Can you have say from us the aks place

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Answer 1

Answer: I’m confused on whatvyour question is, please elaborate.

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What is the standard form of two hundred fifty three thousandths

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We are given number in words " two hundred fifty three thousandths".

Let us write it in number form: First we would write the number form of "two hundred fifty".

Two hundred fifty = 253.

Now, we need to write three thousandths.

Three thousandths = .003

Now, we need to combine 253 and 0.003.

On combining we get 253.003.

Therefore, two hundred fifty three thousandths in standard form is 253.003.

A carpet company advertises that it will deliver your carpet within 15 days of purchase. A sample of 49 past customers is taken. The average delivery time in the sample was 16.2 days. Assume the population standard deviation is known to be 5.6 days. a. State the null and alternative hypotheses.
b. Using a critical value, test the null hypothesis at the 5% level of significance.
c. Using a p-value, test the hypothesis at the 5% level of significance.
d. What type of error may have been committed for this hypothesis test

Answers

Answer:

a) $H_0: \mu\leq15\n\nH_1: \mu>15$

b) The z-value (1.5) is smaller than z=1.645 (critical value), so it is in the "acceptance region". It failed to reject the null hypothesis.

c) The p-value (0.07) is greater than the significance level (0.05), so it failed to reject the null hypothesis.

d) In this case, the error we may hae comitted is a Type II error (failed to reject a null hypothesis that is false).

Step-by-step explanation:

We have to perfomr a hypothesis test on the mean, with known standard deviation of the population.

a) The null hypothesis is that the deliver time is 15 days or less.

The null and alternative hypothesis are then:

$H_0: \mu\leq15\n\nH_1: \mu>15$

The significance level is defined as 0.05.

b) The critical value of z for a one-side test (rigth side) and a significance level of 0.05 is z=1.645.

If the z-value for this sample is higher than 1.645, it is in the "rejection region".

Calculating the z-value:

$z=(M-\mu)/(\sigma/√(n))=(16.2-15)/(5.6/√(49))=(1.2)/(0.8)=1.5$

The z-value (1.5) is smaller than z=1.645 (critical value), so it is in the "acceptance region". It failed to reject the null hypothesis.

c) The p-value for z=1.5 is:

$P(z>1.5)=0.067$

The p-value (0.07) is greater than the significance level (0.05), so it failed to reject the null hypothesis.

d) There are two types of error:

Type I errors: happen when we reject a null hypothesis that is true.

Type II errors: happen when we failed to reject a null hypothesis that is false.

In this case, the error we may hae comitted is a Type II error.

The null hypothesis at 5% significance level is 1.50

Data;

n = 49
mean = 16.2
standard deviation = 5.6

Null and Alternative Hypothesis

The alternative hypothesis are

$H_-;\mu \leq 15 : H_1 : \mu > 15$

H_o = mean = 15

standard deviation = 5.6 days

using z-test,

n is greater than or equal to 30

Assuming standard deviation is known

$z = (x-\mu)/(\sigma - √(n) ) \nz = (16.2-15)/(5.6/√(49) )\nz = 1.50$

z-critical value is 1.96 at 95% confidence level.

Since z-critical value is greater than the test statistic, so we tail to subject H_o.

There's no evidence that mean delivery time is different from 15 days.

Learn more on hypothesis here;

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Pls help with hw I’m not good at this and I really need answers

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i just finished this unit.

A: false
B: false
C: false
D: true
E: true

A scale drawing has a ratio of 1:75 what does this ratio mean

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Answer:

it means it could be this 1/75 or 1 to 75

Step-by-step explanation:

Use the given data to find the minimum sample size required to estimate a population proportion or percentage. Margin of error: seven percentage points, confidence level 95%, from a prior study,^p is estimated by the decimal equivalent of 42%n=_____ (round to the nearest integer.)

Answers

Answer: 191

Step-by-step explanation:

Formula to find the minimum sample size required to estimate a population proportion or percentage:

$n= \hat{p}(1-\hat{p})((z^*)/(E))^2$

, where $\hat{p}$ = proportion estimated by prior study.

E= Margin of error.

z* = Critical z-value.

Given : Confidence level = 95%

Critical value for 95% confidence = z*=1.96

$\hat{p}=\ 42\%=0.42$

E= 7%= 0.07

Then, $n= 0.42(1-0.42)((1.96)/(0.07))^2$

$n= 0.42(0.58)(28)^2$

$n= 0.2436(784)=190.9824approx191$

Hence, the minimum sample size required=191

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that Rn(x) ? 0.]f(x) = 10/x , a= -2f(x) = \sum_{n=0}^{\infty } ______Find the associated radius of convergence R.R = ______

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Rewrite $f$ as

$f(x)=\frac{10}x=-\frac5{1-\frac{x+2}2}$

and recall that for $|x|<1$ , we have

$\displaystyle\frac1{1-x}=\sum_(n=0)^\infty x^n$

so that for $\left|\frac{x+2}2\right|<1$ , or $|x+2|<2$ ,

$f(x)=-5\displaystyle\sum_(n=0)^\infty\left(\frac{x+2}2\right)^n$

Then the radius of convergence is 2.

Final answer:

The Taylor series for the function f(x) = 10/x, centered at a = -2, is given by the formula ∑(10(-1)^n*n!(x + 2)^n)/n! from n=0 to ∞. The radius of convergence (R) for the series is ∞, which means the series converges for all real numbers x.

Explanation:

Given the function f(x) = 10/x, we're asked to find the Taylor series centered at a = -2. A Taylor series of a function is a series representation which can be found using the formula f(a) + f'(a)(x-a)/1! + f''(a)(x-a)^2/2! + .... For f(x) = 10/x, the Taylor series centered at a = -2 will be ∑(10(-1)^n*n!(x + 2)^n)/n! from n=0 to ∞. The radius of convergence R is determined by the limit as n approaches infinity of the absolute value of the ratio of the nth term and the (n+1)th term. This results in R = ∞, indicating the series converges for all real numbers x.

Learn more about Taylor series here:

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