Answer:
0.1554
Step-by-step explanation:
.37x.42=.1554
To find the product of 0.37 and 0.42, multiply the numbers together. The missing digits in the empty boxes should be 5 and 4, respectively.
To find the product of 0.37 and 0.42, you need to multiply the two numbers together. The empty boxes represent the missing digits after the decimal point.
The first number, 0.37, has two decimal places, and the second number, 0.42, has two decimal places as well. When you multiply these two numbers, you need to make sure the total number of decimal places in the product matches the sum of the decimal places in the original numbers.
The product of 0.37 * 0.42 is 0.1554. So, the missing digits in the empty boxes should be 5 and 4, respectively.
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house in Kenton County, what is the probability the house size is:
a. over 1371 square feet?
O Z=
o probability =
b. under 1296 square feet?
O Z=
o probability =
c. between 773 and 1637 square feet?
o zl =
o Z2 =
o probability =
Note: Z-scores should be rounded to 2 decimal places & probabilities should be
rounded to 4 decimal places.
License
Points possible: 8
This is attempt 1 of 3.
Answer:
(a) The probability that the house size is over 1371 square feet is 0.4483.
(b) The probability that the house size is under 1296 square feet is 0.3974.
(c) The probability that the house size is between 773 and 1637 square feet is 0.9344.
Step-by-step explanation:
We are given that the sizes of houses in Kenton County are normally distributed with a mean of 1346 square feet with a standard deviation of 191 square feet.
Let X = the sizes of houses in Kenton County
The z-score probability distribution for the normal distribution is given by;
Z = ~ N(0,1)
where, = mean size of houses = 1346 square feet
= standard deviation = 191 square feet
(a) The probability that the house size is over 1371 square feet is given by = P(X > 1371 square feet)
P(X > 1371) = P( > ) = P(Z > 0.13) = 1 - P(Z 0.13)
= 1 - 0.5517 = 0.4483
The above probability is calculated by looking at the value of x = 0.13 in the z table which has an area of 0.5517.
(b) The probability that the house size is under 1296 square feet is given by = P(X < 1296 square feet)
P(X < 1296) = P( < ) = P(Z < -0.26) = 1 - P(Z 0.26)
= 1 - 0.6026 = 0.3974
The above probability is calculated by looking at the value of x = 0.26 in the z table which has an area of 0.6026.
(c) The probability that the house size is between 773 and 1637 square feet is given by = P(773 square feet < X < 1637 square feet)
P(773 < X < 1637) = P(X < 1637) - P(X 773)
P(X < 1637) = P( < ) = P(Z < 1.52) = 0.9357
P(X 773) = P( ) = P(Z -3) = 1 - P(Z 3)
= 1 - 0.9987 = 0.0013
The above probabilities are calculated by looking at the value of x = 1.52 and x = 3 in the z table which has an area of 0.9357 and 0.9987 respectively.
Therefore, P(773 square feet < X < 1637 square feet) = 0.9357 - 0.0013 = 0.9344.
Please provide steps
Answer:
x = 50
Step-by-step explanation:
= a straight line is always equal to 180 degrees
= 180 -30 degrees = 150
= 150/3
=50
Answer:
The correct answer is $800.
Step-by-step explanation:
Let the length and width of the field be equal to l meters and b meters respectively and l > b.
Area of the field is given by l × b = 400 square meters.
The river is supposed to be along the longest side so that the price of fencing the other three sides is minimum. Thus the total perimeter of the fence is b+ b+ l = 2b+l.
Total cost for fencing the other sides of the field = $ 10 × (2b + l)
The wall is supposed to be perpendicular to the river and thus the length of the wall is b meters.
Total cost for the wall is $ 20 × b
Therefore, the total price for making the field is given by
C = 10 × (2b + l) + 20 × b
⇒ C = 40b + 10l
⇒ C = + 10l
To minimize the cost we differentiate the cost with respect to l and equate it to zero.
= 0 = - + 10
⇒ = 1600
⇒ l = 40 ; [ negative sign neglected as length cannot be negative ]
⇒ b = 10
The second order derivative of C is positive giving the minimum value of the cost.
Thus the minimum cost required to make the field is given by $800.
To find the lowest possible cost to build the field, we need to determine the dimensions that will yield the minimum perimeter and then calculate the total cost of building the field. By differentiating the cost equation and solving for x, we can find the dimensions that minimize the cost.
To find the lowest possible cost to build the field, we need to determine the dimensions that will yield the minimum perimeter. Since the area of the field is 400 square meters and it will be divided into two equal halves by a brick wall, each half will have an area of 200 square meters. Let's say the length of the field is x meters. Then the width of each half will be 200/x meters.
The perimeter of the field is the sum of the lengths of the three sides:
Perimeter = 2x + 200/x + 200/x
Now, we can define the total cost to build the field as:
Total Cost = Cost of wall + Cost of fence
Cost of wall = 2x * $20 (since there are two halves)
Cost of fence = (2x + 200/x + 200/x) * $10 (since there is a fence on three sides)
Therefore, the total cost is: Total Cost = 2x * $20 + (2x + 200/x + 200/x) * $10.
To minimize the cost, we can differentiate the total cost with respect to x and set it equal to zero:
d(Total Cost)/dx = 0
Simplifying this equation will give us the value of x that minimizes the cost. We can solve this equation to find the minimum cost to build the field.
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Answer:
£43.23
Step-by-step explanation:
8645 cans divided by 72 per kilo is 120.069 kilos of cans
120.069 kilos times 0.36 pounds
Rounded up to 43.23
Answer:
C
Step-by-step explanation:
3x+2-x>8
2x+2>8
2x>8-2
2x>6
x>3
Answer:
C
Step-by-step explanation: