in a sequence is (4/7)*(3/6)=2/7.