Adrian shops for school clothes and spends a total of $93.42. If the local tax rate is 8%, how much was the cost without taxes?
Answers
Based on the amount that Adrian spent in total, the cost without taxes was $86.50.
The cost of the clothes was $93.42 including tax.
Assuming the original cost is x, the equation is:
Total cost = Original cost x ( 1 + tax)
Solving would give:
93.42 = x × (1 + 8%)
93.42 = 1.08x
x = 93.42 / 1.08
= $86.50
In conclusion, the cost without taxes was $86.50.
Find out more at brainly.com/question/17836987.
Answer:
85.95
Step-by-step explanation:
If the local tax was 8% and we want to know what is was without the tax then we need to do 93.42 times .92
Since money only goes to the hundredths place we need to round there
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Two cyclists, 112 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other, and they meet after 4 hours of riding.a. Write an equation using the information as it is given above that can be solved to answer this problem. Use the variable r to represent the speed of the slower cyclist.b. What are the speeds of the two cyclists? Put both values in the answerbox, separated with a comma, and select the appropriate units.
Answers
random samples = 300 batteries
defective samples = 9 batteries
level of significance = 0.1
Using the P-table values and using the given values, we see that the number of defective batteries are really less than 5%
Answers
Answer:
$2.06
Step-by-step explanation:
$2.99 x 6 = $17.94
$20.00 - $17.94 = $2.06
Hope this helps
Answer: $0.26
Step-by-step explanation:
Cost of 6 pens
= 2.99 x 6
= 17.94
Add sales tax at 10%,
= 17.94 x 1.1
= 19.74
Change due to me
= 20 - 19.74
= 0.26
Answers
Answer:
Step-by-step explanation:
5(-2x -10) = 25(x + 1)
-10x - 50 = 25x + 25
by transposing
-10x - 25x = 25 + 50
-35x = 75
x = -75/35
x = 15/7
or 2.142857..... in decimal
Hope this helps
plz mark as brainliest!!!!!!!
Answers
Answer:
Step-by-step explanation:
Given the expression
we have to tell the above expression is the sum of cube
The sum of cube is of the form
→ (1)
125 is the cube of 5 and 169 is the square of 13
Comparing above with equation (1), we see the given expression is not the sum of cube
125x^3 is the cube of 5x.
169 = 13^2
169 is the square of 13, but not the cube of a rational number.
The statement is false.
Answers
Answer:
338 in
Step-by-step explanation:
If each of the measures shown is the measure from the vertex to the point of tangency, then that measure contributes twice to the perimeter (once for each leg from the vertex to a point of tangency).
2(22 in + 27 in + 22 in + 98 in) = 2(169 in) = 338 in
Answers
Final answer:
In damped harmonic motion, we calculate damping coefficient γ by comparing the periods of damped and undamped motion. For the given situation where the quasi-period is 90% greater than the undamped period, the damping coefficient is approximately 0.7416.
Explanation:
The subject of this question involves Damped Harmonic Motion, a concept in Physics, related to vibrations and waves. The equation given, u'' + γu' + u = 0, describes the motion where γ denotes the damping coefficient. Here, we have to calculate this damping coefficient when the quasi period of the damped motion is 90% greater than the period of the corresponding undamped motion.
To solve this, we must use the relationship between damped and undamped periods. The quasi-period T' of a damped harmonic motion relates to the undamped period T as: T' = T/(sqrt(1 - (γ/2)^2)). Now, given that T' = 1.9T, we can but these two equations together:
1.9 = 1/(sqrt(1 - (γ/2)^2))
Solving this for γ, we get γ ≈ 0.7416. Hence, the damping coefficient γ for which the quasi period of the damped motion is 90% greater than the period of the corresponding undamped motion is approximately 0.7416.
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Final answer:
The value of the damping coefficient γ for which the quasi period of the damped motion is 90% greater than the period of the undamped motion is the one that satisfies γ=2*ω*0.9, where ω is the natural frequency of oscillation.
Explanation:
The given equation is for a damped harmonic oscillator, a physical system that oscillates under both a restoring force and a damping force proportional to the velocity of the system. The damping coefficient γ determines the behavior of the system and in this case, we need to find the value of γ such that the quasi period of the damped motion is 90% greater than the period of the undamped motion.
The period of the undamped motion, T₀, is calculated by the formula T₀=2π/sqrt(ω), where ω is the natural frequency of oscillation. The quasi period of the damped motion, Td, is increased by a factor of 1+η (in this case, 1.9 as the increase is 90%) and calculated by the formula Td=T₀(1+η) = T₀*1.9.
The damping ratio η is determined by the damping coefficient γ as η=γ/2ω. Therefore, by combining these expressions and rearranging the terms, we extract γ from these formulas as γ=2ω*η => γ=2*ω*(0.9). Thus, the value of the damping coefficient γ for which the quasi period of the damped motion is 90% greater than the period of the corresponding undamped motion is the one which satisfies γ=2*ω*0.9.
Learn more about Damped Harmonic Oscillation here:
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