Answer:
the significant figures of the number 0.0560 is 3.
Step-by-step explanation:
Significant figure is the number of non-zero digits.
The given number is 0.0560
Now, we know that leading zeros are not significant.
Hence, we count the number of digits after the decimal excluding 0.
So there are 3 digits 5,6 and 0.
Hence, we can conclude that the significant figures of the number 0.0560 is 3.
P(Both defective) = 49/2500
P(Both defective) = 3/175
P(Both defective) = 7/25
feet.
height (h)= 7+37x-16x^2
h/7.00 > 210.00; h> 30; 30 hours h/7.00 < 210.00; h < 30; 30 hours 7.00h≥ 210.00; h≥ 30; 30 hours** 7.00h≤ 210.00; h ≤ 30; 30 hours
Answer:
17.) D.) 55 + m ≥ 65; m ≥ 10
18.) C.) 7.00h≥ 210.00; h≥ 30; 30 hours
Explanation:
I took the test, also your answers were right.
Answer: The contrapositive of the statement is
"If a number is not divisible by 10, then it does not end with 0".
Step-by-step explanation: We are given to write the contrapositive of the following statement:
"If a number ends with 0, then it is divisible by 10".
We know the contrapositive of a conditional statement of the form
"If p then q" is given by "If not q then not p".
Or,
the contrapositive of "p ⇒ q" is "~q ⇒ ~p".
So, the contrapositive of the given statement is
"If a number is not divisible by 10, then it does not end with 0".
Thus, the contrapositive of the statement is
"If a number is not divisible by 10, then it does not end with 0".
The graph will not pass through quadrant II, because the slope is positive and the y-intercept is negative. The correct option is B.
The word "linear function" in mathematics refers to two different but related ideas: In calculus and related fields, a linear function is a function whose graph is a straight line, i.e., a polynomial function of degree zero or one.
Given function is y = ( -6 + ( 2 / 3 ) x. By plotting the graph on the coordinate axis it is observed that the graph of the function passes through the first third and fourth quadrants.
The coordinates of the graph cutting on the x and y axis are ( 9, 0 ) and ( 0, -6). The graph of the linear equation is attached with the answer below.
Therefore, the graph will not pass through quadrant II, because the slope is positive and the y-intercept is negative. The correct option is B.
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Answer:
Quadrant II, because the slope is positive and the y-intercept is negative, I just took the test.
Step-by-step explanation: