MATHEMATICS MIDDLE SCHOOL

A candy company packaged boxes of candy. Each box held 60 ounces ofcandy. On Tuesday, the candy company produced 2,828 ounces of candy.
How many boxes of candy can the company completely fill on Tuesday?

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

You need to divide the candy evenly into boxes, so you would divide 2,828 by 60.

2,828/60=47.13

The company would package the candy into 47 boxes that would completely fill up.

Hope this helps! Have a nice day c:

Related Questions

sela put 6 times as many coins now as she had 4 months ago. if sela has 240 coins now, how many did she have 4 months ago

Answers

Sela had 40 coins 4 months ago because 240 divided by six is 40.

she put 24 coins 4 months ago because 6 times 4 is 24.

Find the reciprocal of the number. Multiply to check your answer.2/3

A.1/2

B.3/2

C.2

D.3

Answers

To find the reciprocal of a fraction, you just need to "flip" it. To check your work, you multiply the fraction and the reciprocal to get 1.

the reciprocal if 2/3 is 3/2

$(2)/(3) * (3)/(2) = (6)/(6) = 1$

The answer is B

i think it would be B

Write 7340 in standard form

Answers

seven thousand three hundred and forty

7,340 is in standard form

7000+300+40 is in expository form

Seven thousand, three hundred forty
Word form

Hope i helped

And ur welcome for those who say thanks

If A+D=117kg , A+M=88kg and M+D=161kg whats there total weight

thx in advance

Answers

Think of A as a constant - with D it's 117 and with M it's 88

So the difference between D and M is 29 (117-88)

We also know that M + D = 161

Let's substitute in the problem We will leave M equal to M and rewrite D as M+29 since it is 29 kg heavier.
M + M + 29 -161 or 2M +29 = 161 Subtracting 29 from both sides we get 2M=122
Now divide both sides two and get M=61
Since D is M+29 it is 61+29 or 100kg
Finally A + M = 88 A + 61 - 88 Subtract 61 from both sides and get A=17
So there you have it:
A=17kg
M=61kg
D=100kg and it works in all three equation in your problem (try it to check)

There's actually a really slick solution to this problem.Add all three equations. This results in 2(A+M+D)=366. Dividing by two, we see that A+M+D=183, so 183 is the total of the weights.

How many solutions does the equation have?3(4x-3)-7x=5x-9

A.
one solution

B.
infinite solutions

C.
no solution