A scientist found that a Petri dish from an experiment had not been cleaned several days earlier. In the dish, she discovered a bacterial culture that she had not seen during the experiment. How could she gather evidence to support a claim about whether the bacteria had developed from the material left from the earlier experiment? a)Take a sample of the bacteria and grow it in an incubator. b)Gather dirty Petri dishes from other labs to see if they grow the same bacteria. c)Check all the clean Petri dishes for residue from the previous experiment. D)Try the original experiment again, do not clean some of the Petri dishes, and see if the bacteria grow.

Answers

Answer 1

Answer:

Answer:

Explanation:

The best way she can gather evidence to support a claim of the bacteria developing from the material left from the earlier experiment would be to repeat the original experiment again, leave some of the Petri-dishes uncleaned, and then see if the same bacteria would grow on the uncleaned Petri dishes.

If indeed the bacteria developed from the material left from the earlier experiment, the same bacteria should grow on the uncleaned Petri dishes in the second experiment. If they do not grow, it means that the source of the bacteria is from somewhere else within the lab.

The correct option is D.

Answer 2

Answer:

Answer: D

Explanation:

I had this same question before. Hope it helps:)

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Explain competing theories about the formation of Earth's oceans.

Answers

Answer:

1. volcanic and rock outgassing of the early Earth

2. comet impacts during the "heavy-bombardment period"

Explanation:Hope This Helps:)

A student conducts an experiment to determine how the amount of water given to a plant affects its growth. What is the dependent variable for this experiment? a. the amount of water b. the height of the plant c. the amount of sunlight d. the amount of soil Please select the best answer from the choices provided

Answers

Answer: b. the height of the plant.

In an experimental set up an independent variable is the one which can be manipulated or change to observe the effects of such changes or manipulation on dependent variable. For example, plant growth is a dependent variable because it is dependent on independent variables such as amount of sunlight available, amount of fertilizers and water provided.

In this experiment, it is to be determined that how the amount of water given to a plant affects its growth. Here, water is an independent variable which can be change in the experiment and the affect of change can be observed on plant growth which is a dependent variable. A height represents the growth of the plant therefore, height of the plant is the dependent variable.

I think the answer to this is the height of the plant. The amount of water is the independent variable and the amount of sunlight and soil arent included in this experiment.

Use the template of a replication fork to draw arrows that represent both continuous and discontinuous DNA synthesis. Draw one long arrow to show continuous DNA synthesis and three arrows to show discontinuous DNA synthesis. The arrows should point in the direction of nucleotide addition, and the three arrows showing discontinuous synthesis should be numbered 1, 2, and 3, in the order of fragment synthesis.

Answers

Answer: seen below

Explanation:

Deoxyribonucleic acid (DNA) synthesis is the biological process by which DNA molecule is created. In the cell, each of the two strands of the DNA molecule acts as a template for the synthesis of a complementary strand. This strands are separated during replication (DNA replication is the biological process of producing two identical replicas of DNA from one original DNA molecule). DNA polymerase synthesizes the new strands by adding nucleotides that complement each (template) strand.

Deoxyribonucleic acid (DNA) synthesis is continuous because extension of a single ribonucleic acid (RNA) primer occurs without interruption into the replication fork as it continues to open to the right as seen on the diagram below. On the upper lagging strand which is the discontinuous synthesis, here synthesis is discontinuous, since new RNA primers must be added as opening of the replication fork continues to expose new template.

How many different ways does/could energy change form during its travels between the Sun and your stomach?

Answers

Energy will take the path from sun to stomach as sun's energy to chemical energy followed by thermal and mechanical energy.

Explanation:

The energy of the sun is in the from of chemical energy which is the ultimate basis of life on earth . The process of photosynthesis occurs to form a chemical compound named glucose. The food ingested is in polymer complex forms as protein, carbohydrate, fats etc which is broken into monomers for absorption in intestine and stomach.

The dietary compound has energy stored in their bonds as chemical energy.

So, from sun human consume chemical energy which is stored in food.

The energy even if consumed by eating meat is also chemical energy which is stored as potential energy.

The breakdown of food or chemical energy into monomers leads to release of thermal energy or heat to maintain optimum body temperature.

Chemical energy also gets converted to mechanical energy which allows functioning of vital organs and movement of body.

All of the following statements about glycolysis are true except: A) Glycolysis has steps involving oxidation-reduction reactions.
B) The enzymes of glycolysis are located in the cytosol of the cell.
C) Glycolysis can operate in the complete absence of O2.
D) The end products of glycolysis are CO2 and H20.
E) Glycolysis makes ATP exclusively through substrate-level phosphorylation.

Answers

Answer:

Explanation:

The end product of glycolysis is pyruvate. This process occurs in the cytosol of the cell in the absence of oxygen and has a net ATP production of 2 and 2 NADH. When there is no oxygen, the pyruvate is converted to lactic acid. When there is oxygen , the pyruvate is channeled to the Krebs cycle in the mitochondria where it is used to produce more ATP. The formation of ATP in glycolysis is powered by the energy in the bonds of the molecules (substrate-level phosphorylation). This is unlike in Krebs cycle where most of ATP are formed through oxidative phosphorylation. The end products of Krebs cycle is CO₂ and H₂O.

All of the following statements about glycolysis are true except the one that states- The end products of glycolysis are CO2 and H2O. So the correct option is option D.

The glycolysis process can take place when there is oxygen present (aerobic) or when there is no oxygen present (anaerobic). Pyruvate is transformed into lactic acid in anaerobic conditions. The fact that glycolysis occurs widely in other species suggests that it is an old metabolic pathway.

Glycolysis in most cells takes place in the cellular cytosol. The process of glycolysis can be divided into two stages: the investment stage, in which ATP is initially consumed, and the yield stage, in which more ATP is eventually produced.

To learn more about glycolysis, refer to the link:

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Transcription and Translation Practice Worksheet
Example:
DNA : G T A C G C G T A T A C C G A C A T T C
mRNA: C A U G C G C A U A U G G C U G U A A G
Codons: AUG-CGC-AUA-UGG-CUG-UAA
Anticodons: UAC-GCG-UAU-ACC-GAC-AUU
Amino Acids: Methionone-Arginine-Isoleucine-Tryphtophan-Leucine
Using the example above, transcribe the following DNA strand into mRNA and translate that strand into a polypeptide chain, identifying the codons, anticodons, and amino acid sequence.
1. DNA: A T A C G A A A T C G C G A T C G C G G C G A T T C G G
mRNA:
Codon:
Anticodon:
Amino Acids:
2. DNA: T T T A C G G C C A T C A G G C A A T A C T G G
mRNA:
Codon:
Anitcodon:
Amino Acids:
3. DNA: T A C G G G C C T A T A C G C T A C T A C T CA T G G A T C G G
mRNA:
Codon:
Anitcodon:
Amino Acids:
4. DNA: G T A C G C G T A T A C C G A C A T T C
mRNA:
Codon:
Anitcodon:
Amino Acids:
Transcribe the following DNA strand into mRNA and translate that strand into a polypeptide chain, identifying the codons, anticodons, and amino acid sequence.
DNA: C G A T A C A A T G G A C C C G G T A T G C G A T A T C C

Answers

Transcription occurs in the nucleus and translation occurs in the cytosol. Proteins are AUG-CUU-UAG / MET-PRO-VAL-VAL-ARG-ILE-LEU / MET-PRO GLY-TYR-ALA-MET-MET-SER-THR / MET-ALA-TYR-THR-LEU

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Transcription

Transcription occurs in the nucleus. In RNA uracil replaces thymine.

While growing mRNA molecule,

→ adenine pairs uracil,

→ thymine pairs adenine, and

→ guanine pairs cytosine.

Translation

Translation occurs in the cytosol. mRNA codons codify for amino acids.

There is a start Codon AUG and stop codons UAA, UAG, UGA.

DNA: A T A C G A A A T C G C G A T C G C G G C G A T T C G G

mRNA: U A U G C U U U A G C G C U A G C G C C G C U A A G C C

Codon: AUG CUU UAG

here we recognize the start codon and a stop codon very close.

Anticodon: UAC GAA AUC GCG AUC GCG GCG AUU CGG

Amino Acids: MET - LEU

DNA: T T T A C G G C C A T C A G G C A A T A C T G G

mRNA: A A A U G C C G G U A G U C C G U U A U G A C C

Codon: AUG CCG GUA GUC CGU UAU GAC

here we ONLY recognize the start codon but no stop codon.

Anitcodon: UAC GGC CAU CAG GCA AUA CUG

Amino Acids: MET - PRO - VAL - VAL - ARG - ILE - LEU

DNA: T A C G G G C C T A T A C G C T A C T A C T C A T G G A T C G G

mRNA:A U G C C C G G A U A U G C G A U G A U G A G U A C C U A G C C

Codon: AUG CCC GGA UAU GCG AUG AUG AGU ACC UAG

here we recognize the start codon and one stop codon.

Anticodon: UAC GGG CCU AUA CGC UAC UAC UCA UGG AUC

Amino Acids: MET - PRO - GLY - TYR - ALA - MET - MET - SER - THR

DNA: G T A C G C G T A T A C C G A C A T T C

mRNA: C A U G C G C A U A U G G C U G U A A G

Codon: AUG CGC AUA UGG CUG UAA

here we recognize the start codon and one stop codon.

Anticodon: UAC GCG UAU ACC GAC AUU

Amino Acids: MET - ALA - TYR - THR - LEU

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Answer:

Explanation:

1. DNA: A T A C G A A A T C G C G A T C G C G G C G A T T C G G

mRNA: U A U G C U U U A G C G C U A G C G C C G C U A A G C C

Codon: AUG-CUU-UAG-CGC-UAG-CGC-CGC-CGC-UAA- GCC

Anticodon: UAC-GAA-AUC-GCG-UAC-GCG-GCG-GCG-AUU-CGG

Amino Acids: Methionine-Leucine-Stop.

2. DNA: T T T A C G G C C A T C A G G C A A T A C T G G

mRNA: A A A U G C C G G U A G U C C G U U A U G A C C

Codon: AUG-CCG-GUA-GUC-CGU-UAU-GAC

Anitcodon: UAC-GGC-CAU-CAG-GCA-AUA-CUG

Amino Acids: methionine-glycine-histidine-glutamine-alanine-isleucine-leucine

3. DNA: T A C G G G C C T A T A C G C T A C T A C T CA T G G A T C G G

mRNA: A U G C C C G G A U A U G C G A U G A U G A G U A CC U A G C C

Codon: AUG-CCC-GGA-UAU-GCG-AUG-AUG-AGU-ACC-UAG

Anitcodon: UAC-GGG-CCU-AUA-CGC-UAC-UAC-UCA-UGG-AUC

Amino acids: Methionine-glycine-proline-tyrosine-alanine-methionine-methionine-serine-threonine.

4. DNA: G T A C G C G T A T A C C G A C A T T C

mRNA: C A U G C G C A U A U G G C U G U A A G

Codon: AUG-CGC-AUA-UGG-CUG-UAA

Anitcodon: UAC-GCG-UAU-ACC-GAC-AUU

Amino Acids: Methionine-arginine-isoleucine-tryptophan-leucine

5. DNA: C G A T A C A A T G G A C C C G G T A T G C G A T A T C C

mRNA: G C U A U G U U A C C U G G G C C A U A C G C U A U A G G

CODON: AUG-UUA-CCU-GGG-CCA-UAC-GCU-AUA

Anticodons- UAC-AAU-GGA-CCC-GGU-AUG-CGA-UAU

Amino acids: Methionine-leucine-proline-glycine-proline-tyrosine-alanine-isoleucine.

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Keeping in mind the life cycle of bacteriophages, consider the following problem: During the reproductive cycle of a temperate bacteriophage, the viral DNA inserts into the bacterial chromosome where the resultant prophage behaves much like a Trojan horse. It can remain quiescent, or it can become lytic and initiate a burst of progeny viruses. Several operons maintain the prophage state by interacting with a repressor that keeps the lytic cycle in check. Insults (ultraviolet light, for example) to the bacterial cell lead to a partial breakdown of the repressor, which in turn causes the production of enzymes involved in the lytic cycle. As stated in this simple form, would you consider this system of regulation to be operating under positive or negative control?

Pink eye is a recessive trait found in deer mice. In a cross between two individuals, both of whom are heterozygous for the pink eye mutation, the following offspring are obtained:Normal 18Pink eye 2Use the chi-square test to determine if the observed numbers of offspring fit the expected numbers of offspring from this cross. The value of is: ____________

Why is oceanic crust subducted under continental crust?A. Oceanic crust is moving faster than continental crust.B. Oceanic crust is denser than continental crust.C. Oceanic crust is less dense than continental crust.D. Oceanic crust is older than continental crust.

Phosphofructokinase, a controlling enzyme of glycolysis, is inhibited by ___ and activated by ___.