How do i find displacement on a position time graph ?

Answers

Answer 1

Answer: Displacement is just the distance between the start-point and the end-point,
regardless of the route that was traveled on the way.

If you're asked to find a displacement, then the first thing the asker has to do
is define the part of the graph that he's interested in.The easiest way to do that
is to specify the start-time and end-time. Once you have those, the displacement
is easy. Just look at the graph. Find the position at the end, and the position
at the beginning. Subtract the beginning position from the ending position, and
that's the displacement.

Ignore everything in between. No matter how many curves, curls, breaks, or
stops the graph may have on the way, you don't care. The displacement is just
the difference between the end position and the start position.

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What is the purpose of a core in an electrmagnet

Answers

Answer:

The purpose of a core in an electromagnet is to enhance the magnetic field strength produced by the electromagnet. The core is typically made of a ferromagnetic material, such as iron or steel, that can easily magnetize and demagnetize.

When an electric current flows through a wire wrapped around the core, a magnetic field is generated. This magnetic field is concentrated and strengthened by the core material. The core acts as a pathway for the magnetic field lines to flow through, making the electromagnet stronger and more efficient.

The core helps to increase the magnetic flux density, which is the amount of magnetic field passing through a given area. By concentrating the magnetic field, the core allows the electromagnet to exert a stronger force on nearby magnetic objects, such as attracting or repelling other magnets or moving metal objects.

To visualize this, think of the core as a "magnetic conductor" that channels and focuses the magnetic field. It's like using a magnifying glass to concentrate sunlight onto a small spot, making it hotter and more intense. Similarly, the core enhances the strength of the magnetic field produced by the electromagnet.

In summary, the purpose of a core in an electromagnet is to increase the magnetic field strength by providing a pathway for the magnetic field lines to flow through. This makes the electromagnet more powerful and allows it to perform various tasks, such as lifting objects, generating electricity, or controlling mechanical devices.

Please brainlist me

Answer:

Purpose of a core in an electromagnet to increase the strength, efficiency, and size of the magnetic field.

Explanation:

An electromagnet is a type of magnet in which the magnetic field is produced by an electric current. Electromagnets usually consist of wire wound into a coil. A current through the wire creates a magnetic field which is concentrated in the hole in the center of the coil.

The purpose of a core in an electromagnet is to concentrate the magnetic field.

The coil of wire that creates the magnetic field in an electromagnet is typically made of copper, which has a relatively low magnetic permeability. This means that the magnetic field lines tend to spread out in all directions, resulting in a weak magnetic field.

Some of the purposes of using a core in an electromagnet are:

To increased magnetic field strength:
The core concentrates the magnetic field, resulting in a much stronger magnetic field.
To reduced size:
The core helps to confine the magnetic field, which can reduce the size of the electromagnet.
To improved efficiency:
The core helps to direct the magnetic field, which can improve the efficiency of the electromagnet.

Overall, the core in an electromagnet plays an important role in increasing the strength, efficiency, and size of the magnetic field.

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As you jump on a pogo stick where is the potential energy the greatest?

Answers

The potential energy would be greatest at the highest point of the jump; the kinetic energy equaling 0.

An object is thrown downward with an initial velocity of 3 feet per second. The relationship between the distance s it travels and time t is given by s = 3t + 16t2. How long does it take the object to fall 70 feet?

Answers

Answer:2 s

Explanation:

Given

initial velocity $u=3 ft/s$

distance travel $s=3t+16t^2$

time taken to travel 70 feet

$70=3t+16t^2$

$16t^2+3t-70=0$

using $x=(-b\pm √(b^2-4ac))/(2a)$ to get roots

$t=(-3\pm √(3^2-4(16)(-70)))/(2\cdot 2)$

t=2 and -2.19

only feasible time is 2 s

thus it requires 2 s to cover 70 feet

What lines the inferior surface of the diaphragm?

Answers

The roof of the abdominal cavity is inferior to the diaphragm.

Two people pull as hard as they can on horizontal ropes attached to a boat that has a mass of 200 kg. If they pull in the same direction, the boat has an acceleration of 1.42 m/s2 to the right. If they pull in opposite directions, the boat has an acceleration of 0.509 m/s2 to the left. What is the magnitude of the force each person exerts on the boat

Answers

Answer: 192.9N and 91.1N

Explanation:

Let the force exerted by one person = X

Let the force exerted by the other person = y

Then, we can create equations

When both persons pull in the same direction, then

X + Y = 200 * 1.42

When both persons pull I'm opposite directions, then

X - Y = 200 * 0.509

Now we have

X + Y = 284

X - Y = 101.8

When we add the 2 equations together, we get

2X = 385.8

X = 385.8/2

X = 192.9

If x = 192.9, then, y = 284 - x

Y = 91.1

Therefore, one person exerts 192.9N, and the other exerts 91.1N

A speeder passes a parked police car at a constant speed of 23.3 m/s. At that instant, the police car starts from rest with a uniform acceleration of 2.75 m/s 2 . How much time passes before the speeder is overtaken by the police car? Answer in units of s.

Answers

Answer:

32s

Explanation:

We must establish that by the time the police car catches up to the speeder, both have travelled a certain distance during the same amount of time. However, the police car experiences accelerated motion whereas the speeder travels at a constant velocity. Therefore we will establish two formulas for distance starting with the speeder's distance:

$x=vt=23.3(m)/(s)t$