While hiking, Sandra went up 120 meters. If Sandra started at 800 meters above sealevel, what is her elevation now?

Answers

Answer 1
Answer:

The Answer:

If Sandra started at 800 meters and went up 120, the answer would be 920.

Step-by-step explanation:

First, simply add 800 meters, which is what she started with. Next, since she has gone up 120 meters since then, and the question is asking us what her elevation is NOW, you can add 800 + 120 to get 920. This question is solved by using addition.

Hope this helps!

Answer 2
Answer: Sandra is 920 meters above sea level


You would add 120 and 800 which is 920

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I need help with this math problem please (3x+2)(5x-7)

Answers

Answer:

Hey there!

Using the foil method: (3x+2)(5x-7)

15x^2+10x-21x-14

15x^2-11x-14

Let me know if this helps :)


Here’s your answer (3x+2)x(5x-7)

1. What is the width of a piece of paper in meters and millimeters if it is 20 centimeters?2.What is the height of a woman in centimeters and millimeters if it is 1.52 meters?

Answers

Answer:

1. 0.20 m, 200 mm

2. 152 cm, 1520 mm

Step-by-step explanation:

You may be familiar with a place-value chart that names the digits of a number based on their relationship to the decimal point. It might look like ...

  (units) . (tenths) (hundredths) (thousandths)

So a number like 0.2 units can be rewritten in terms of hundredths or thousandths like this:

  0.200 units = 20.0 hundredths = 200. thousandths

The name that's attached depends on where you put the decimal point.

___

When the units are meters, the corresponding names are ...

  (meters) . (decimeters) (centimeters) (millimeters)

1. That is 0.200 meters = 20.0 centimeters = 200. millimeters.

2. 1.520 meters = 152.0 centimeters = 1520. millimeters.

Before 1918, approximately 40% of the wolves in a region were male, and 60% were female. However, cattle ranchers in this area have made a determined effort to exterminate wolves. From 1918 to the present, approximately 60% of wolves in the region are male, and 40% are female. Biologists suspect that male wolves are more likely than females to return to an area where the population has been greatly reduced. (Round your answers to three decimal places.) (a) Before 1918, in a random sample of 10 wolves spotted in the region, what is the probability that 7 or more were male

Answers

Answer:

P(≥ 7 males) = 0.0548

Step-by-step explanation:

This is a binomial probability distribution problem.

We are told that Before 1918;

P(male) = 40% = 0.4

P(female) = 60% = 0.6

n = 10

Thus;probability that 7 or more were male is;

P(≥ 7 males) = P(7) + P(8) + P(9) + P(10)

Now, binomial probability formula is;

P(x) = [n!/((n - x)! × x!)] × p^(x) × q^(n - x)

Now, p = 0.4 and q = 0.6.

Also, n = 10

Thus;

P(7) = [10!/((10 - 7)! × 7!)] × 0.4^(7) × 0.6^(10 - 7)

P(7) = 0.0425

P(8) = [10!/((10 - 8)! × 8!)] × 0.4^(8) × 0.6^(10 - 8)

P(8) = 0.0106

P(9) = [10!/((10 - 9)! × 9!)] × 0.4^(9) × 0.6^(10 - 9)

P(9) = 0.0016

P(10) = [10!/((10 - 10)! × 10!)] × 0.4^(10) × 0.6^(10 - 10)

P(10) = 0.0001

Thus;

P(≥ 7 males) = 0.0425 + 0.0106 + 0.0016 + 0.0001 = 0.0548

An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with μ = 44 and σ = 5.0. (a) What is the probability that yield strength is at most 40? Greater than 62? (Round your answers to four decimal places.) at most 40 greater than 62 (b) What yield strength value separates the strongest 75% from the others? (Round your answer to three decimal places.)

Answers

Answer:

Step-by-step explanation:

Using normal distribution,

z = (x - μ)/σ

μ= mean = 44 and

σ = standard deviation= 5.0

a) The probability that yield strength is at most 40=

P( x lesser than or equal to 40)

z = (40-44)/5= -0.8

Looking at the normal distribution table,

P( x lesser than or equal to 40) =0.2119

b) P(x greater than 62) = 1 - P(x lesser than or equal to 62)

z = (62-44)/5= 3.6

Looking at the normal distribution table,

P(x greater than 62) = 1 -0.99984

= 0.00016

c)P( 42 lesser than or equal to x lesser than or equal to 62)

= P(x lesser than or equal to 62) - P( x lesser than or equal to 40)

= 0.99987-0.2119= 0.78797

d) What yield strength value separates the strongest 75% from the others.

To get x for strongest 75, we get the z value corresponding to 0.75 from the table

z = 0.675= (x-44)/5

x = 3.375+44 = 47.375

The rest is 25% = 0.25

we get the z value corresponding to 0.25 from the table)

z = -0.67 = (x-44)/5

-3.35= x -44

x = -44+3.35= 40.65

yield strength value that separates the strongest 75% from the others

=47.375-40.65= 6.725

Final answer:

The probability that the yield strength is at most 40 is approximately 0.2119 and the probability that it is greater than 62 is approximately 0.0001. The yield strength value that separates the strongest 75% from the others is approximately 40.628 ksi.

Explanation:

This question is about calculating probabilities and percentiles using the properties of the normal distribution. The yield strength for the A36 grade steel is normally distributed with a mean (μ) of 44 and a standard deviation (σ) of 5.0.

(a) To find the probability that the yield strength is at most 40, we will need to calculate the Z-score value for the yield strength of 40. The Z-score can be calculated using the following formula: Z = (X - μ) / σ , where X is the observed value, μ is the mean, and σ is the standard deviation. For X = 40, μ = 44, and σ = 5.0, the Z-score is -0.8. Looking up the Z-score in the standard normal distribution table, the probability that the yield strength is at most 40 is approximately 0.2119. Using a similar process, we find that the probability that the yield strength is greater than 62 is less than 0.0001, very close to zero.

(b) To determine the yield strength value that separates the strongest 75% from the others, we find the Z-score that corresponds to a cumulative probability of 0.25 in the standard normal distribution table (because the strongest 75% corresponds to the weakest 25%). That Z-score is approximately -0.6745. Using the formula Z = (X - μ) / σ to solve for X gives us X = σZ + μ  = 5.0 * -0.6745 + 44 = 40.6275, which rounded to three decimal places is 40.628.

Learn more about Normal Distribution here:

brainly.com/question/34741155

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You have 14 gallons of lemonade to sell. You use cone-shaped cups that are 9 centimeters in diameter and 11 centimeters tall. Eachcustomer uses one paper cup. How many paper cups will you need if you sell all of the lemonade? (1 gal = 3785 cm)

Answers

Answer:

You need to sell approximately 119 paper cups to sell all of the lemonade.

Step-by-step explanation:

80 total students 6/2 are girls how many are girls

Answers

Answer:

60

Step-by-step explanation: