taxable income last year?
A. $5262.03
B. $437.97
C. $0
D. $3212.03
The part-time shelf stocker's taxable income is calculated by subtracting the exemption of $3650 and the standard deduction of $5700 from her annual income of $8912.03, resulting in a negative number, which means her taxable income was $0.
To calculate the taxable income for the part-time shelf stocker who made $8912.03 last year, we need to subtract the exemption and standard deduction from her annual income. The exemption claimed is $3650, and the standard deduction is $5700.
Here's the calculation:
Since the taxable income cannot be negative, the correct answer is $0. Thus, her taxable income last year was $0.
#SPJ2
Answer: C) $0
Step-by-step explanation:
Demon slayer
Answer:
a)
And rounded up we have that n=551
b)
And rounded up we have that n=494
Step-by-step explanation:
Previous concept
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The population proportion have the following distribution
Solution to the problem
In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by and . And the critical value would be given by:
Part a
The margin of error for the proportion interval is given by this formula:
(a)
And on this case we have that and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
We can assume that since we don't know prior info. And replacing into equation (b) the values from part a we got:
And rounded up we have that n=551
Part b
And rounded up we have that n=494
To determine the required sample size for the survey, we can use a sample size formula based on the desired confidence level and margin of error. If nothing is known about the passenger preferences, a sample size of 549 would be needed. If a prior survey suggests a certain proportion, the sample size can be calculated using the known proportion.
In order to determine the number of randomly selected air passengers that must be surveyed, we need to calculate the required sample size for a desired confidence level and margin of error.
a. If nothing is known about the percentage of passengers who prefer aisle seats, we can use a sample size formula given by n = (Z^2 * p * q) / E^2, where Z is the z-score corresponding to the desired confidence level, p and q are the estimated proportions for aisle seat preference and non-aisle seat preference respectively, and E is the desired margin of error. Since a confidence level of 99% and a margin of error of 5.5% are specified, we can round up the sample size to 549.
b. If a prior survey suggests that about 34% of air passengers prefer an aisle seat, we can use the same sample size formula but with the known proportion p = 0.34. We do not have information about the non-aisle seat preference, so we cannot determine the required sample size.
#SPJ11
Answer:
13/8
Step-by-step explanation
Since the denominator is the same, you keep it. Then you just add 6 and 7 which is 13.
~
=> Property used = distributive property.
for that two lines be parallel the condition is that two slope be equal m1 = m2
Now you must calculate with point givens both slope , with the following formula
m= y2-y1/ x2-x1, for the firsts two points P( -7,0) and Q( 6,-5)
m = -5-0/6-(-7) , m = -5/13
for the seconds points R (-1,-1) and S( 0,-4)
m = -4-(-1)/ 0-(-1) = -3/1 = -3
the lines are not parallel, m1 ≠ m2