10. The ratio of the number of male employees to the number of female employees in Westlake high school is 6:5. There are 40 females in the school. How many total employees are in Westlake high school?

Answers

Answer 1
Answer:

Answer:

45

Step-by-step explanation:

Male = 6          Male = ?

Female = 5      Female = 40

                                         ^

? = 6x5 because 5x5 = 40


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Determine whether or not the two equations below have the same solution. In two or more complete sentences, explain your rationale.2/3x + 3/4 = 8 8x=87
Solve for x: −2x + 5 < 7

What is the slope of the line? (4,4) and (1,1)

Answers

you would put 4-1 over 4-1 so the slope would be 3/3 which is one 
so slope=1
1-4 / 1-4
-3 / -3
1
The slope is 1

Simplify 3 1/5 + 4/16

Help asap!!!

Answers

Answer:

3 1/5 = 16/5

4/16 = 1/4

simply and find a common denominator, in this case it is 20. Multiply the top and bottom by the same number, to get the bottom to twenty. So, to get 5 to 20, you must multiply by 4, so you have to multiply the top by 4 too, which is 64. Do the same for the next fraction.  

16/5 = 64/ 20 (both x4)

1/4 = 5/20 (both x5)

now add

64/20 + 5/20 = 69/20

69/20 is the final answer because it cannot be simplified futher.

Answer:

Step-by-step explanation:

3 1/5 + 1/4

3 4/20 + 5/20

3  9/20

A root of x2 – 5x – 1 = 0 is

Answers

Hello,

Roots are (5+√(29))/(2)\ and\ (5-√(29))/(2)

Δ=(-5)²-4*(-1)*(1)=29

Mr. Morgan has five daughters. They were all born the number of years apart as the youngest daughter is old. The oldest daughter is 12 years older than the youngest. What are the ages of Mr. Morgan's daughters?

Answers

Representing the scenario as an equation,the ages of Mr. Morgan's daughters are 3,6,9,12 and 15.

Given the parameters:

  • Number of daughters = 5

owing to constant difference between their ages :

  • Let 'oldest' = 5a , 'youngest' = a

Since we are told that the difference between the ages of the youngest and oldest is 12 :

  • 5a - a = 12

5a - a = 12

4a = 12

a = 12/4

a = 3

Youngest is 3 ;

oldest = 5(3) = 15

The ages of the other 3 will be ;

  • 3 * 2 = 6
  • 3 * 3 = 9
  • 3 * 4 = 12

Hence, their ages are 3,6,9,12 and 15.

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x, 2x, 3x, 4x, 5x

5x - x = 12

x = 3

The youngest is 3 and the oldest is 15.

The ages are: 3, 6, 9, 12, 15

A young boy dropped his deck of baseball cards. Unwilling to count them again he remembered that when he put them in piles of two, there was one card left over. When he put them in stacks of three, there was one card left over. The same thing happened for stacks of 4, 5, 6, but when he put them in stacks of 7, there were no cards left over!How many cards did the boy have? Is there only one possibility? Can you generalize a solution?

Answers

so if he put them in 2 stacks and there was 1 card left over, he has an odd number of cards

when he put them in 3 stacks there was 1 card left over
      we can tell that if he took away one of his card and divided 
     the stack of cards by two or three the number would be the
     same

so he divides it by 4 5 and 6 so the number of cards is not divisible by 2,3,4,5,6
but it is divisable by 7
so we must find a number that when you subtract one you can divide it by 2,3,4,5,6
so i just guessed a term from 7^n
so 49 doesn't work because 48 doesn't divide into 5
343 doesn't work because 342 doesn's divide by 6
but 2401 (7^4) works because 2400 divides evenly by 2,3,4,5, and 6

Just a note, this number is not very logical that he would have time to count them all but hey, it's math


 

Solve the inequality. |3x + 6| < 12A. –6 > x > 2

B. –2 < x < 2

C. –6 < x < 2

D. –21 < x < 3

Answers

The solution to the inequality |3x + 6| < 12 is -6 < x < 2, which corresponds to option C.

To solve the inequality |3x + 6| < 12, we can break it down into two separate inequalities:

3x + 6 < 12

-(3x + 6) < 12

Solving the first inequality:

3x + 6 < 12

Subtracting 6 from both sides:

3x < 6

Dividing both sides by 3 (since 3 is positive, we don't need to change the direction of the inequality):

x < 2

Solving the second inequality:

-(3x + 6) < 12

Distributing the negative sign:

-3x - 6 < 12

Adding 6 to both sides:

-3x < 18

Dividing both sides by -3 (since -3 is negative, we need to change the direction of the inequality):

x > -6

Combining the solutions from both inequalities, we have:

-6 < x < 2

Therefore, the correct option is C. -6 < x < 2.

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Hello,

Answer C

if 3x+6>0 then |3x+6|=3x+6
==> 3x+6<12==>3x<9==>x<2
else
|3x+6|=-3x-6
-3x-6<12==>-3x<18==>x>-6

-6<x<2