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A person going to a party was asked to bring 4 different bags of chips. Going to the store, she finds 13 varieties. How many different selections can she make?
(this is a probability question)

Answers

Answer 1

Answer:

"715" are the different selections she can make.

Given:

Number of different begs,

Total number of varieties,

So,

Total number of different selection = ¹³C₄

= $(13!)/(4!* (13-4)!)$

= $(13!)/((4!* 9!))$

= $(13* 12* 11* 10)/(4* 3* 2)$

= $(17160)/(24)$

= $715$

Thus the above answer is correct.

Learn more:

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Answer 2

Answer:

Answer:

Step-by-step explanation:

13!/4(13-4)!

13!/4(9)!

Continue simplifying.

The formula for combinations n!/r!(n-r)! pay attention to class next time

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The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who were vegans and another sample of such women who were omnivores.Diet Sample Size Sample Mean Sample SD Vegan 85.00 5.20 1.08Omnivore 91.00 5.65 1.10 Calculate a 99% CI for the difference between the population mean total cholesterol level for vegans and population mean total cholesterol level for omnivores. (Use μvegan−μomnivore). Round to three decimal places.)Interpret the interval.a. We are 99% confident that the true average cholesterol level for vegans is less than that of omnivores by an amount within the confidence interval.b. We are 99% confident that the true average cholesterol level for vegans is greater than that of omnivores by an amount within the confidence interval.c. We are 99% confident that the true average cholesterol level for vegans is greater than that of omnivores by an amount outside the confidence interval.d. We cannot draw a conclusion from the given information.
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For every 2 books that Tom buys, he can buy 3 magazines. If he pays $60 fo 4 books and 4 magazines, how much does he have to pay for each book?

Answers

Answer:

Price of book is $9\$$

Step-by-step explanation:

Let the price of book be $x$ and price of magazine be $y$

We have

$2x=3y$

We also have

$4x+4y=60$

$2* 2x+4y=60\n\n2*3y+4y=60\n\n10y=60\n\ny=6\n\n2x=3*6\n\nx=9\$$

Price of book is $9\$$

Suppose you invest $50 a month in an annuity that earns 48% APR compounded monthly. How much money will you have in this account after 2 years?A: 2001.29
B: 751.29
C: 1954.13
D: 1536.19
Solution:
use formula P[((1+(r/n)^(nt))-1)/(r/n)]
Solution 50[((1+(0.48/12)^(2 x 12))-1)/(0.48/12)]
= C $1954.13

Answers

It is given that you have invested $50 a month in an annuity that earns 48% APR compounded monthly. We can conclude that after 2 years you will have $1954.13 in your account.

How to solve future value?

To solve this we are going to use the formula for the future value of an ordinary annuity:

$P[(((1+(r/n)^(nt)-1))/((r/n))]$

where

FV is the future value

P is the periodic payment

r is the interest rate in decimal form

n is the number of times the interest is compounded per year

t is the number of years

It is given that you have invested $50 a month in an annuity that earns 48% APR compounded monthly. we need to find how much money you have in this account after 2 years.

Since the interest is compounded monthly, it is compounded 12 times per year; therefore,

r = 48% = 0.48

n = 12

Let's put the values in our formula:

$P[(((1+(r/n)^(nt)-1))/((r/n))]\n\n50[(((1+(0.48/12)^(12* 3)-1))/((0.48/3))]\n\n$1954.13$

Thus, We can conclude that after 2 years you will have $1954.13 in your account.

Learn more about interest here;

brainly.com/question/1548909

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C is the right answer

Please help it’s due at 5

Answers

Answer:

nei prossimi giorni, che si è svolto il convegno

How many randomly selected employers must we contact in order to create an estimate in which we are 95% confident with a margin of error of 9%? b) Suppose we want to reduce the margin of error to 4%. What sample size will suffice? c) Why might it not be worth the effort to try to get an interval with a margin of error of 1%?

Answers

Answer:

a)n=543

b)n=1509

c)n=13573

Step-by-step explanation:

c=98%,

$E=0.05$

Margin Error $E=Zα/2√p(1-p)/n$

but $n=((Zα/2)/n)²×p(1-p)$

where the confidence level is 1-α=0.98

cross multiply

$Zα/2=2.33$

where p=0.5

input the values

$n=(2.33/0.55)²×0.5(1-0.5)=543$

n=0.33

b) E=0.33

$E=Zα/2√p(1-p)/n$

$n=((Zα/2)/n)²×p(1-p)$

$1-α=0.01$ confidence level

n=(2.33/0.33)²×0.5(1-0.5)=1504

$n=1504$

c) $E=Zα/2√p(1-p)/n$

$n=((Zα/2)/n)²×p(1-p)$

1-α=0.98

cross multiply

Zα/2=2.33

p=0.5

n=(2.33/0.01)²×0.5(1-0.5)=13573

$n=13573$

16 1/9+ -4 2/3 help please??

Answers

Answer:

11 4/9

Step-by-step explanation:

ANDDD the answer is

1. After you retire in 17 years your goal is to have $100,000 in your investment account that earns 8% compounded annually. How much money would you need to deposit now to reach this goal

Answers

9514 1404 393

Answer:

$27,026.90

Step-by-step explanation:

The future value formula can be solved to find the present value required.

FV = P(1 +r)^t . . . future value of P compounded at annual rate r for t years

$100,000 = P(1 +0.08)^17

P = $100,000/3.70002 . . . . divide by the coefficient of P

P = $27,026.90

You would need to deposit #27,026.90 now to reach this goal.

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At the new light bulb plant, 9 out of 25 light bulbs produced are defective. If the daily production is 4400 light bulbs, how many are defective?

A person going to a party was asked to bring 4 different bags of chips. Going to the store, she finds 13 varieties. How many different selections can she make? (this is a probability question)

Answers

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How to solve future value?

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A person going to a party was asked to bring 4 different bags of chips. Going to the store, she finds 13 varieties. How many different selections can she make?
(this is a probability question)