MATHEMATICS HIGH SCHOOL

Ahmad has $x. Abu has $5 more than Ahmad. Razak has twice as much as Abu. Together they have $175. What is the value of x?

Answers

Answer 1

Answer: Abu X + 5

Razak 2x + 10

Ahmad X

Together 4x + 15

175 - 15 = 160

160 / 4 = 40

X = 40

Answer 2

Answer:

Answer:$40

Step-by-step explanation:

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Marcia will make a frame for her picture the length of the picture is 15 inches the width is one third of the length how much wood does marcia need for

Answers

the answer to that would be 5 !!!!

Ten times the sum of half a number and 6 is 8

Answers

10 times the sum of 1/2 of a number and 6 means 10(x/2+6)
is 8
=8

10((x/2)+6)=8
divide both sides by 10
(x/2)+6=0.8
minus 6 from both sides
x/2=5.4
times both sides by 2
x=10.8

Find the greatest common factor 15x^2 y^3, and -20x^3 yz.

Answers

Answer:

$5x^2y$

Step-by-step explanation:

We are given that two terms are

$15x^2y^3, -20x^3yz$

We have to find the GCF of given terms

$15x^2=3* 5* y* y* y* x* x$

$-20x^3yz=-2* 2* 5* x* x* x* y* z$

GFC= $5* x* x* y$

GCF= $5x^2y$

Answer: $5x^2y$

15x^2y^3=3*5*x*x*y*y*y
-20x^3yz=-1*2*2*5*x*x*x*y*z
comon numbers are
5,x,x,y

greatest common factor is 5x^2y

the length of a garden is 4 m longer than the width. if the area of the garden is 196m^2, find the width of the garden.

Answers

l = 4 + w
w = w
A = 196 m^2

A = lw
A= (4+w)w
196 = w^2 +4w

w^2 + 4w - 196 = 0

The quadratic roots (or zeros) of the function are 12 and -16.

Since -16 does not make sense as a measure of width, then 12 is the answer.

What is the answer for
80=30t

Answers

Answer:

t = 8/3

Step-by-step explanation:

80 = 30t

t = 80/30

t = 8/3

Answer: t = 8/3

Step-by-step explanation:

divide 30 on both sides: t=80/30

t = 8/3

Write an equation of the line in point-slope form through each pair of points (9,5) and (8,2) A) y+5=3(x+9)
B )y+5=1/3(x+9)
C) y-5=3(x-9)
D) y-5=1/3(x-9)

Answers

$\bf (\stackrel{x_1}{9}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{9}}}\implies \cfrac{-3}{-1}\implies 3 \n\n\n \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\n \cline{1-1} \n y-y_1=m(x-x_1) \n\n \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{3}(x-\stackrel{x_1}{9})$

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